Two methods are used to determine whether a vertex is in any polygon.Import
Determines whether the touch point is inside a polygon.Method 1. Mathematical Methods
The advantage of this method is that any platform can be used, not only for AndroidAlgorithm:
Solve the intersection of the horizontal line and each side of the polygon through this point. If the intersection of one side is odd, it is true.
Okay, we actually need to look at the intersection o
Maximum Distance between convex polygon
Given two Convex PolygonPAndQTo find the point (P,Q)(PBelongPAndQBelongQ) To maximize the distance between them.
Intuitively, these points cannot belong to the interior of their respective polygon. This condition is actually very similar to the diameter problem:
Two convex polygonPAndQThe maximum distance is determined by the pair of distance points between polyg
Good Harvest: Line Segments and straight lines are more skillful, and some details are also improved.
It gives you a polygon, a straight line. Note that it is a straight line that determines the sum of the length of this line inside the polygon.
It is clear that all the intersections are sorted in one direction. The line segments between two adjacent points must be either within the
Link: http://poj.org/problem? Id = 1654Area
Time limit:1000 ms
Memory limit:10000 K
Total submissions:14952
Accepted:4189
DescriptionYou are going to compute the area of a special kind of polygon. one vertex of the polygon is the origin of the orthogonal coordinate system. from this vertex, you may go step by step to the following vertexes of the
Reprinted please indicate the source: http://blog.csdn.net/u012860063
Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1115
Lifting the stone
Problem descriptionthere are eclipsecret openings in the floor which are covered by a big heavy stone. when the stone is lifted up, a special mechanic detects this and activates initialize ONED arrows that are shot near the opening. the only possibility is to lift the stone very slowly and carefully. the ACM team must connect a rope to the
Document directory
Common polygon operations
OpenGL template test implementation
Implementation under the glut framework:
Reference
Common Operations on Polygon: Region operations in the android API sample are as follows: This article implements these polygon operations based on OpenGL's stenric buffer. Test Implementation of OpenGL templates: for example,
/***************************************: A polygon has n vertices. Input m straight lines and output their length in the polygon respectively. The boundary is also calculated as an algorithm: obtain all the intersections between a straight line and a polygon. After sorting, determine whether each line segment is within the p
Question: give you some polygon points to determine the intersection between each polygon and those polygon. The numbers are output in Lexicographic Order.
Idea: enumerate each side of each polygon to see if there is any intersection. The intersection here includes the endpoint. The key is to find the other two points
Lifting the stone
Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 5432 accepted submission (s): 2273
Problem descriptionthere are eclipsecret openings in the floor which are covered by a big heavy stone. when the stone is lifted up, a special mechanic detects this and activates initialize ONED arrows that are shot near the opening. the only possibility is to lift the stone very slowly and carefully. the ACM team must connect a rope to the st
Lifting the Stone (calculate the center of gravity of any polygon)Lifting the StoneTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission (s): 5432 Accepted Submission (s): 2273Problem DescriptionThere are eclipsecret openings in the floor which are covered by a big heavy stone. when the stone is lifted up, a special mechanic detects this and activates initialize ONED arrows that are shot near the opening. the
The main idea: start with the origin and then add an x, Y value each time, find out how many points at the end of the polygon edge, how many internal points, polygon area is how much.Analysis:1, with the lattice point as the vertex of the line segment, the number of points covered is gcd (Dx,dy), wherein, dxdy respectively for the segment of the horizontal and vertical points accounted for. If DX or dy is 0
http://acm.hdu.edu.cn/showproblem.php?pid=2036Reform Spring breeze blowing everywhereTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 22973 Accepted Submission (s): 11889Problem Description "Reform spring breeze blowing everywhere,no AC okay;I really can't go back to my hometownThere is another acre of land.Thank you! (band playing) "Saying that some students are very good mentality, every day to know the game, the exam is so simple topic, but a
Topic Links:Test instructionsGiven n points, a polygon of n points (which can be concave polygons, but n points must be all on a polygon)In all polygons that can consist of n pointsThe perimeter of the polygon with the smallest area-the minimum perimeter.Ideas:First we select a fixed point, then the next number of a permutation, there is (n-1)! permutations.This
To give you illustrator software users to detailed analysis to share the design cool fashion polygon background of the drawing tutorial.
Tutorial Sharing:
First open the illustrator, draw a square on the artboard, then select the Pen tool, randomly draw the curve, through the square.
You can turn on the smart Guides (ctrl+u) so that you can snap to existing points and continue to draw some of these lines.
C
To give you illustrator software users to detailed analysis to share the creation of polygonal paper effect of ice cream painting system tutorial.
Tutorial Sharing:
The points we will be learning in this tutorial are:
Application of BLOB Brush tool
Polygon Construction
The use of textures
Gradient fill
One, hand-painted modeling
The so-called hand-painted modeling, in fact, is j
First, with transform panel
We take positive Pentagon as an example
1, create a new file, in the scene to draw a straight line, press F8 into the film, the center as the upper left corner, as shown in Figure 1
Figure 1: The center is set in the upper left corner
2, select the line, press Ctrl+t to pull out the transform panel, and in the Rotate box to enter 72 (360/5), the angle of calculation is 360 degrees divided by the number of edges. As shown in Figure 2
Figure 2:transform Panel
3, press
*************************************** Reprint Please specify the Source: Http://blog.csdn.net/lttree ********************************************Chapter Two: Dynamic programming> Optimal triangulation Algorithm Description:? Polygon: A piecewise linear closed curve on a plane. which consists of a series of straight line segments.? A convex polygon is usually represented by a counter-clockwise sequence of
Polygon
Time Limit: 1000MS
Memory Limit: 10000K
Total Submissions:6633
Accepted: 2834
DescriptionPolygon is a game for one player this starts on a Polygon with N vertices, like the one in Figure 1, where n=4. Each vertex are labelled with a integer and each edge are labelled with either the symbol + (addition) or the symbol * (pro Duct). The ed
Objective: To specify a polygon (which may result in self-intersection) of any point string sequence, and determine the direction of the storage sequence of its points.
Note: the end point of the input polygon point string is the same as the first point, that is, one more point is saved, and the first point is saved twice.
Algorithm idea:
(1) determine the number of po
Codeforces -- Sort ent Berland Circus (minimum polygon determined by three points)
Specified ent Berland Circus
Time Limit:2000 MS
Memory Limit:65536KB
64bit IO Format:% I64d % I64u Submit Status Appoint description:
System Crawler)
Description
Nowadays all circuses in Berland have a round arena with diameter 13 meters, but in the past things were different.
In your ent Berland arenas in circuses were shaped as a regular (equiangular)
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