pk0 004

effective scoreSelect s # as student ID, (SELECT score from SC where SC. S # = t. S # AND C # = '004 ') AS database, (SELECT score from SC where SC. S # = t. S # AND C # = '001') AS Enterprise Management, (SELECT score from SC where SC. S # = t. S # AND C # = '006 ') AS English, COUNT (*) AS valid course COUNT, AVG (t. score) AS average scoreFrom SC AS tGroup by s #Order by avg (t. score)18. query the highest score and lowest score of each subject: d

] Procedure: 1. on the Microsoft Windows 2003 or Windows XP desktop, click Start and run, type regedit.exe in open, and click OK ". In Windows 2000, use regedt32.exe to start the Registry Editor. 2. Locate the following registry key: [HKEY_LOCAL_MACHINE \ SOFTWARE \ Microsoft \ Windows NT \ CurrentVersion \ Perflib] "Last counter" = DWORD: 425566a (22122) (this value varies with machines, not fixed values)"Last help" = DWORD: 566b (22123) (this value varies with machines, not fixed v

';16. insert some records into the SC table. These records must meet the following requirements: Student IDs, 2, and,Average score of course no;Copy codeThe Code is as follows:Insert SC select S #, '002 ', (Select avg (score)From SC where C # = '002') from Student where S # not in (Select S # from SC where C # = '002 ');17. Show the "Database", "enterprise management", and "English" course scores of all students based on average scores in the following format: Student ID ,, database, enterprise

Student where S# not in (Select S# from SC where C#='002');17. Show the "Database", "enterprise management", and "English" course scores of all students based on average scores in the following format: Student ID ,, database, enterprise management, English, number of valid courses, average effective score Select s # as student ID, (SELECT score from SC where SC. S # = t. S # and c # = '004 ') AS database, (SELECT score from SC where SC. S # = t. S #

effective scoreSelect s # as student ID, (SELECT score from SC where SC. S # = t. S # AND C # = '004 ') AS database, (SELECT score from SC where SC. S # = t. S # AND C # = '001') AS Enterprise Management, (SELECT score from SC where SC. S # = t. S # AND C # = '006 ') AS English, COUNT (*) AS valid course COUNT, AVG (t. score) AS average scoreFrom SC AS tGroup by s #Order by avg (t. score)18. query the highest score and lowest score of each subject: d

# As student ID, (Select score from SC where SC. s # = T. S # And C # = '004 ') as database, (Select score from SC where SC. s # = T. S # And C # = '001') as Enterprise Management, (Select score from SC where SC. s # = T. S # And C # = '006 ') as English, Count (*) as valid course count, AVG (T. Score) as average scoreFrom SC as tGroup by S #Order by AVG (T. Score)18. query the highest score and lowest score of each subject: displayed as follows: cou

(*) from SC where s#= ' 1002 '); 15, delete learning "cotyledons" Teacher class SC table records; Copy Code code as follows: Delect SC From course, Teacher where COURSE.C#=SC. C # and course.t#= teacher.t# and tname= ' cotyledons '; 16, to the SC table to insert some records, these records required to meet the following conditions: No number of "003" course of the classmate number, 2,The average score of the class; Copy Code code as follows:

student ID and name of other students whose courses are identical to those of "1002; select S# from SC where C# in (select C# from SC where S#='1002') group by S# having count(*)=(select count(*) from SC where S#='1002');15. Delete the SC table record for learning "ye ping; Delect SC from course, Teacher where Course. C # = SC. C # and Course. T # = Teacher. T # and Tname = 'peiping ';16. insert some records into the SC table. These records must meet the following requirements:

requirements: Student IDs, 2, and, Average score of course no; Insert SC select S #, '002 ', (Select avg (score) From SC where C # = '002') from Student where S # not in (Select S # from SC where C # = '002 '); 17. Show the "Database", "enterprise management", and "English" course scores of all students based on average scores in the following format: Student ID ,, database, enterprise management, English, number of valid courses, average effective score Select s # as student ID , (SELECT

@ ABC rebase] $ git Branch* MasterTopic[Rocrocket @ ABC rebase] $ VI Roc. c[Rocrocket @ ABC rebase] $ git commit-a-m "master: 003 ″Created commit 91a7ffc: MASTER: 0031 files changed, 1 insertions (+), 0 deletions (-)[Rocrocket @ ABC rebase] $ VI Roc. c[Rocrocket @ ABC rebase] $ git commit-a-m "master: 004 ″Created commit b81fbc3: MASTER: 0041 files changed, 1 insertions (+), 0 deletions (-)[Rocrocket @ ABC rebase] $ cat Roc. cInt main (){Printf ("MAS

(*) = (select count (*) from SC where S # = '123 ');15. Delete the SC table record for learning "ye ping;Delect SCFrom course, TeacherWhere Course. C # = SC. C # and Course. T # = Teacher. T # and Tname = 'peiping ';16. insert some records into the SC table. These records must meet the following requirements: Student IDs, 2, and,Average score of course no;Insert SC select S #, '002 ', (Select avg (score)From SC where C # = '002') from Student where S # not in (Select S # from SC where C # = '00

valid courses, average effective scoreSelect s # As student ID, (Select score from SC where SC. s # = T. S # And C # = '004 ') as database, (Select score from SC where SC. s # = T. S # And C # = '001') as Enterprise Management, (Select score from SC where SC. s # = T. S # And C # = '006 ') as English, Count (*) as valid course count, AVG (T. Score) as average scoreFrom SC as tGroup by S #Order by AVG (T. Score)18. query the highest score and lowest s

#, '002 ', (Select avg (score)From SC where C # = '002') from Student where S # not in (Select S # from SC where C # = '002 ');17. Show the "Database", "enterprise management", and "English" course scores of all students based on average scores in the following format: Student ID ,, database, enterprise management, English, number of valid courses, average effective scoreSelect s # as student ID, (SELECT score from SC where SC. S # = t. S # AND C # = '004