nlp exercises

[Lab4-1] Grasping routing exercises question 1:Fetching 172.18.0.0/16----172.29.0.0/16 routes with ACLsAnswer: 172.16.0.0 0.15.255.255, it looks perfect, but the box is actually a little wider.R1 (f0/0)-(f0/0) R2Interface address on R1:r1#sh IP int bInterface ip-address OK? Method Status Protocolfastethernet0/0 12.1.1.1 YES NVRAM upLoopback0 172.16.0.1 YES NVRAM upLoopback1 172.17.0.1 YES NVRAM upLoopback2 172.18.0.1 YES NVRAM upLoopback3 172.19.0.1 Y

ACM Exercises (v)1.//ASCLL code Value Ordering/* #include using namespace Std;void Chushi (char a[3]){for (int i=0;i{cin>>a[i];}}void Paixu (char a[3]){for (int i1=0;i1for (int i2=i1;i2{if (A[i1]>a[i2]){Char TEMP=A[I1];A[I1]=A[I2];A[i2]=temp;}}cout}int main (){int N;cin>>n;Char a[3];for (int m=0;m{Chushi (a);Paixu (a);}return 0;}*/2.//Odd-even separation/* #include using namespace Std;void Jishu (int n){int i=0;for (i;i{if (i%2==1){cout}}cout}void Ors

summed up the beauty of programming above on the list of problems, there is not the right place, welcome to shoot bricks, and other programming beauty to read, back to brush other problems encountered linked list and then add ~The catalogue is as follows (click to expand the above directory to the topic of interest):/************************************************************************//* Linked List Classic exercises 1. Removing nodes from the Hea

TopicCode/* ---------------------------------------* Date: 2015-07-05* sjf0115* Title: Object Manager * Source: Huawei Machine Test Exercises----------------------- ------------------*/#include #include "ObjMgt.h"#include using namespace STD;structobject{unsigned intKey1;unsigned intKey2;unsigned intKey3; Object (unsigned intAunsigned intBunsigned intc) {key1 = A; Key2 = b; Key3 = C; } Object () {}}; vectorContainer/ *-----------------------

TopicDescribe:找出1至n之间同构数的个数。同构数是这样一组数：它出现在平方数的右边。例如：5是25右边的数，25是625右边的数，5和25都是同构数。Detailed Description:Interface descriptionPrototype:intSearchSameConstructNum(int n);Input parameters:int n：查找1至n之间的全部同构数return value:int：1至n之间同构数的个数Practice Stage:Code/* ---------------------------------------* Date: 2015-07-05* sjf0115* title: Find the number of isomorphic numbers * Source: Huawei Machine Test Exercises-------------------- ---------------------*/#inclu

TopicDescription: Topic title:求某二进制数中1的个数。给定一个unsigned int型的正整数，求其二进制表示中“1”的个数，要求算法的执行效率尽可能地高。Detailed Description:Prototype:int GetCount(unsigned int num)Input parameters: num 给定的正整数Output parameters (the memory area pointed to by the pointer is guaranteed to be valid):无return value:返回1的个数举例：输入13，则对应的二进制是1101，那么1的个数为3个。则：返回3。Practice Stage:初级 Code/* ---------------------------------------* Date: 2015-07-03* sjf0115* title: Number of 1 in a binary number * Source: Huawei Machine Test

usingSystem;usingSystem.Collections;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;usingSystem.Text.RegularExpressions;namespaceC Programming Exercises { Public enumqqstate {OnLine=1,//The enumeration type has a default initial value of 0 and assigns a value of 1 to match the console output. OffLine, Leave, Busy, QMe,}classProgram {Static voidMain (string[] args) { //prompts the user to select an online status, we

Topic描述: 详细描述：N个人围坐在一个圆桌上，顺时针报数，报数的初始值为第一个人设置。当有成员报出的数字为7的倍数或数字中包含7，则该人退出圆桌，而后由下一个人开始重新继续该游戏。实现以下接口： 1、设定输入原始的圆桌游戏的人数。以最先开始报数的人编号为1，顺时针排序。 2、设定第一个人的初始值，获取按照规则退出圆桌的人的编号。 3、结束游戏。样例:比如初始化为4人的游戏：第1轮初始值为1，退出为3；第2轮初始值为4，退出为4号；第三轮初始值为16，退出为2号；第四轮初始值为6，退出为1号；练习阶段: 中级 Code/* ---------------------------------------* Date: 2015-06-31* sjf0115* title: Roundtable game * Source: Huawei Machine Test Exercises----------------------- ------------------*/#inclu

// 1. the exercises in this chapter are purely for the sake of existence... Typedef struct phone {char * quhao; char * jiaohuantai; char * zhanhaoma;}; typedef struct call {char * date; char * time; phone * shiyong; phone * self; phone * hujiao ;}; 2. typedef struct cash {float retail_price; float sale; float sales_tax; float licensing_fee ;}; typedef struct daikuan {float hour; float sales_tax; float licensing_ment; float interval; float loan_duratio

Exercise 1.45 is a summary of many previous exercises on fixed points. This topic reviews the fixed point search method we used in Section 1.3.3. When looking for the fixed point of Y-> x/y, this transformation itself does not converge, an average damping is required. For the transformation y-> X/(y ^ 2), it can also be reduced by an average damping. However, one average damping is not enough for the four equations. That is to say, for a transforma

This is a self-made exercise and may be incorrect. You are welcome to discuss and discuss various optimization and reconstruction solutions.Based on the reader's feedback or code review, I will update and supplement the answer or related content of this article, which will be added to the comments of this blog.I try to ensure that the answer code for each question is complete, not just functions or classes. Open the Python 2.7 IDLE and copy the complete code to debug and run it.Welcome to Balian

about the drivers and responsibilities. First of all, everyone should be sure that everyone is responsible for the rise and fall of the team. The good and bad of a person involve the entire team. When everyone reaches a consensus, for example, let everyone build their own workflows and plans first, it must be simple and practical. It should be set based on the performance gap. Of course, the reward system should be required, and the rewards should be rewarded to raise the responsibility. 5.E

are required. 3. Division by players' character characteristics: A. the type of competitive challenges. I like the excitement, but I don't want to control it. I don't want to spend any money on games; B. Team Spirit type. I like to explore the world with my peers, reduce stress and enhance friendship. My payment tends to be outstanding; C. Easy and easy to use. I am used to traveling with others. Generally, I am not willing to pay money; Based on this, you can determine the type and bi

SQL server statement exercises, SQL server statements Related tables: Query section: -- Query the last three letters of an employee's name: select substring (ename, LEN (ename)-3) FROM dbo. EMP -- query the number of weeks for employees in department 10 to enter the company. SELECT ename, DATEDIFF (wk, hiredate, GETDATE () AS the number of weeks to enter FROM dbo. emp where deptno = 10--1 query all employees in department 30 SELECT * FROM dbo. emp wh

To complete these exercises, you will need the index.html file for this chapter, as well as the finished JavaScript code as found in complete. js. these files can be downloaded from the Packt Publishing web site at http://www.packtpub.com/support. Http://ww.packtpub.comChallenge exercies may require use of the official jQuery documentation at http://api.jquery.com /. 1. Add a class of specialto all of the 2. Add a class of yearto all of the table cell

C Language exercises in Linux: obtain five strings from the keyboard and sort the strings using pointer arrays. C Language exercises in Linux: obtain five strings from the keyboard and Use Pointer arrays to sort strings # Include # Include Int main () {int I, j; char * str [5]; char * tmp = (char *) malloc (sizeof (char) * 20 ); char * tmp1 = tmp; for (I = 0; I

Ah, it took a week to learn Io language because I was busy writing a draft of the oauth2.0 Server framework last week. The answer to this exercise is followed by seven weeks and seven languages: understanding a variety of programming patterns; answers to the exercises after Ruby class I/O is a prototype language, similar to Javascript, and does not distinguish between classes and objects. All things are objects, the data structure of an object is main

PHP Learning Path II (array exercises) For an array of exercises, PHP is different from Java and C + + He is a weak type of language, and PHP arrays are very powerful. It has both the properties of the array in Java and the purpose of the collection. ";//Traversal array, method two: Print variable print_r ($a); echo"";? > ' Http://www.sina.com ', ' baidu ' = ' http://www.baidu.com ', ' google ' = ' ht

={ @ "Wang": array1, @ "Zhang": array2 }; // optimized nslog (@ "xxxxxxxxxxxxxxxx % @ xxxxxxxxxxxx", dicl2); nsarray * array5 = dicl2 [@ "Zhang"]; // obtain value nslog (@ "array5 = % @", dicl2) through key;}-(void) didreceivememorywarning {[Super didreceivemorywarning]; // dispose of any resources that can be recreated .} @ end set exercises # Import "viewcontroller. H "@ interface viewcontroller () @ end @ implementation viewcontroller-(void) viewd

Exercises: 1, using while loop input 1 2 3 ... 8 9 2, all the number of 1-100 and 3, output 1-100 of all the odd 4, output 1-100 all even 5, 1-2+3-4 ... 99 of all the numbers and the analog landing 1. User input account password to log in 2. User information is stored in the file 3. User password entered error three times after locking user "three-level menu: 1. Run Program output first level menu 2. Select a menu of one