open jar file

The path of the configuration file cannot be obtained after the jar package is created for the project. Today, I am working on a Java project in development. I want to read the information in the configuration file. when the project is packaged with a jar package, the configuration

After the recent upgrade of the entire schema to spark 2.0.0, the problem was that every time a hive--service Metastore started, a small bug was always reported. Unable to access/home/ndscbigdata/soft/spark-2.0.0/lib/spark-assembly-*.jar: There is no file or directory. And what is going on in this line, there is no information on the Internet. Have no way, had to step-by-step analysis, finally found

The Hibernate entity classes and their mapping files are also placed in the project, and because there are multiple projects using the same database, Hibernate entity classes and mapping files are duplicated, which is inconvenient for maintenance and upgrades. Therefore, it is extracted, made into a jar package, and then introduced back to the project. In practice, there is a strange problem: The project runs fine, but the JUnit unit test does not ru

The usual way to run a jar file on a Linux server is to: $ Java-jar Test.jar The feature is that when the SSH window is closed, the program aborts. or the runtime can't cut out to perform other tasks, is there a way to get the jar running in the background: Method One: $ nohup Java-

In actual projects, the original large projects need to be split into small functions based on business functions, and deployed independently in the form of services. On this premise, the same code is also used to apply various projects, for convenience. It is introduced as a jar package and used as another project. In an independent JAR package, we set an independent data source

If you need to download the jars instead of using a build system, create a Maven pom file like this with the desired versi OnThen execute:Mvn-f Download-zuul-pom.xml dependency:copy-dependenciesIt would download Zuul-core-*.jar and its dependencies into./target/dependency/.Maven pom.xml jar File download

Li Wu:Learn to think more, honouring teachers save Thanksgiving. Leaf See Root 321, rivers with one.Meekness Conscience Lord, willing to do without regrets to the most bitter. Reading exercise strong body and mind, Prudential advised and the line and cherish. Os:windows7 x64 Ide:myeclipse 2017 The first stepWhen the jar package has been imported, view the. class file and you will find ... Source cod

Package Java project into a jar package, if there is a resource file in the jar package needs to access, need to take the form of stream access, you can call the getResourceAsStream () method, and cannot be accessed by path (the file has been hit into the jar, Not conforming

Because of the need for development, you need to dynamically load classes based on the configuration, so simply test the Java dynamic load class Defining interfaces Package Loader;public interface Helloiface {public String hello (); Public String Sayhi ();} Implementing interfacesImplement this interface in other plug-in classes and export it as a jar, such as D:/tmp/test.jar Package Loader;public class Helloimpl implements helloiface{@Overridepublic

Introduction to Jnotiy, a jar package that supports dynamic monitoring (cascading monitoring) folders and files. In Linux, the Jnotify service is called on the Linux underlying. In Windows, you need to add the DLL file for the attachment.Because this jar file is not in the generic Maven repository, the Pom.xml

It's been a toss of the afternoon ~ ~, "no job jar file Set" is the meaning of the job jar is not found, and then it is not possible to find a custom mymapper class, the general reason is not set the Jar package class, that is, when configuring the job, there is no following this line of code:Job.setjarbyclass (mutidou

1. When packaging, place the resource in the asset folder and get the specified resource through Assetsmanager:The assets folder in the target app and Jar is merged, so you can get the target resource by getting the folder for that app2. Using the Library projectSuch a method cannot confuse the code, which means that the library source project needs to be provided at the time of publication. In the target project referencing this lib, you will see a

Unable to read TLD ' Meta-inf/c.tld ' from JAR filecreationtime--2018 July 18 17:46 author:marydon1. Scenario DescriptionTomcat can start the project normally, but it can't run, the error message is as follows:Unable to read TLD ' meta-inf/c.tld ' from JAR file ' file:/d:/tomcat6.0.41/apache-tomcat-6.0.41/webapps/proje

JSP file download (jar package is not used) Java code: Public class Download extends HttpServlet {public Download () {super ();} public void destroy () {super. destroy (); // Just puts destroy string in log // Put your code here} public void doGet (HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {this. doPost (request, response);} public void doPost (HttpServl

Previously, the configuration file was loaded in this way: [java] private static void init () {URL url = PropertyUtil. class. getClassLoader (). getResource ("ApplicationResources. properties "); String file = url. getFile (); try {file = java.net. URLDecoder. decode (file, "UTF-8");} catch (Exception e) {e. printStack

","Attachment;filename="+NewString (Filename.getbytes ("gb2312"),"Iso8859-1")); Response.AddHeader ("Content-length",""+ file.length ()); OutputStream toclient =NewBufferedoutputstream (Response.getoutputstream ()); Response.setcontenttype ("Application/octet-stream"); Toclient.write (buffer); Toclient.flush (); Toclient.close (); }Catch(IOException ex) {Ex.printstacktrace (); } } Public void Init()throwsservletexception {//Put your code here}}This download

First, the jar file is an executable file that is exposed under eclipse, but this is not the file you can double-click to execute under Windows.So to say, how to put the exported jar file, run it up.1, under the Windows system:Fir

; Parent> dependencies> -- dependency> groupId>org.springframework.bootgroupId> artifactid>spring-boot-starter-webartifactid> Dependency> dependency> groupId>org.springframework.bootgroupId> artifactid>spring-boot-starter-data-jpaartifactid> Dependency> -- dependency> groupId>mysqlgroupId> artifactid>mysql-connector-javaartifactid> Dependency> -- dependency> groupId>commons-langgroupId> art

: = $ (common_android_package_suffix)Include $ (build_prebuilt) (9) Add a static Java LibraryLocal_path: = $ (call my-DIR)Include $ (clear_vars)# Build all java files in the Java subdirectoryLocal_src_files: = $ (call all-subdir-Java-files)# Any libraries that this library depends onLocal_java_libraries: = Android. Test. Runner# The Name Of The JAR file to createLocal_module: = sample# Build a static

Import resource file in spring, there are two cases: Classes directory and JAR packageIf the resource file is in the classes directory:Note:1, the directory of files such as: Classes/bean/test.xmlIf the resource file is in the jar package:1, pay attention to add * number aft