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Codeforces 332B B. Maximum absurdity (RMQ)

Topic Links:Codeforces 332BMain topic:Give a sequence to find the two length k segments that do not cover each other, ask for the weight and maximum of the two segments, sort by the left end of the left segment, and the left end of the right segment as the second keyword to get the first answer.Topic Analysis: Very water data structure of the topic, we only need to first use the prefix and preprocessing all the length of the total weight of the section K. The RMQ is then used to maintai

Codeforces Round #257 Div.2 D or 450D Jzzhu and Cities "shortest circuit"

the priority queue of data too much caused by the memory exceeded the limit, so hurriedly added a limit. Sure enough, it's over.      Here is a Boolean array trainofpath[v] recorded to the V point of this side is not a railroad. If the road was originally a railroad, it is now the road that is updated, only to be updated; If you want to get a MLE code, if you are working on a highway that is currently being updated, some per

poj--3268 Silver Cow Party (Shortest way)

Topic Radio Wave: poj--3268 Silver Cow PartyRun two times, Dijkstra. Mentally retarded problem#include #include#include#include#includeusing namespacestd;#defineMAXN 10001#defineINF 0x3f3f3f#definePII pairstructac{intTo,va; AC () {} ac (intAintb) { to=a,va=b; }};vectorQ[MAXN],W[MAXN];intDIS[MAXN],DIST[MAXN];BOOLFA[MAXN];voidDijkstraints) {memset (FA,0,sizeof(FA)); memset (Dis,inf,sizeof(DIS)); Priority_queuePQ; Dis[s]=0; Pq.push (PII (dis[s],s)); w

14th Week 5.30---6.5

New Week/w \Everyone is reading in the library. I sleep in the library ...5.31Do CF encounter a problem of BFS, think of this question has not yet mendedHiho 1233 BoxesLast year a God taught me ... But it's not going to happen again.Or is the representation of the State not to be clear, is the weight of each block multiplied by the position of the number representing a state1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 8typedef pairint,int>

ACM Learning process-hdu4415 Assassin ' s Creed (greedy)

people who are not 0, but it is a priority to manually kill the less durable ones.Conclusion: After killing the first person with a minimum endurance of 0, I manually kill from small to large with durability.It is also important to note that, after killing people in turn, if the rest of the people can be killed automatically, I do not need to manually kill the person.In the end, there are two cases where the most value is taken.Code:#include #include#include#include#include#includeSet>#include#

CODEFORCES730D award Ceremony (IDEA)

Test instructionsGive you n personal scores and change the values, ask you to arrange a change in order to make n individual rank change and maximumIdeas:N^2 enumerates the effects on the results of the change in the rank of each of the two people./************************************************author:d evil*********************************************** * */#include#include#include#include#include#include#includeSet>#include#include#include#includestring>#include#include#include#defineLL Long

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined)

Portal: http://codeforces.com/contest/765A: Give your home name, and n the beginning and end of the ticket, Jinotega start at home, you have to judge according to the beginning and end of these tickets Jinotega is not at home. Direct record the number of times the beginning and end of the home appear, if the equal description Jinotega at home, otherwise not at home.#include #include#include#include#include#include#include#includestring>#include#include#includeSet>#include#defineX First#defineY S

Des\3des\base64 in Java and C + +

decrypt the password data, It reproduces the core data in the form of plaintext. This ensures the security and reliability of core data (such as pins, MACS, etc.) that are transmitted in the public communication network.By periodically switching to a new key at the source and destination of the communication network, it is possible to further improve the confidentiality of the data, which is now a popular practice in the financial Transactions network.3DES3DES is a mode of the DES encryption al

Understanding cloud computing Vulnerabilities

extends to these service models. In the future, we hope virtualization can evolve from virtualized servers to computing resources that can be directly used for SaaS services.Encryption: Many cloud computing security requirements can be solved only by using encryption technology.With the development of cloud computing, the list of core technologies is likely to expand.Basic FeaturesIn the description of its basic cloud features [2], the National Institute of Standards and Technology (

JavaScript Development Tools Daquan

debugging running on Android apps. Chrome Dev Tools provides a range of tools that you can use to debug JavaScript code, edit CSS, and test application performance. Ng-inspector is a firefox,chrome and Safari browser plugin that helps developers develop, understand, and debug angularjs applications. It provides real-time updates, Dom highlighting and other features. Augury is a chrome plugin that you can use to debug your angular 2 app. It allows developers to view the application s

LaTeX's treatment of references has some advantages: __latex

1. Can maintain a bib file, in your entire research career can only maintain such a file, like a number According to the library, each reference is a record, described by a unique ID (such as the MartinDSP00 below). For example, one of the typical documents in my Myreference.bib file is this: @article {MartinDSP00, Author = "A. Martin and M. Przybocki", title = "The {NIST} 1999 Speaker Recognition Evaluation---an overview", Journal = "Digital Sign

Codeforces 500D New year Santa Network (tree + count)

sample. There is 6 triples: (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1). Because N = 3, the cost of needed to build the network are always D(1, 2) + D(2, 3) + D (3, 1) for all the triples. So, the expected cost equals to D(1, 2) + D(2, 3) + D(3, 1). It's a pity that I didn't make it in this game (or yellow). Test instructions is given a tree with weights.Ask you to choose any of the 3 points in the tree C1, C2, C3 D (C1,C2) + D (C2,C3) + D (C1, C3) expectations.Because

Computer motherboard knowledge

, integrated Nic, etc.) are all controlled by the nanqiao chip. The nanqiao chip is usually exposed next to the PCI slot, and the block size is relatively large. A channel is required for data transmission between the North and South bridges at any time. This channel is the north and south bridge bus. The wider the north-south bridge bus, the more convenient data transmission. In the Motherboard chipset of each manufacturer, the North-South Bridge bus is named respectively ., For example, Intel'

Week six 2.21-2.27

It's only been a week, Qaq.2.21CF 629 E famil Door and RoadsIn fact, when Tarjan to engage in, O (n+m) of Acridine.1#include 2#include 3#include 4 using namespacestd;5typedefLong LongLL;6typedef pairint,int>PII;7 Const intMAXN = 1e5 +Ten;8VectorQ[MAXN];9 DoubleANS[MAXN];Ten One //Tree A intcnt, H[MAXN]; - structEdge - { the intto, pre; -} e[maxn1]; - - voidAddint from,intto ) + { -cnt++; +E[cnt].pre = h[ from]; AE[cnt].to =to ; ath[ from] =CNT;

HDU 5125 Magic Balls (segment tree +DP)

subsequence is.Sample Input2 5 35 14 23 12 43 1 5 45 14 23 12 43 1Sample output44 Test instructions is given two sequences a, B. Then asked to use the most m operation (Swap (AI,BI)), so that the longest ascending sequence of the length of a sequence of the longest is not difficult to think of a DP is, dp[i][j][k] means that the last element of the oldest sequence is I, with a J operation, K indicates that element I has not exchanged (0 means no, 1 means there is )。 Then the transfer is dp[i][

POJ 2010 (Priority queue

Sweep with priority queue to get the minimum value of the sum of the values greater than and less than the median, and sweep again to get the optimal solution#include #include#include#include#include#include#defineINF 0X3FFFFFFFusing namespaceStd;typedefLong Longll;intN,c,f;typedef pairint,int>PII;Const intmaxv=1e5+ -;p Airint,int> COW[MAXV];////score,aidll LOW[MAXV],UPP[MAXV];BOOLCMP (PII a,

UVA 1152 4 values whose Sum is Zero and 4 value of 0

;intdata[4][MAXN];intvec[maxn*MAXN];int_lower_bound (int*a,intLintRintv) { intm; while(lR) {m= (l+r) >>1; if(A[M]GT;=V) R =m; ElseL = m+1; } returnL;}int_upper_bound (int*a,intLintRintv) { intm; while(lR) {m= (l+r) >>1; if(A[M]GT;V) R =m; ElseL = m+1; } returnL;}intMain () {intT scanf"%d",T); int*a = data[0], *b = data[1], *c = data[2],*d = data[3]; while(t--){ intN scanf"%d",N); for(inti =0; I ) {scanf ("%d%d%d%d", a+i,b+i,c+i,d+i); } intSZ =0; for(inti =0; I )

Ecnuoj 2856 to the sky

represents the composition of the starry sky.OutputLine: Indicates the number of stars in the current constellation.Sample Input10 5.. *.....**.**.. *****.*...*...... ****.***.. ****.***15 8**.**......*.. *.. *.**.*...*...*.*.**.*****.**...***.****.**....**.. *.*.....*****.. *****.. *....**...*.. *..*.*...*.*.*.***Sample Output27SourceProblem solving: Searching1#include 2 #definePII pair3 using namespacestd;4 intw,h;5 Chartable[1010][ -];6 Const intdir[8][2] = {7-1,0,1,0,0,-1,0,1,8-1,-1,1,1,-1,

[Graph theory Training] Bzoj 3245: Fastest route "shortest circuit"

. No. 0, at a speed of.Outputonly one row, sequentially outputting the city from 0 to D. Ensure that the quickest route is a single line.Sample Input6 15 10 1 25 680 2 30 500 5 0 1011 2 70 771 3 35 422 0 0 222 1 40 862 3 0 232 4 45 403 1 64 143 5 0 234 1 95 85 1 0 845 2 90 645 3 36 40Sample Output0 5 2) 3 1HINT"Data Range"30% n100% 2SourceSpfaIdea: Actually very obviously, here not only to record to this point of time, but also to this point of the speed, so record a two-dimensional dist[x][y] t

UVA 215 Spreadsheet Calculator

Simulation questions. Each cell has an expression on DFS, and if there is a ring then it cannot be parsed, and may be repeatedly accessed to unresolved cells, dropped sets, or the array is sentenced to repeat.This problem first frame to, variable name do not take too messy, more details, know more library functions easier to write. Note the details and note the format./**********************************************************--------------Tyrannosaurus---------* * Author Abyssalfish ***********

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