openoffice 4 0 1

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Transfer Protocol for IC Card (1)-Character Transfer Protocol t=0 "Go"

TAL in response APDU and wait for the next C-APDU.When exchanging commands and data between TTL and IC Card, TTL and IC card must know clearly the driver of data flow and I/O, that is, whether the terminal sends data to the IC card or the IC card sends the data to the terminal.(4) Transmission of C-APDUWhen the T=0 protocol is used, only the command data sent to the IC card or the C-APDU containing the IC

[Swust OJ 465]--wu granny buys fish (0-1 backpack +dfs)

fish of Wu's grandmother. The following N lines, each with two positive integers S (1≤s≤n), T, indicate the number of a fish and the price of the fishes.Next, there are two integer p,q per line.When P,Q is greater than 0 o'clock, p,q cannot coexist; when p,q equals 0 o'clock, the end of the input file is indicated. The first behavior of the output file is two po

Case study of PHP greedy algorithm for solving the 0-1 knapsack problem

Case study of PHP greedy algorithm for solving the 0-1 knapsack problem This article mainly introduces the PHP greedy algorithm to solve the 0-1 knapsack problem. The example analyzes the principles of the greedy algorithm and the implementation skills of the knapsack problem. For more information, see This article d

UVa 624 CD (0-1 backpack)

tracks (and durations) which are the correct solutions and string ' sum: ' and sum of duration times. Sample Input 5 3 1 3 4 4 9 8 4 2 4 5 7 4 8 1 2 3

Solving 0-1 knapsack problem with priority queue Branch-and-gauge method

, the second known as the Limit function, Whether the optimal solution is possible.3. In order to find the solution of the 0-1 knapsack problem as soon as possible, each time the next Slipknot point is chosen as the extension node, it is the next node that is most likely to find the optimal solution in the current situation. Therefore, each time you select an extension node: In the current case, select the

"Backpack" 0-1 backpack with full backpack one-dimensional array implementation

Backpack problem is very classic, "backpack problem Nine" speak very detailed, suggest to take a look. Here, I want to give 0-1 backpacks and complete backpack compression space after the implementation, that is, as long as a one-dimensional array. The 0-1 backpack, unlike the complete backpack, is just the same as

0/1 knapsack problem by dynamic programming method to solve--java realization

example: To find the Fibonacci number F (5):F (5) = f (4) + F (3);Sub-Problem: f (4) = f (3) + F (2);F (3) = f (2) + f (1);F (2) = f (1) + f (0)F (2) = f (1) + f (0);Sub-Problem: f (3)

How many times has the 0~400 1 appeared?

It's a little piece of cake in the neighborhood today: "How many times did 1 appear in 0~400?" ”。Side dishes to see the majority of users to the algorithm is based on string processing, the idea is roughly: stitching all the numbers into a string, and then processing the string, and then get the number of occurrences. For example, the following code:1 /**2 * User

0-1 Backpack Re-revision

comments:1#include 2 3 using namespacestd;4 Const intn=1010;5 intA[n];6 intB[n][n];7 intMain ()8 {9 intn,m,m;Ten while(SCANF ("%d%d%d", n,m,m) = =3) One { A for(inti =0; I ) -scanf"%d", a[i]);//number of pieces per product - the for(inti =0; I ) -b[i][

Timus 1209. 1, 10,100,100 0...

: 110100100010000 .... Your task is to give the value of the specified position of the sequence. Through careful observation, we can see that the first 1 in the sequence (x + 1) is located in the nth = 1 + (1 + 2 +... x) = 1 + x (x + 1

0-1 knapsack problem of algorithm design

, update the current optimal total value for the current total value (i.e. BESTP=CP), updateLoading scheme (i.e. Bestx[i]=x[i] (1≤i≤n));The ② uses a for loop to discuss item I and no two cases (0≤j≤1):1> x[i]=j;2> If the total weight is not greater than the backpack capacity (i.e. cw+x[i]*w[i]The number of backtrack (I

Compile the c serial port program in linux: Infileincludedfromserial. c: 1: 0:

Compile the c serial port program in linux: Infileincludedfromserial. c: 1: 0: -- Linux general technology-Linux technology and application information. See the following for details. Serial Port program serial. c CODE: # include "serial. h"Static struct termios termios_old, termios_new;// Set the serial communication rateInt _ BaudRate (int baudrate){Switch (baudrate){Case B2400:Return (2400

"Translated from MoS article" The/var/log/messages of Linux is empty (0k), messages.0, Messages.1 is also empty

Linux/var/log/messages is empty (0k), messages.0, Messages.1 is also emptyFrom:The/var/log/messages is empty, and so is the rotated log files such as messages.0, Messages.1,... (Document ID 2053885.1)Suitable for:Linux os-version Enterprise Linux 4.0 to Oracle Linux 7.1 with unbreakable Linux kerne l[3.8.13] [Release R

The difference between raid0+1 and raid1+0

The difference between raid0+1 and raid1+0 Requires 4 hard drivesDISK1, DISK2, DISK3, DISK4 A raid0+1Raid0+1 can not RAID0 each side of the bad hard disk, but can be unilateral at the same time the unilateral two hard drive.Reason: If DISK1 a1,disk a2,disk3 B1, DISK B2A (A1,A2) B (B1,B2)

Learning programming from 0 (1)-115-general knowledge

Introduction: This is the detailed page for learning programming from 0 (1)-115 -- a general understanding. It introduces PHP and PHP programming from 0 (1) -115-have a general understanding of related knowledge, skills, experience, and some PHP source code. Class = 'pingjiaf' frameborder = '

POJ 2184--cow Exhibition (0-1 backpack variant)

~ ~ (specific look at the code bar)The code is as follows:1#include 2#include 3 using namespacestd;4 Const intINF =0x3f3f3f3f;5 Const intMAXN =100000;6 Const intAdd =100000;7 intdp[200001], si, FI, N, I, J, ans;8 intMain ()9 {TenCIN >>N; OneMemset (DP,-inf,sizeof(DP)); ADp[add] =0; - for(i =1; I ) - { theCin

See RAID0+1 and raid1+0 through a data catastrophe

composed of one of the RAID1 in the RAID0 of a disk offline (should be 1 or 3), resulting in the entire RAID0 offline (two offline), and then has been a single RAID0 way to work (remember unexpectedly two years, Khan!) Until recently, one of the remaining groups of RAID0 was offline, and raid was completely paralyzed. The raid card used by the user is a Adaptec 0-channel RAID card, which can not safely buf

Regular Expressions: Mailbox format and phone number (3-4-bit area code, 7-8-digit live number, 1-4 poorly transposition number)

)function Mail() { varPatten2=NewREGEXP (/^[0-9| a-z|_]{1,17}[@][0-9| a-z]{1,3}. (COM) $/)//e-mail Regular expression varPatten1 =NewREGEXP (/(\d{11}) |^ ((\d{7,8}) | ( \D{4}|\D{3})-(\d{7,8}) | (\d{4}|\d{3})-(\d{7,8})-(\d{4}|\d{3}|\d{2}|\d{

1153:0 start-up algorithm 60--element forward 1 bit

1153:0 start-up algorithm 60--element forward 1-bit time limit:1 Sec Memory limit:64 MB 64bit IO Format:%lldsubmitted:859 accepted:574[Submit] [Status] [Web Board] DescriptionMoves the array all elements forward one (the first element moves to the last) and then outputs the moved arrayInputMultiple sets of test data, each setThe first line enters an inte

Backtracking 6th questions-0/1 string Problems

[Problem description] the input is a string consisting of only 0/1 characters and cannot contain three consecutive identical substrings.Input: the length of the string is n (n Output: the number of all strings that meet the condition.[Sample input] 2[Sample output] 4[Problem Analysis] Set the length of the 0/

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