/libzBxcrypto_a-md5. Tpo-c-o libzbxcrypto_a-md5.o ' test-f ' md5.c ' | | echo './' md5.cin file included from/usr/include/sys/corral.h:25,From/usr/include/libperfstat.h:28,From.. /.. /.. /include/sysinc.h:292,From.. /.. /.. /include/common.h:23,From md5.c:54:/usr/include/netinet/in6_var.h:65:error:array type has incomplete element typemake:1254-004 the error code from the last command is 1.Stop.make:1254-004
the table, with the column family columns familiesCreate ' Blog ', {name=> ' info '}, {name=> ' content '}Then, add data, note that HBase is a Rowkey-based column database, and you can add one or more columns at a time, and you must add the specified Rowkey each timeUse the PUT command:hbase> put ' table ', ' row_id ', ' family:column ', ' value 'Example:Put ' Blog ', ' Michelle-001 ', ' info:title ', ' Michelle 'Put ' Blog ', ' Matt-001 ', ' info:author ', ' Matt123 'Put ' Blog ', ' Matt-001 '
Label:Feature Description: The first is a non-field aggregation , which is then aggregated after the fields are grouped from left to right To create a table: 1 Create Table score
2 (
3 Int,
4 Varchar2(50 ),
5 varchar2(6 )
Int
7 ); View Code Insert test data: 1 Insert intoScoreValues(001,'Xiao Xu','language', the); 2 Insert intoScoreValues(001,'Xiao Xu','Mathematics',98); 3 Insert intoScoreValues(001,'Xiao Xu','Foreign Languages', About); 4 Insert intoScoreValues(002,'Xiao Wu','
, enterprise management, English, number of valid courses, average effective score
Select s # As student ID
, (Select score from SC where SC. s # = T. S # And C # = '004 ') as database
, (Select score from SC where SC. s # = T. S # And C # = '001') as Enterprise Management
, (SELECT score from SC where SC. S # = t. S # AND C # = '006 ') AS English
, COUNT (*) AS valid course COUNT, AVG (t. score) AS average score
From SC AS t
Group by s #
Orde
S (SNO, sname) Student Relationship. Sno is the student ID, and sname is the name
C (CNO, cname, cteacher) Course relationship. CNO is the course number, cname is the course name, And cteacher is the course teacher
SC (stu_no, cla_no, score) Course Selection relationship. Score
Initialization table:
Insert into S values ("001", "zhangsan"); insert into S values ("002", "padern"); insert into S values ("003 ", "wangwu"); insert into S values ("004", "X
Problem description:Create three tables to manage job business training information:Student (stu_no, stu_name, stu_workunit, age)
Stu_no, stu_name, stu_workunit, and age indicate the student ID, Student name, unit, and age respectively.
Class (cla_no, cla_name)
Cla_no. cla_name indicates the course number and Course name respectively.
SC (stu_no, cla_no, score)
Stu_no, cla_no, and score indicate the student ID, number of the selected course, and score respectively.
Initialization table:
Create
Oracle tree query. If you need it, refer to it. The code is messy. Sorry.
Oracle tree query. If you need it, refer to it. The code is messy. Sorry.
Format:
SELECT column
FROM table_name
Start with column = value
Connect by prior parent primary key = Child foreign key
Select lpad ('', 4 * (level-1) | name, job, id, super from emp
Start with super is null
Connect by prior id = super
Example:
Raw data: select no, q from a_example2
NO NAME
----------------------------------------
001 a01
001 a02
00
Format:
Select column
From table_name
Start with column = Value
Connect by prior parent primary key = Child foreign key
Select lpad ('', 4 * (level-1) | Name, job, ID, super from EMP
Start with super is null
Connect by prior id = super
Example:
Raw data: Select No, Q from a_example2
No name
----------------------------------------
001 A01
001 A02
001 A03
001 a04
001 a05
002 B01
003 c01
003 C02
004 d01
005 e01
005 e02
005 e03
005 e04
005 e05
The result
Student ID
, (SELECT score from Scores WHERE Scores.stuid=t.stuid and courseid= ' 004 ') as database
, (SELECT score from Scores WHERE Scores.stuid=t.stuid and courseid= ' 001 ') as Enterprise management
, (SELECT score from Scores WHERE Scores.stuid=t.stuid and courseid= ' 006 ') as English
, COUNT (*) as effective course number, AVG (T.score) as average score
From Scores as T
GROUP by Stuid
ORDER by AVG (T.score)
18, inquires the highest and lowest
The Zookeeper 336 and v2 use the rtl8188cus chip. In the given document (included with the CD), the supported kernel is 2.6.18-2.6.33, And the opensuse11.4 kernel version is 2.6.37. OpenSUSE: usrsrclinux # lsusbBus001Device001: ID1d6b: 0002LinuxFoundation2. 0roothubBus002Device
The Zookeeper 336 and v2 use the rtl8188cus chip. In the given document (included with the CD), the supported kernel is 2.6.18-2.6.33, And the opensuse11.4 kernel version is 2.6.37. OpenSUSE:/usr/src/linux # lsusbBus 001
Scala classes are similar to Java classes. A simple example is as follows:
class MyClass { var myField : Int = 0; def this(value : Int) = { this(); this.myField = value; } def getMyField() : Int = { return this.myField; } def addToMyField(value : Int) { this.myField += value; }}
If you are curious, you can decompile the compiled code into Java code:
import scala.reflect.ScalaSignature;@ScalaSignature(bytes="\006\00112A!\001\002\001\013\t9Q*_\"mC
.operation_time >= DATE '2016-09-01' AND NEW .operation_time
Finally, create a trigger to execute the Function:
CREATE TRIGGER sys_log_insert_trigger BEFORE INSERT ON t_sys_log_mainFOR EACH ROWEXECUTE PROCEDURE sys_log_insert_trigger();
The creation is complete here. Finally, let's test the results. To confirm that our trigger is indeed triggered, we turn on the statistics switch of the stored procedure. In postgresql. conf, find track_functions and change it to all:
Next, we can run several
Recently just the system to learn the Linux file permissions this piece, in the "Umask value and its corresponding file permissions" on this issue, looked for video (old boy teacher's video, highly recommended), also looked at the bird Brother's book, of course, also found on the Internet, find that the calculation methods are various, But personally feel mastered a kind of good, see a variety of methods, actually most are looking for the law, not to find the law is too complex, so the personal
When the last time that the received HTTP data was communicated to another thread through the pipeline, it did not send the data directly past, but rather sent the data in the shared memory handle to the past, to achieve efficient communication purposes. The following is an analysis of the resource processing process, what to do after receiving the message. The processing code for this message is as follows:
#001 void Resourcedispatcher::onreceiveddata (int request_id,
#002 Sharedmemoryhandle S
T_scoreSelect Sid, ' 002 ', (select AVG (grade) from T_score where cid = ' 002 ')From T_studentWhere Sid is not in (the Select SID from T_score WHERE cid = ' 002 ');17, according to the average score from high to low display all students "database", "Enterprise Management", "English" the course results, as shown in the following form: Student ID, database, business management, English, effective course number, effective average scoreSELECT SID as Student ID,(SELECT grade from T_score WHERE Sid=
, insert some records into the T_score table, these records require the following conditions: No number "003" of the course's student number, 2, The average grade of the class; Insert T_score Select Sid, ' 002 ', (select AVG (grade) from T_score where cid = ' 002 ') From T_student Where Sid is not in (the Select SID from T_score WHERE cid = ' 002 '); 17, according to the average score from high to low display all students "database", "Enterprise Management", "English" the course results, as show
Description: A chat record is used to explain the numbering methods and misunderstandings in real life: Let me tell you about my situation. It seems that the employee No. 03-0756-004-1JF indicates: 03 indicates production in 03 years, 0756 indicates Contract No., 004 indicates the number of the other party's organization, 1 indicates the number of the contract, and JF indicates the workshop. Do you think th
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