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C Programming language Exercises 1-10

replaced immediately, and the input is not copied to the output program. /*while ((c = getch ())! =) {if (c = = ' \ t ') printf ("\\t"); else if (c = = ' \b ') printf ("\\b"); else if (c = = ' \ \ ') printf ("\\\\"); else Putchar (c); }*/ //Getch (); //prevent the console from flashing through, you need to accept any characters after you close the console. //return 0; //returns a shape to the execution environment, and 0 represents a successful execution. //This topi

C Programming language Exercises 1-11

Practice 1-11 How are you going to test the word count program? If there is some kind of error in the program, what kind of input is most likely to find such errors?The code is as follows:#include //contains information about the standard library. #defineIn 1/* within the word */#defineOut 0/* outside the word */intMainvoid)//defines a function named Main, which does not accept parameter values. {printf ("====== counter Program ======\n"); intC, NL, NW, NC, State; State=Out ; NL= NW = NC =0; wh

Concurrent Programming-Unit exercises

to process asynchronously.Service side:ImportSocketserverclassHandler (socketserver. Baserequesthandler):defhandle (self):Print('New Connection:', self.client_address) whileTrue:Try: Data= SELF.REQUEST.RECV (1024) if notData Break Print('Client data:', Data.decode ()) Self.request.send (Data.upper () )exceptException as E:Print(e) Breakif __name__=="__main__": Server= Socketserver. Threadingtcpserver (('127.0.0.1', 8082), Handler) Server.serve_forever () client im

Linux C Programming series exercises system call file IO, memory ing program write ls program, the system calls ls

Linux C Programming series exercises system call file IO, memory ing program write ls program, the system calls ls Click Connect to enter the article 1.1Linux System Call exercise 1.2 simulate Linux ls program to display the tree directory 1.3 Memory sharing for simple data sharing Linux C development is not a matter of two or three days. You need to start from the basics and write a blog to record

Modern software engineering exercises and discussions Chapter 4 paired Programming

in daily life and do your best to help others. I hope that my own actions will be recognized and appreciated by others. Enfj Enthusiastic, considerate for others, easy to sense, and responsible. Focus on others' feelings, needs, and motivations. Be good at discovering the potential of others and hope to help them achieve it. Can become a catalyst for personal or group growth and progress. Loyal, will actively respond to praise and criticism. Friendly and social networking. Helping others

Geek Programming Exercises--zigzag matrices

one square.If the element in the two-dimensional array m[i][j] coordinates i is odd, and j=0 or j=7, then the Traverse path in the matrix is moving vertically down one grid.Code 2#include #include #include using namespace STD;intMain () {intNCin>> N; vectorint>VEC (N*n);intx=0, y=0; for(inti =0; i for(intj =0; J //boundary steering divided into odd and even two cases //Odd cases are divided into upper and lower triangles for processing ifN2) {//Upper triangle

First-time programming exercises

=POINT2+POINT4;cout}Else{POINT1=POINT1+POINT4;POINT2=POINT2+POINT4;POINT3=POINT3+POINT4;cout}}else if (ast4[0]== ' R ' ast4[1]== ' o ' ast4[2]== ' t ' ast4[3]== ' a ' ast4[4]== ' t ' ast4[5]== ' E ' ast4[6]==0){cin>>ast5;cin>>avg;Deg=avg/180*pi;Rot (0,0) =cos (deg);Rot (0,1) =sin (deg);Rot (1,0) =-sin (deg);Rot (=cos) (deg);if (n==1){Point1=point1*rot;cout}else if (n==2){Point1=point1*rot;Point2=point2*rot;cout}Else{Point1=point1*rot;Point2=point2*rot;Point3=point3*rot;cout} }Else{cout}return 0;

Geek programming Exercises-the longest same substring

TopicsEnter a line of string to find the same and longest string that appears, outputting it and the position of the first character.InputyyabcdabjcabcegOutputabc3parsingFirst declare that if the string is aaaaaa, the answer should be aaaaa. Two equal-length substrings can have some overlapping characters.Take Abcab as an example to analyze the following:First look for substrings of length 4, only ABCA and Bcab, and then see if the two substrings have other identical substrings. Some words direc

Chapter III Programming Exercises 3.1

Packageexercise3;ImportJava.util.Scanner; Public classMain1 { Public Static voidMain (string[] args) {Scanner input=NewScanner (system.in); DoubleA =input.nextdouble (); Doubleb =input.nextdouble (); Doublec =input.nextdouble (); DoublePanbieshi = b*b-4*a*C; if(Panbieshi ) {System.out.println ("No value"); } Else if(Panbieshi = = 0) { DoubleR1 =-b/(a); SYSTEM.OUT.PRINTLN (R1); }Else{ DoubleR1 = (-B + math.pow (Panbieshi, 0.5))/(2 *a); Doubler2 = (-b-ma

Ka recursive programming exercises part2| the positive sequence output, arithmetic progression and

1#include 2 voidPP (intN)3 {4 if(n==0)return;5PP (n/Ten);6printf"%d", n%Ten);7 }8 voidNP (intN)9 {Ten if(n==0)return; Oneprintf"%d", n%Ten); APP (n/Ten); - } - intAd (intN) the { - if(n==0)return 0; - if(n==1)return 1; - returnAd (n1)+N; + } - intMain () + { A intN; atscanf"%d",n); -printf"%d\n", Ad (n)); - PP (n); -printf"\ n"); - NP (n); - return 0; in}PP is the positive sequence, NP is reverse order, ad is a series and.The difference between PP and NP is that, as t

C and Pointers chapter two programming exercises

character constant. Intmain () {inti=0;charstr[1000] ={0};intcount=0; printf ("Please enter: \ n"); NBSP;NBSP;NBSP;NBSP;SCANF ("%s", str);while (Str[i] != ' \ n ') {if (str[i]== ' {') { count++;}if ( str[i]== '} ') (count==0) { count--; break;}if ((str[i) == '} ') (count!=0)) { count--;} i++;}if (count==0) {printf ("All curly braces appear in pairs \ \");} else{printf ("Curly braces do not appear in pairs \ \"); }system ("pause"); return0;}This article is from the "Sean" blog, so be sure to

Sixth Chapter programming Exercises

First question1#include 2#include 3 using namespacestd;4 intMain ()5 {6 Chararr[ the];7 Charch;8Cin.getline (arr, the);9 intI=0;Tench=arr[0]; One while((ch!='@') (i the)) A { - if((ch>='a') (ch'Z')) coutChar(ToUpper (CH)); - Else if((ch>='A') (ch'Z')) coutChar(ToLower (CH)); the Elsecoutch; -i++; -Ch=Arr[i]; - } + return 0; -}Second question1#include 2#include 3 using namespacestd;4 intMain ()5 {6 Doubletemp;7 Doubledonation[Ten];8

"Programming Zhu Ji Nanxiong" (2nd edition) Chapter One ": After-school exercises

to the height of the right sub-tree. The key values can be traversed from small to large using the middle order traversal (with iterators).Refer to Cplusplus for a more detailed description of the set container.The specific code is as follows:1#include 2#include Set>3 using namespacestd;4 5 intMain ()6 {7 intMyints[] = { $, at, the, the, - };8 Setint> MySet (myints, myints +5);//Use the ' Set ' member function ' Insert ' is also OK.9 Ten Setint>::iterator ITR =Myset.begin (); One

Python core Programming The answer to the second edition of the exercises

()Choice=input ("Please choice One:")If choice==1:Sum=sum ()Print "sum is%d"%sumElif choice==2:Ave=ave ()Print "average is%f"%aveElif choice== ' x ':BreakElsePrint "Wrong choice,please choose again!"2-15#让用户输入3个数值并将分别将他们保存到3个不同的变量中, do not use a list or sorting algorithm#从小到大While True:Num1=int (raw_input ("Please input NUM1:"))Num2=int (raw_input ("Please input num2:"))Num3=int (raw_input ("Please input num3:"))If num1>num2:Tmp=num1Num1=num2Num2=tmpIf num2>num3:Tmp=num2Num2=num3Num3=tmpIf num1

Python core programming Exercises-sixth chapter

: - Print "Invalid:first symbol must be alphabetic" + elifMyinputinchKW: A Print "invalid:it a python keyword" at Else: - forOthercharinchMyinput[1:]: - ifOtherchar not inchAlphas +Nums: - Print "invalid:remaining symbols must be alphanumeric" - Break - Else: in Print "Okay as an identifier"3. Sorting(a) Enter a series of numbers and arrange them from large to small.(b) Same as a, but in dictionary

Python core programming chapter sixth exercises

6-6 Creating a similar String.strip () functionMethod an inefficient method for copying and generating substring objects in large numbers def Str_strip (s):While Len (s) >=2:If s[0]== ':S=s[1:]ElseBreakWhile Len (s) >=2:If s[-1]== ':S=S[:-1]ElseBreakIf s== ' or s== ':Return 'Elsereturn s Method Two: Convert to List def Str_strip (s): if s = = "or S = =" ": Return "" #to List Elif Len (s) >=2: L = List (s) While L and l[0] = = "":

Java Basics-Programming exercises (III)

"." Location of the number - intindex = Name.lastindexof ('. ')); Wu //get the suffix of a file -String prefix =name.substring (index); About $ //The judgment must contain the "." Number, and cannot appear in the first place, with the suffix named "java" - if(Index! =-1 Index! = 0 prefix.equals (". Java")) { - - return1; A } + } the return-1; - $}Operation Result:This is in accordance wi

Java Programming Ideas Fourth Edition Chapter two answers to the exercises

table is not used at all. Compile with Javac, and then run it in Java. If you're using a different development environment than the JDK, learn how to compile and run it in your environment Public class javathinking { publicstaticvoid main (string[] args) { System.out.println ("Hello,world");} }Exercise 3: Find the code snippet that contains the atypename, rewrite it as a complete program, and then compile, runclass atypename{ public atypename () { System.out.println

android--Multithreaded Programming Exercises

(inti=0;i) the { - if(i%2==0) in { theC2= ""; the } About Else the { theC2= "Shanghai"; the } +Runonuithread (NewRunnable () { - @Override the Public voidrun () {Bayi Tvw2.settext (C2); the } the }); - //Pause - Try { theThread.Sleep ((int) (Math.random (

Python Core Programming Second Edition second chapter exercises

2.12.32.42.52.62.72.82.92.102.11deftest_sum (): Tup=("1","2","3","6","5") Sum=0 forIinchTup:sum=float (i) +sumreturnsumdeftest11 (): whiletrue:string=raw_input (">>") ifstring=="1": Sum=test_sum ()Print "sum:", Sumelifstring=="2": Sum=test_sum () Avg=sum/5Print"avg:", Avgelifstring=="x": Exit ()Else: Print"Please enter 1 or 2 or x"test11 ()2.12-2.132.15B:deftest15 (): Num1=raw_input ("First num:") num2=raw_input ("Second num:") num3=raw_input ("Third num:") NUM1=float (NUM1) nu

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