offline speech recognition

Apple's iphone has Google's technology for voice recognition, and Android, Google's push, will naturally implant its core technology into Android and build it up with Google's cloud technology. So Google Voice recognition's implementation on Android became extremely easy. Speech recognition, with the help of cloud technology to identify the user's voice input,

(), Encoding.UTF8)) {Strjson=Strhttptext.readtoend (); } jobject jsons= Jobject.parse (Strjson);//parsing JSON if(jsons["err_msg"]. valuestring> () = ="success.") {StrText= jsons["result"][0]. ToString (); returnStrText; } Else{Error= jsons["Err_no"]. valuestring> () + jsons["err_msg"]. valuestring>(); returnerror; } } stringAccess = Getstraccess ("VJDS2SNHUUDLZ57KTYTQDAVJ","896348e496b47382d49e0cd2e7d5f1e8"); Console.Write (access);

Speech recognitionEr.xmlYuyin.cpp#include const keywordConst int *p; int const *P;Const * address can not be modifiedint *const p;*const data pointed to cannot be modified#include String application#define _CRT_SECURE_NO_WARNINGS//close security check #includememory allocation and processing of massive amounts of data#include #define _CRT_SECURE_NO_WARNINGS//close security check #include Copyright notice: This blog all articles are original, welcome

) { } Else if(Textutils.isempty (Mdownloadresult)) {}Else{Mresulttext.settext (""); Userwords Userwords=Newuserwords (mdownloadresult.tostring ()); if(Userwords = =NULL|| Userwords.getkeys () = =NULL) { return; } for(String Key:userwords.getKeys ()) {Mresulttext.append (key+ ":"); for(String word:userwords.getWords (key)) {Mresulttext.append (Word+ ","); } mresulttext.append ("\ n"); } }} @Override Public voidOnEvent (intEventType, Bundle params)

(); writestream.dispose (); } }catch {returnnull; } stringresult=string. empty;stringresult_final= string. empty;using (HttpWebResponse response= (HttpWebResponse) request. GetResponse ()) { using (stream Responsestream=response. GetResponseStream ()) {using (streamreaderreadstream=new StreamReader (Responsestream,encoding.utf8)) { string Line=string. empty; stringbuildersb=newstringbuilder (); while (!readstream.endofstream) { line=readstream.readline (); NBSP;NBSP;NBSP;NBSP;NBSP;NBSP;SB

Width: #define _CRT_SECURE_NO_WARNINGS #include #include #include int main() { Char STR [10] = "xuanyuan "; printf("%d,%d\n", sizeof(str), strlen(str));//10,4 Printf ("% d \ n", sizeof (""); // 5 Printf ("% C \ n", STR [0], STR [1]); // Xuan Printf ("% C \ n", STR [0], STR [1]); // garbled Printf ("% d, % d \ n", sizeof ("hello"), sizeof (L "hello"); // 6 12 Char * P = "Hello tianchao "; Wchar_t * PW = l "Hello tianchao "; Printf ("% s \ n", P); // He

; PrivateAudioClip _cliprecord =NewAudioClip (); PrivateASR _asr; voidStart () {_asr=NewASR (APIKey, Secretkey); Startcoroutine (_ASR. Getaccesstoken ()); StartButton.gameObject.SetActive (true); StopButton.gameObject.SetActive (false); Descriptiontext.text=""; StartButton.onClick.AddListener (Onclickstartbutton); StopButton.onClick.AddListener (Onclickstopbutton); } Private voidOnclickstartbutton () {StartButton.gameObject.SetActive (false); StopButton.gameObject.SetActive (

Speech recognition:Precautions to use: Mainfest.xml must remember permission to write in21001: My case is not written Speechapp class, and need to register in application;20005: No matching results23300: Local engine error, my problem is the syntax error, missing a semicolon,,,, and debugging for a long time to find, and there will be no hint.The cause of the engine error in general:1, Java code Check your grammar file path, syntax ID and other relate