pimax 8k

=" consider using RAID 50 to replace raid ten (SSD) "style=" Border:0px;vertical-align:middle;height:auto; />RAID 50 in the above comparison has been able to tolerate the 3rd or even 4th disk failure, but the availability is lower than raid 10, but neither of them can achieve the perfect 100%, so the tradeoff between availability and cost of RAID 50 is a considerable advantage.Next look at performance, in order to be able to analyze performance well, we followed the first set of comparison scena

server settings are taken at the time of connection. If you are not using a shared service, then the configuration differs from the default worth of SDU that needs to be set on both the client and server side. For shared services mode, because the server side defaults to the maximum value, you only need to set the client's value. When the allocated information size is not 8192, you need to consider modifying the SDU size. The SDU size should be 70b larger than the allocated information size. If

greater than the advantages.2: Logical fields, such as gender fields, and so on, match too many records, and the table scan is comparable.3: Fields with very large field content, such as text, can greatly increase the space occupied by the index and the speed at which the index is updated.We say that SQL consumes system resources when maintaining indexes, so what resources does SQL consume when maintaining indexes? What problems will arise? How exactly can I optimize the index of a field?First:

] zhaiqutianshangxing]# mknod/dev/null C 1 3[Email protected] zhaiqutianshangxing]# chmod 666/dev/nullThen execute the command to view the/dev/null file as shown below and have successfully repaired the/dev/null file[Email protected] zhaiqutianshangxing]# Ls-la/dev/nullcrw-rw-rw-. 1 root root 1, 3 December 13:13/dev/nullTest disk IO with/dev/zero:[[email protected] zhaiqutianshangxing]# dd If=/dev/zero of=test bs=64k count=4k Oflag=dsyncRecorded 4096+0 read-inRecorded the writing of 4096+0.26843

lot of great gods in the class who have got better offer, because I think a few are really strong. In fact, I can in the interview when my salary is very good, open 8k,9k wages, like some like to brag about their own people. However, I know that I am a small rookie, give me 6k, or the first job since graduation, I have been very satisfied, if I took the salary of more than 8k to go to the company, then I g

; Uwsgi_temp_path/var/tmp/uwsgi_temp 1 2; Scgi_temp_path/var/tmp/scgi_temp 1 2; Ignore_invalid_headers on; Server_names_hash_max_size 256; Server_names_hash_bucket_size 64; Client_header_buffer_size 8k; Large_client_header_buffers 4 32k; Connection_pool_size 256; Request_pool_size 64k; Output_buffers 2 128k; Postpone_output 1460; Client_header_timeout 1m; Client_body_timeout 3m; Se

(listenfd,10); maxfd=listenfd; Initializecounter=-1;for (i=0;iClient Core code:re-find work since, voted the first, yesterday to face, 9377, feel good, but feel oneself asking too high ~ ~ ~A fresh student, no service end of the work experience, only half a year of u3d internship experience, to 8K did, or too young, too little experience ah ~ ~, in fact 8K is only expected, low point is indifferent, 6k5 I

crontab-e XX * * */bin/bash/usr/local/webserver/nginx/sbin/cut_nginx_l og.sh #/sbin/service crond restart Copy Code--------------nginx Configuring gzip compressionIn general, the compressed HTML, CSS, JS, PHP, jhtml and other files, the size can be reduced to the original 25%, that is, the original 100k of HTML, compressed only 25k left. This can undoubtedly save a lot of bandwidth, but also can reduce the load of the server.Configuring Gzip in Nginx is easierIn

;Default: proxy_buffer_size 4k|8k;Context: http, server, location//proxy_buffers 缓冲区Syntax: proxy_buffers number size;Default: proxy_buffers 8 4k|8k;Context: http, server, location6.Proxy proxy site commonly used optimization configuration is as follows, the configuration is written to a new file, called when using the include reference[[emailprotected] ~]# vim /etc/nginx/proxy_paramsproxy_set_header Host $

routine stress testing.Installation: [root@linwaterbin ~]# yum install -y iozone Parameter description:-L: Minimum number of processes-U: Maximum number of processes-R: Basic read/write unit, subject to the block size of the test objectFor example, if the Oracle block is set to 8 K, you can set it to 8 K.-S: It is consistent with the meaning of the S parameter of Bonnie ++.If this value is too small, the test results will be affected.Because many programs have run out of memory-F: cached files

4K rw-- /lib/libkrb5support.so.0.1002a3000 16K r-x- /lib/libplc4.so002a7000 4K rw-- /lib/libplc4.so002ab000 88K r-x- /lib/libaudit.so.1.0.0002c1000 4K r-- /lib/libaudit.so.1.0.0002c2000 4K rw-- /lib/libaudit.so.1.0.0002c3000 216K r-x- /lib/libgssapi_krb5.so.2.2002f9000 4K rw-- /lib/libgssapi_krb5.so.2.2002fa000 808K r-x- /lib/libkrb5.so.3.3003c4000 24K rw-- /lib/libkrb5.so.3.3003ca000 152K r-x- /lib/libk5crypto.so.3.1003f0000 4K rw-- /lib/libk5crypto.so.3.1003f1000 92K r-x- /usr/lib/libnssutil3

source end and Terminal Matching resistance are both 75 ohm, as shown below: Hsync and vsync synchronize row data without frame data, which is TTL level. 0.714 V is divided by the resistance pressure. As shown above, the parallel resistance on the left and the resistance on the right obtain 0 ~ The voltage range of 0.714 is shown as follows: So I calculated the divider resistance as follows: 253.96 k | 1 k | 2 k | 4 k | 8 k | 16 K ≈ Ω 0.5k | 1 k | 2 k | 4 k | 8 K ≈ 258.06 Ω (1) F

Nginx gzip Configuration parameter descriptionGzipDecide whether to open the Gzip module:Param:on|offExample:gzip on;Gzip_buffersSet the size of the gzip request memory to request memory space by a multiple of the block sizeParam1:intParam2:int (k) the rear unit is KExample:gzip_buffers 4 8k;Gzip_comp_levelSet the GZIP compression level, the lower the level of compression faster file compression than the smaller, whereas slower file compression than t

',--log file name@MaxMinutes =--Limit on time allowed to wrap log.@NewSize = 1-the size of the log file you want to set (M) Setup/initializeDECLARE @OriginalSize intSELECT @OriginalSize = sizeFrom SysfilesWHERE name = @LogicalFileNameSELECT ' Original Size of ' + db_name () + ' LOG is ' +CONVERT (VARCHAR, @OriginalSize) + ' 8K pages or ' +CONVERT (VARCHAR (@OriginalSize *8/1024)) + ' MB 'From SysfilesWHERE name = @LogicalFileNameCREATE TABLE Dummytr

accepts for one client request at a time. This header includes not only the request-line, but also the general information header, the Request header field, and the length sum of the response header fields. This also limits the length of the URL to a considerable extent. Nginx Server default limit is 4K or 8K, which is based on the hardware configuration of the server, usually the size of the memory page, the majority of the current is 4K, that is, 4

their products, user positioning, this hotspot can rub, occasion marketing is the common means of operators. The major news platform, the vertical platform of Internet information, Baidu Search and the list, micro-bo hot search, etc. are hot source, daily attention, great benefit.Finally,Re-disk summary, the above all the steps completed, not just finished, but to summarize, to sort out the applicable model, the fragmentation into a system, in order to better improve their ability. Operating co

let me in the office. Just tell me that we are outsourcing companies. ask me how long I have worked, I said 3 years, Android front and back are done. This man said we have a similar to you, now 8k can you accept it? I said I think about it! really shocking. Then I thought about it, I did not do the right thing is that I went to the company before the interview did not have some basic information about this company, leading to White run a trip! so th

stack top address of the kernel stack is given directly to the stacking pointer register.3. Implementation of kernel stacksKernel stacks are implemented differently in kernel-2.4 and kernel-2.6.Inside the kernel-2.4 kernel, the implementation of the kernel stack is:Union Task_union {Struct task_struct task;Unsigned long stack[init_stack_size/sizeof (long)];};Among them, the size of the init_stack_size can only be 8K.When the kernel allocates task_struct structures for each process, it actually

1 Kernel threadsThe kernel allocates 8K of stack space for each thread , with a struct thread_info structure at the top of each stack to hold thread-related information.There are several important variables:Preempt_count:This variable is divided into four parts0-7bit : Flag of whether the current process can be preempted8-15BIT:SOFTIRQ Enable Flag16-23BIT:HARDIRQ Enable Flag24bit:preempt_active flag bit ( atomic context flag bit??) )Task: process-rela

rw--/lib/libkrb5support.so.0.1 002a3000 16K r-x-/lib/libplc4.so 002a7000 4K rw--/lib/libplc4.so 002ab000 88K r-x-/lib/libaudit.so.1.0.0 002c1000 4K r--/lib/libaudit.so.1.0.0 002c2000 4K rw--/lib/libaudit.so.1.0.0 002c3000 216K r-x-/lib/libgssapi_krb5.so.2.2 002f9000 4K rw--/lib/libgssapi_krb5.so.2.2 002fa000 808K r-x-/lib/libkrb5.so.3.3 003c4000 24K rw--/lib/libkrb5.so.3.3 003ca000 152K r-x-/lib/libk5crypto.so.3.1 003f0000 4K rw--/lib/libk5crypto.so.3.1 003f1000 92K r-x-