pii breach

String > 13 # Include 14 # Include 15 # Include 16 # Include 17 # Include 18 # Include Set > 19 Using Namespace STD; 20 21 Typedef Long Long Ll; 22 # Define Debug (x) cout 23 # Define Rep (I, n) for (INT I = 0; I 24 # Define For (I, S, T) for (INT I = (s); I 25 # Define PII pair 26 # Define PB push_back 27 # Define MP make_pair 28 # Define Fi first 29 # Define Se second 30 # Define Lowbit (x) (X (-x )) 31 # D

data bit, which can be 8 to 192 digits at most. The data should be an integer multiple of the bytes. Crcl6 is a 16-bit CRC verification code for data domain verification. The verification polynomials are: g (x) = x16 + x15 + X2 + 1. 3) handshake packet formatA handshake package is used to indicate the transaction status, such as the successful receipt of data, the receipt of commands, and the rejection. The handshake package format is 10.35.A handshake package consists of only

This article draws on http://www.puschitz.com/ Article :Installing Oracle 9i on Redhat Linux 7.1, 7.2, 7.3, 8.0, 9, Red Hat Advanced Server 2.1, and on Red Hat Enterprise Linux Advanced Server 3 (RHEL as 3)Machine configuration: HP lh6000Cpu pii 700Memory 512 MBTwo 36 GB hard disks for RAID 0Linux: RedHat linux.7.1Partition:/boot: 100 m swap: 1024 M/: all available spaceSelect install XWindow and KDE.Setting XWindow supports remote logon to Linux usin

textbox TB; Public helloworld () { exitcommand = new command ("exit", command. exit, 1); TB = new Textbox ("Hello MIDlet", "Hello, world! ", 15, 0); TB. addcommand (exitcommand); TB. setcommandlistener (this); } protected void Startapp () { display. getdisplay (this ). setcurrent (TB); } protected void pauseapp () {} protected void destroyapp (Boolean U) {} Public void commandaction (command C, displayable d) { If (C = exitcommand) { destroyapp (false); policydestroyed (); }

on with "27" headers are EPROM (486 and less than 486 of the computer using the chip), while 28c010, 29c010, 29c020, 29c040, etc., are EEPROM, 29c010 is 128 K * 8, that is, 1 M bit Parallel EPROM, 29c010 is 128 K * 8 (1 M bit), 29c020 is 256 K * 8 (2 M bit) 29c040 is a 512 K * 8 (4 M bit) Flash ROM (586 and PII, piII BIOS chip ). Serial EEPROM is rare on the computer motherboard, and most of the manufacturers that provide these chips are MX, WINBOND,

An instance that uses iptables to configure Nat Zhake, 2006-11-24 This article describes how to use iptables to create Nat in Linux. We can use it as a gateway so that multiple machines in the LAN can use a public IP address to connect to the Internet. the method I use is to override the source address and target address of the IP package through the NAT system. Preparation:CPU: PII or higherSystem: Any Linux versionSoftware: iptablesNIC: 2 Idea:Rep

algorithm, see Manacher algorithm. #define N 110050#define M 100005#define maxn 205#define MOD 1000000000000000007int T,n,a,pri[N],ans,len,sn = 0,top[N],tail[N],pn,ln;bool dp[N][4];pii seg[N];bool Manacher(char str[],int len){ char tstr[N+N]; int p[N + N],l2 =0,mi; tstr[l2++] = '#'; for(int i =0;i SourceBestCoder Round #49 ($) Recommendhujie | We have carefully selected several similar problems for you: 5342 5341 5339 5338 Copyright Dis

= zh_CN.GB2312Export XMODIFIERS = @ im = fcitxFcitxIn this way, fcitx can be automatically started with X. Vim Configuration:After installation, go to the system to configure vim and run the following command as the Root user:Cp/usr/share/vim/vim63/vimrc_example.vim/usr/share/vim/vimrc Kernel header file installation:Apt-get install kernel-headers'-2.6.8-2 Kernel image update:If your CPU is one of PPro/celon/PII/PIII/P4, you can install the following

, and 90nm. Recently, it has been officially said that there are 65nm manufacturing processes. 10. Instruction Set (1) CISC Instruction Set The CISC Instruction Set, also known as a Complex Instruction Set. Its English name is CISC (abbreviation of Complex Instruction Set Computer ). In the CISC microprocessor, each instruction in the program is executed in sequence, and each operation in each instruction is also executed in sequence. The advantage of sequential execution is that the control is

, max = + 0.00 V) ALARM + 3.3 V: + 3.34 V (min = + 2.97 V, max = + 3.63 V) + 5 V: + 5.12 V (min = + 4.50 V, max = + 5.48 V) + 12 V: + 11.67 V (min = + 10.79 V, max = + 13.11 V) -12 V:-11.83 V (min =-13.21 V, max =-10.90 V) -5 V: + 3.53 V (min =-5.51 V, max =-4.51 V) ALARM V5SB: + 5.58 V (min = + 4.50 V, max = + 5.48 V) VBat: + 3.15 V (min = + 2.70 V, max = + 3.29 V) Fan1: 3970 RPM (min = 3000 RPM, div = 2) Fan2: 0 RPM (min = 3000 RPM, div = 2) ALARM Temp1: + 40 °C (limit = + 60 °C) sensor = ther

Create a cross-compiling environment in Linux-Linux general technology-Linux programming and kernel information. For more information, see the following. Recently, many of my friends have been discussing how to build a cross-compiling environment for Linux. The following are some of the issues to be discussed in order to encourage others. The application development environment based on the Linux operating system is generally composed of the target system hardware (Development Board) and the ho

the body (MINI-PCI or mini pci-Express) and a preset antenna. In this way, you only need to purchase the wireless network card of the corresponding interface and connect the antenna. If you have an expansion slot (MINI-PCI or mini pci-Express) that is not cabled, you can also install and use the antenna after purchasing it. There are two types of expansion slots in the fuselage: Mini-PCI or Mini PCI-Express. The Mini-PCI wireless network adapter can be supported from the end of the

corresponding interface and connect the antenna. If you have an expansion slot (MINI-PCI or mini pci-Express) that is not cabled, you can also install and use the antenna after purchasing it. There are two types of expansion slots in the fuselage: Mini-PCI or Mini PCI-Express. The Mini-PCI wireless network adapter can be supported from the end of the PII model to many models of the second generation. However, because currently popular models of the t

structures that satisfy the same pre-sequence traversal and post-order traversal (title dry)　　　　　　　　This topic asks us to ask how many of the two fork trees satisfy the situation, that is, let's find out how many nodes have only one child nodeSo how are we going to handle this?This again uses the nature of the pre-order traversal and subsequent traversal: the position of a node and its only child nodes in the pre-sequence traversal and post-order traversal is exactly the opposite (i.e. crossdre

It's a new week, eh.8.8Do CFAfter a day's game, B thought well and complicated. Always count SG is wrong.C is not understand how to deal with the first T-seconds inside not be 2 operation of the number of operations droppedCF 366 Div2 c C-thorTo each node A queue, the queue is stored in the corresponding to the time it added,In the 3 operation, you can maintain a position, if the last operation to T1 then this operation will only need to T1 to T2.I didn't expect to throw every time as a thing in

#defineREP1 (I,L,R) for (int i = (l); I #defineRep_0 (i,r,l) for (int i = (r); i > (l); i--)#defineRep_1 (i,r,l) for (int i = (r); I >= (l); i--)#defineMS0 (a) memset (A,0,sizeof (a))#defineMS1 (a) memset (A,-1,sizeof (a))#defineMSi (a) memset (A,0x3f,sizeof (a))#defineINF 0x3f3f3f3f#defineLson L, M, RT #defineRson m+1, R, RT #defineSqr (a) (a) * (a)typedef pairint,int>PII;#defineA First#defineB Second#defineMK Make_pairtypedef __int64 Ll;templatevoi

", stdin) - #defineFWrite () freopen ("Out", "w", stdout) - #defineRep (i, Len) for (int i = 0; i the #defineFor (I, A, Len) for (int i = (a); I - #defineCls (a) memset ((a), 0, sizeof (a))Wuyi #defineCLR (A, X) memset ((a), (x), sizeof (a)) the #defineFull (a) memset ((a), 0x7f7f7f, sizeof (a)) - #defineLRT RT Wu #defineRRT RT - #definePi 3.14159265359 About #defineRT return $ #defineLowbit (x) x (-X) - #defineOnenum (x) __builtin_popcount (x) -typedefLong LongLL; -typedefLong DoubleLD; At

balance tree is empty, then output-1Too bad! ~ ~ ~#include #include#include#include#include#include#includestring>#include#include#include#include#include#includeSet>#include#include#include#include#include#include#include#include//#include using namespaceStd;typedefLong LongLl;typedefDoubleDb;typedef pairint,int>Pii;typedef pairPdd;typedef Complexcp;typedef Vectorint>VI;#defineMmSt (a,v) memset (A,v,sizeof (a))#defineMmcy (A, B) memcpy (A,b,sizeof

Topic Link: PortalThe main topic: slightlyTopic Idea: Use the function of the topic to launch the expression, and then use the equal-to-sum formula to get the relationship between (need multiplication inverse element), can also directly construct the matrix, with the matrix fast power solution.Feel: Do the problem must be careful, need to carefully pay attention to when the use of%, the problem because of the use of improper, WA3 times#include #include#include#include#include#include#include#inc

problem:I'll give you a string of M, which is the number of strings with a length of N, at least one of which is a substring.analize:-Turn problems into k ?NoPackagecontainingRenmeaningChildstringof theanumber , where an AC automaton is used to create a forbidden string.-The child nodes of all nodes begin as root nodes and are extended during the process of adding forbidden strings-Use the fail pointer to extend the forbidden string, that is, the string of the fail pointer of the c