perforce p4

instead of the current version, a good source code control system can play a role. Most IDEs support Concurrent Version System (CVS) and Subversion, which are both open-source control systems. One IDE supports Perforce, a commercial source code control system. FTP/SFTP integration One function related to source code control is to use FTP for the latest code on the server. This is much easier than using an FTP client or package a file and sendi

, both of which are open source control systems. One of the Ides supports perforce--a commercial source control system. FTP/SFTP Integration A feature associated with source control is the use of FTP on the server for the latest code. This is much easier than using an FTP client or packaging a file and sending it to the server and then unpacking it. Database navigation A non-basic but very useful feature is database navigation. With this feature, you

Author: redguardtoo) Updated on: 4-11-29 Original time: Taste is quite small. If you use a famous free software package that hundreds of millions of working people love, you don't have to read this article. My software selection criteria are: Powerful functions (programmable, supporting plug-ins) Excellent Performance (with no graphic interface, written in C, general performance is acceptable) Honest and reliable (it is best to open the source. if the source is closed, developers should have

; Multiple users (professional and shortate edition ); Forward or reverse code Engineering (professional and reverse ate edition)-supports Java, C #, C ++, VB. NET, Delphi, Visual Basic, and PHP; XML import/export is easy; Spelling check; New Features RTF wysiwysiwyg template editor and report builder-ea has enhanced the feature of generating RTF documents in its Enterprise and Professional editions by using a template driver to generate RTF documents, users can customize the appearan

. Then the test reports program exceptions to the senior management, and the senior management notifies the developers to make changes. Instead, the developers return to the high-level decision. At the end of the meeting, we were able to determine the function behavior in two hours. The result is that these functions are used by other groups, and these actions must be modified to adapt to the applications of other groups. Then the error loop appears again. We can see the reason for the delay of

, it supports the following code version management software: SVN, CVS, perforce, git, bazaar, and mercurial. Yahoo is one of the users of review-board. "The review board has changed the code review method, which can force high-quality code standards and styles and become the programmer's mentor in programming. Every time you access search.yahoo.com, the code is review using the review board tool. We're re great fans of your work !" -Yahoo! Web Searc

Git Study Notes (1), Git Study Notes ( Version Control System Overview A version control system is a system that records changes in the content of several files for future reference to specific version revisions. The system can not only control the version of text files of software source code, but also control the version of any other types of files. With the version control system, we can trace a file back to the previous state, or even trace the entire project back to the previous state at a

code version management software: SVN, CVS, Perforce, Git (http://progit.org/book/zh/), Bazaar, and mercurial. Yahoo is one of the users of Review-board. "Review board has changed the way code reviews, which can force high-quality code standards and styles, and can be a programmer for programmers." Every time you visit search.yahoo.com, its code is Review with the Review Board tool. We ' re great fans of your work! "–yahoo! Web Search 2. Codestriker

kill process : Ps-ef|grep Tomcat; Kill-9 Toggle Root Permissions : Sudo/usr/local/bin/sudoshvi Edit File : (Command mode): O is a line inserted below the current line q! Do not save exit: Wq Save exitSet Environment : perforce/setenv.sh or source perforce/setenv.shMount:(1) Vi/etc/fstab Add the device on the last line (the system will actively read the contents of the/etc/fstab file when booting, and mount

= 254Reply from 192.168.200.2: byte = 32 time = 3 ms TTL = 254Reply from 192.168.200.2: byte = 32 time = 3 ms TTL = 254Reply from 192.168.200.2: byte = 32 time = 9 ms TTL = 254Configure Automatic Tunnel.[R1] ipsec policy p3 300 isakmp[R1-ipsec-policy-p3-300] security acl 3000[R1-ipsec-policy-p3-300] proposal trans1[R1-ipsec-policy-p3-300] tunnel local 192.168.13.1[R1-ipsec-policy-p3-300] tunnel remote 192.168.23.2[R1-ipsec-policy-p3-300] quit[R1] ike pre-shared-key 12345 remote 192.168.23.2[R1]

"); Privilege p2 = new Privilege (); p2.setPrivilegeId (2); p2.setPrivilegeName ("delete log "); privilege p3 = new Privilege (); p3.setPrivilegeId (3); p3.setPrivilegeName ("Modify log"); Privilege p4 = new Privilege (); p4.setPrivilegeName ("view log "); p4.setPrivilegeId (4); Session session = sf. openSession (); Transaction tx = session. beginTransaction ();

__init__(self): super(Point, self).__init__() self.neibors = [] self.color = None def paint(self, c): self.color = c def clean(self): self.color = None def getLeftOverColors(self): copyOfColorList = colorList[0 : 4] for neibor in self.neibors: nc = neibor.color if nc in copyOfColorList: copyOfColorList.remove(nc) return copyOfColorListdef main(): global pointList p0 = Point() p1 = Point() p2 = Point() p3 = Point()

ref_count _. Note that the addition and subtraction operations on the counter should be atomic as much as possible.The counter class provides multiple constructor types, which support multiple constructor types of input T.[Cpp]Template Class RefCountedObject: public T {Public:RefCountedObject (): ref_count _ (0 ){}Template Explicit RefCountedObject (P p): T (p), ref_count _ (0 ){}Template RefCountedObject (P1 p1, P2 p2): T (p1, p2), ref_count _ (0 ){}Template RefCountedObject (P1 p1, P2 p2, P3

]! = 'S1 [j] = a [I];}S1 [j] = '\ 0 ';// Printf ("% s \ n", s1 );// The second substringFor (I = I + 1, j = 0; a [I]! = '>'; I ++, j ++ ){S2 [j] = a [I];}S2 [j] = '\ 0 ';// Printf ("% s \ n", s2 );// The third substringFor (I = I + 1, j = 0; a [I]! = 'S3 [j] = a [I];}S3 [j] = '\ 0 ';// Printf ("% s \ n", s3 );// The fourth substringFor (I = I + 1, j = 0; a [I]! = '>'; I ++, j ++ ){S4 [j] = a [I];}S4 [j] = '\ 0 ';// Printf ("% s \ n", s4 );// The Fifth substringFor (I = I + 1, j = 0; I S5 [j] = a

in each direction: 0, 0.5, 1. The middle-red dots are their respective anches. The sprite1 anchor is () in the lower left corner, and the sprite2 anchor is () in the upper right corner. Now let's take a look at coordinate system transformation. Similarly, let's first write the point test code: CCPoint p1 = sprite2->convertToNodeSpace(sprite1->getPosition());CCPoint p2 = sprite2->convertToWorldSpace(sprite1->getPosition());CCPoint p3 = sprite2->convertToNodeSpaceAR(sprite1->getPosition());CCPoin

, p2, p3, p4, s, t ); // returns whether the straight line where p1 is the start point p2 is the end line 1 and p3 is the start point p4 is the end line 2. If yes, parameters s and t return the ratio of the intersection online segment 1 and Line Segment 2.// Obtain the intersection of s and t by p1 + s * (p2-p1) or p3 + t * (p4-p3.CcpSegmentIntersect (A, B C, D

items deleted from the queue, A ValueError exception q. join (): The producer calls this method for blocking until all items in the queue are processed. Blocking continues until every project in the queue calls the q. task_done () method. From multiprocessing import Process, JoinableQueueimport timeimport randomimport osdef consumer (q): while True: res = q. get () time. sleep (random. randint (1, 3) print ('% s eat % s' % (OS. getpid (), res) q. task_done () def product_baozi (q): for I in ran

queue. After that, the player would immediately connect to the server again and starts queuing at the tail of the queue.3. Activation succeeded:this happens with the probability of P3. Congratulations, the player would leave the queue and enjoy the game himself.4. Service unavailable:this happens with the probability of P4. Something just happened and the server are down. The website must shutdown the server at once. All the requests is still in the

To determine whether two polygons intersect, simply determine if the edges intersect.The amount of coding is a bit large, but the idea is quite simple.#include #include#include#include#includestring>#include#include#include#includeusing namespacestd;strings;structpoint{Doublex; Doubley; Point (DoubleADoubleb) {x=a;y=b;}};structsharp{stringname; Vectorv; Vectorstring>ans;} sharp[ -];inttot;BOOLcmpConstSharpa,Constsharpb) { returna.nameB.name;}voidWork () {inta,b,c,d,e,f; if(s=="Square") {scanf

rotation) will be around the anchor point , we can be seen as the center of the elf position, in general there are three possible values in each direction: 0,0.5,1. The red dots are the respective anchor points, the sprite1 anchor Point is (0,0) the lower left corner, and the Sprite2 anchor point is in the upper right corner.Now let's look at the coordinate system transformation, and again, let's write some test code:Ccpoint P1 = Sprite2->converttonodespace (Sprite1->getposition ()); Ccpoint P2