Ibox4412 lubuntu14.04, ibox4412
Lubuntu14.04 transplanted a year ago. Based on ibox4412, lubuntu14.04 is smoother and more powerful than the friendly port 13.10.
Porting odroid lubuntu14.04 http://odroid.in/ubuntu_14.04lts/ubuntu-14.04.1lts-lubuntu-odroid-u-20141124.img.xz Based on ibox4412
Based on odroid kernel-3.8.13.29, all drivers are ported and adapted
Fun
to 3 persons
User ID
User Name
U1
Xiaoming
U2
Datong
U3
Wuming
(6) Relationship between users and roles:
User ID
Role ID
Inheritance number
U1
R1
0
U2
R2
0
U2
R1
1
U3
R4
0
U3
R3
1
the route Method description and whether to turn on data permissions---> Create roles---> Bind a created route to a created role---> Add a user---> role to create your own signature---> each request carries a signature--- > Bring this signature and resource binding when creating a resource
See what permissions your individual has
// userid 查询 RoleDoc 然后把所有返回的 PathMethods 做聚合 // 通过 PathMethods 也可以结合 RouterDoc 查询具体的数据验证权限
View permissions granted by others
// userid 查询 SignDoc 然后对返回,做
Cardinal Spline
This is relatively simple, with one end point, one start point, and two control points.
Points between the end point and the start point are implemented by interpolation. interpolation functions:
P(U) =PK-1 (-S * u + 2 S * u) +PK [(2-s) u * u + (S-3) u * u + 1] +PK + 1 [(S-2) * u + (3-2 s) * u + S * u] +PK + 2 (S * u-s * u * U)
Code implementation:
void getInterpolation(point p1,point p2,point p3,point p4,float s,float u,point *result){ float u2=u*u; float
resulting from the generation of x into the equations; x0 is the initial value of the unknown vector. If you want to solve the following equation group:
F1 (U1,U2,U3) = 0
F2 (u1,u2,u3) = 0
f3 (u1,u2,u3) = 0Then func can be defined as follows:
def func (x):
u1,u2,u3 = x return
[F1 (U1,U2,
Article Title: tiptop automatic backup script backup. sh. Linux is a technology channel of the IT lab in China. Includes basic categories such as desktop applications, Linux system management, kernel research, embedded systems, and open source.
# Create a crontab Scheduler
Crontab-e
0 *** sh/u3/backup/tool/backup. sh # automatic backup at every day
0 6 *** sh/bin/ftpauto # automatically upload at every morning
# Backup. sh
LANG = en_US
Ans = 'date | a
"[Root @ localhost ~] # Tail-1/etc/passwdU1: x: 4323: 4323: UUU:/home/u1:/bin/csh[Root @ localhost ~] # Groups u1U1: u1 g1 g2
2. Create the following user, group, and group member relationships
Group named adminsUser u2, using admins as the affiliated groupUser u3 also uses admins as the affiliated groupUser u4 cannot log on to the system interactively. The default home directory is/test/u4, And the passwords of u2,
cautionLet's look at an obvious DFS:
Initialization
Starting from a point u, add this point to a set and set it to U. Go through all the points that are connected to him, put them in another set S1, and then go through the first DFS
First time DFS:
Select a point U1 from the S1, and this point must be connected to any point in the set U. Add the U1 in the collection S1 to the collection S2, and add the U1 to the collection U for the second time DFS
Two times
You can choose from the following methods:First, using Eclipse, right-click the project to export the jar.Second, using Eclipse, right-click the project to export the runnable jar.Third, use the Eclipse plugin fat jar to export the executable jar package.There is now a development scenario:First project: A1Second item: B2Item Three: U3Several conditions and relationships:1 U3 references third-party libraries Log4j.jar and common-Io.jar. 2B2 reference
If the measured amplification circuit of several transistors three pin to ground point U1.U2.U3 are the following values, try to determine whether they are silicon tube or germanium tube, is NPN or PnP tube. and determine three electrodes of 1. u1=2.5v. u2=6v. u3=1.8v 2. u1=-6v. U2=-3v. u3=-2.8v I would like to draw up a detailed answer procedure.
A: (authoritat
component), after 8 bit quantization, the uncompressed pixel occupies 3 bytes.
The following four pixels are: [Y0 U0 V0] [Y1 U1 V1] [Y2 U2 V2] [Y3 U3 V3]
The stream stored is: Y0 U0 V0 Y1 U1 V1 Y2 U2 V2 Y3 U3
(2) YUV 4:2:2
The sampling rate of each color-difference channel is half that of the luminance channel, so the chroma sampling rate in the horizontal direction is only half of the 4:4:4. For uncom
initial value of the estimate is introduced, and then the fitting is done;2. Minimum value of the functionThe Optimize module also provides many algorithms for finding function minimums: Fmin, Fmin_powell, FMIN_CG, FMIN_BFGS, etc., which fit the minimum value by passing in the target function and the initial value, fmin* () This type of function also provides a fprime parameter that computes the function of the target function on the partial derivative of each argument.3. Solving the nonlinear
The lubuntu14.04, based on ibox4412, was more fluid and more powerful than the 13.10-year-old transplant.Odroid lubuntu14.04 HTTP://ODROID.IN/UBUNTU_14.04LTS/UBUNTU-14.04.1LTS-LUBUNTU-ODROID-U-20141124.IMG.XZ based on ibox4412 transplantDrive all porting and adaptation based on Odroid kernel-3.8.13.29Features that can be implemented:1, SD card Two partitions, the first partition FAT32, storage environment v
Analysis of mysql paging data loss1. Problematic code
CleverCode finds that data is lost by page in mysql. As shown in the following code, the system_user table contains 4 million rows of data. In this case, all the userids in this table need to be obtained. In this case, only 20 thousand entries can be retrieved by page at a time.
// System user table (4 million rows of data) $ systemUserTable = new systemUserTable (); // 20000 $ pageSize = 20000; for ($ curPage = 1 ;; $ curPage ++) {$ SQL = "s
']; echo $ userid. "\ r \ n ";}}
2. problem analysis
1) suppose system_user only has 10 rows of data (u1, u2, u3, u4, u5, u6, u7, u8, u9, u10 ).2) at this time, five rows are taken each time. Two times.3) normally, the first page is taken (u1, u2, u3, u4, u5). Normally, the second page is taken (u6, u7, u8, u9, u10 ).4) If you finish the first page, the second page will be taken from the previous time gap.
i m -1), the node vector or sequence of nodes is called uniform; otherwise it is non-uniform. A node can be considered a separation point, subdividing the interval [u0, um] into a node interval. All B-spline basis functions are assumed to define the domain on [u0,um]. In this article, we often use u0 = 0 and um = 1, so the definition field is closed interval [0,1].In order to define B-spline basis functions, we also need a parameter, the number of times of the base function (degree)p, the
;/** * * * @author 林计钦 * @version 1.0 201 3-7-25 am 10:33:37 */public class Locktest {public static void main (string[] args) {locktest test = new Locktes T (); Create a concurrent access account MyCount MyCount = test.new MyCount ("95599200901215522", 10000); Create a Lock object lock lock = new Reentrantlock (); Create a thread pool executorservice pool = Executors.newcachedthreadpool (); Create some concurrent access users, a credit card, save, take the take
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