pii breach

3100 100Answer4 29 46 41 22 24 39 49 3 #include #include #include #include #include #include using namespace STD;Const intMAXN =1e4;Const intINF =2*1e9+Ten;Const intdir[4][2] = { {0,1}, {0, -1}, {1,0}, {-1,0} };typedefpairint,int> PII;intN, Nw, Nb, x[maxn+5], y[maxn+5], f[maxn+5], c[maxn+5]; mapint>RvoidInit () {scanf("%d", n); Nw = N/2; Nb = N-NW; R.clear (); for(inti =0; i 0; }}inline intBit (intx) {returnx1;}intGetfar (intx) {returnF[X] = = x?

foregoing provisions, and describes the objects and scope of disclosure. 2.9 Party A shall not guarantee the accuracy and rationality of the confidential information. 2.10 if Party B learns that other third parties have obtained any confidential information, it shall promptly notify Party A in writing and provide Party A with all relevant information. Article 3 Liability for Breach Party B's failure to perform the terms hereunder shall be deemed as a

Test instructions: Like poj3268, everyone needs to find the shortest sum from one point to the next, from point to point.As with poj3268, the first is to build the map to run Dijkstra, get that point to all the other points of the shortest, that is, these people back to the most short-circuit, and then use the inverse of the map to run a short way to get points to the point of the most shorted, sum on the line.1#include 2#include string.h>3#include 4#include 5#include 6 using namespacestd;7typed

Test instructionsThe scheme number of the longest ascending subsequence for a given number of $n$ According to data range requirements is $o (n\log N) $Naïve DP Equation $f_i=max (f_j+1), a_i>a_j$, so the number of scenarios is $v_i$, then $v_i=v_i+v_j, (f_i=f_j+1) $, using the LIS $o (n\log N) $ tree array practice simultaneously maintaining length and number of scenariosA more detailed explanation is also found in the Thong Paste blog: StackOverflowTime Complexity $o (n\log N) $Code#incl

51nod1053 This problem is still familiar with the M-sub-section and, but n,m This problem seems to be a pile of + linked list of topics AH Begin to consider locking all positive negative numbers together. For example: 1 2 3-1–2-3 666 is reduced to 6-6 666 so. Then use a heap to maintain, that is, all negative and positive numbers are thrown into the heap, select all positive numbers, and then each time the number of absolute values in the heap (if negative and not left or right to skip) and the

questions should be brought to your attention: * Closing the unsecured renegotiation feature was found to be unsafe in 2009 and the protocol needs to be updated. Most manufacturers have repaired today, at least with a temporary solution. Unsafe renegotiation is dangerous because she is easily exploited. * Off TLS compression 2012, the crime attack [6] showed us that the information disclosure caused by TLS compression could be used by attackers to restore sensitive data (such as session cookies

references two namespace: Copy Code code as follows: Using Insus.net; Using System.Reflection; Read-Write properties: Copy Code code as follows: Using System; Using System.Collections.Generic; Using System.Linq; Using System.Web; Using System.Web.UI; Using System.Web.UI.WebControls; Using Insus.net; Using System.Reflection; public partial class _default:system.web.ui.page { protected void Page_Load (object sender, EventArgs e) { Instantiating c

drive will read for a long time and occupy a lot of space once the program goes wrong. If this is the case, look for the User.dmp file, which saves dozens of MB of space after deletion. 8, cancel the support of the zip file: run, typing: regsvr32/u zipfldr.dll and then enter. 9.WINDOWS2003 Memory Optimization: Disabling memory page scheduling: Disablepagingexecutive value to "1", lifting System cache: LargeSystemCache value to "1" 10. Modify the CPU level two cache under normal circumstances

contains the sequence F0, F1, ..., fn -1 ( C16>0≤ FI n) and the third-the sequence w0, w1, ..., wn -1 (0≤ wi ≤108). OutputPrint n lines, the pair of integers si, mi in each line. Examplesinput7 31 2 3 4 3 2 66 3 1 4 2 2 3Output10 18 17 110 28 27 19 3Input4 40 1 2 30 1 2 3Output0 04 18 212 3Input5 31 2 3) 4 04 1 2) 14 3Output7 117 119 221 38 1#include #include#include#include#include#defineFi first#defineSe Secondusing namespaceStd;typedefLong LongLl;typedef pairint>

Test instructions: There are n cities, between cities can be sent by mail or e-mail messages, known m-mail lines, each line on behalf of A can send mail to B, and spend V time, if several cities can mail each other, then they are in the same country, they can send messages through e-mail, It takes 0 time. There are k queries, and each time you ask for a message from point A to B, the minimum amount of time it takes.Since multiple cities can send mail to each other, it is not necessary to pass me

Test instructions: A person from home to school, walking speed 10km/h, there are subway 40km/h on the map, the subway has different lines, each line on the subway can be interconnected, two adjacent stations between the subway to run in a straight line, different metro lines can not be directly through the subway to arrive, but the different locations could be directly walking, straight line walk. To the home, school, the coordinates of the subway platform (unit m), ask how long it takes the sho

Test instructions: Frog jump stone, give the coordinates of the stone, and then to determine a path, so that the maximum span of the path is the smallest, in fact, is also a short-circuit problem, as long as the update condition from the total distance from the shortest to the maximum span of the smallest line, that is, from a point to the current point path of the maximum span Or the current point has not been accessed, no maximum span, then update it, and then run Dij or SPFA on this condition