OriginalCodeYou cannot enter only one decimal point.
BeginCase key'0' .. '9', #8, #13, #45, #27, '.':; // #8 return key, #13 return key// Enter 0-9, return, press enter, point, and negative number.ElseBeginMessageBox (0, 'enter a value! ', 'Input error', mb_ OK + mb_iconerror );Key: = #0;End;End;End;
Only one decimal point is allowed:
Add the following code to the keypress event:If not (key
JavaDecimalFormat dcmfmt = new DecimalFormat ("0.00");Double db = 12333.353;System.out.println (Dcmfmt.format (db));JsJava, medium double precision double control retains two decimal places, JS controls two decimal places
06 implement the four-digit provisioner for determining the decimal point input location, and the four-digit decimal point operation
1 private void txtnumberw.keypress (object sender, KeyPressEventArgs e) 2 {3 // MessageBox. show (int) (e. keyChar )). toString (); // ASCii View 4 // This event may be triggered by multiple text boxes, therefore, use sender to obtain the control 5 TextBox currentTextBox = sen
1. The dumbest way ... [I'll do what I do ...]function Get (){var s = 22.127456 + "";var str = s.substring (0,s.indexof (".") + 3);alert (str);}2. Regular expression effect is good3. He is more clever ...4. Friends who will use new things .... But we need ie5.5+ to support it.from:http://xinlingwuyu.javaeye.com/blog/175931JS retains 2 decimal places after the decimal point
When two integers are divided, because the number after the decimal point is truncated, so that the result of the operation is an integer, so if you want to get the result of the operation is the expected floating-point number, then the two integers must be one or all cast as floating-point numbers.For example:(float) A/b cast one of the integers to a floating-point number, and then divide by another integerA/(float) b(float) A/(float) b//convert two
In js, the most common method for getting the decimal point and the two decimal points is the rounding function. I have previously introduced this common function in js, which is useful here, next let's take a look at some methods to sum up the two digits after the float decimal point.
Use Javascript to get the first two digits of the float
Calculate the percentage of two numbers in js, retain the percentage of the two digits after the decimal point, js decimal pointFunction Percentage (number1, number2 ){Return (Math. round (num/total * 10000)/100.00 + "%"); // percentage of the two digits after the decimal point}Two decimal digits, two
Non-terminating decimal expansion; no exact representable decimal result-Lopper column-blog channel-csdn. Net http://blog.csdn.net/lopper/article/details/5314686
Because it is necessary to process floating-point numbers with relatively high precision, double type should be discarded, and bigdecimal type should be used for numerical processing.
There is no problem in addition, subtraction, multiplication, b
We want to modify the display format of a page's data, which requires two steps:1. In JS through $ ('. Class1. Class2 Li:eq (2) Span.value '). Text (). Trim (); A similar statement gets the contents of the data.2. Modify the data to the desired format. (eg:data=10 ==> 9+1)If we get the data value is an integer, then no problem, things will go well, as expected results.But if you take a decimal, the problem comes.What is this for?A: This is related to
C # decimal retains the specified decimal places,
When decimal retains the specified decimal digits, the. NET method is rounding.
If the project encounters a apportioned amount, the amount in the last line = total amount-sum of the apportioned amount.
This may result in a negative number when the last part is apportion
Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float Totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100); If the exact 4-bit is required *10000 then/10000Method 2: Return with DecimalFormat in string format. The class is fully encapsulated in
Turn from:Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100); /If the exact 4-bit is required *10000 then/10000Method 2: Return with DecimalFormat in string format. The class is fully encapsulated in
Today, when using two BigDecimal-type numbers for the division operation, a following exception message appears:1 java.lang.arithmeticexception:non-terminating decimal expansion; No exact representable decimal resultOn the internet to check this anomaly, found the reason: when the division by BigDecimal divide method when not evenly divisible, an infinite loop of decimals, will throw an exception: Java.lan
There's a problem.
First enter the integer part and then the whole part of the deletion, in disguise let the decimal point to the first place
In the case of a two-bit decimal, you cannot change a two-bit number if selected
Netizen Ymwcwee has corrected please refer to his code
Http://blog.csdn.net/jzz870519/archive/2010/08/08/5796876.aspx, because I always failed to reply to the code, so I opened it mys
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