Polygon Mesh Property MapPre-stated:This view involves the use of the path class, if you are unfamiliar with the path class, you can see http://blog.sina.com.cn/s/blog_4d9c3fec0102vyhs.html, this article is easy to understandThe view also involves mathematical cos and sin, which is the basic knowledge of some circles, and if not, please fill in high school knowledge.:Step One: Analyze variable information//-------------we have to give the analog data-
Four, boundary sign filling algorithm
In the raster display plane, the polygon is closed, it is a closed area surrounded by a certain boundary color, the filling is carried out by line, that is, the polygon is intersecting with the scan line, and is filled between the intersection pairs. The boundary flag filling algorithm is used to fill the boundary or boundary color as a symbol when the line-by-row proc
Description
A rectangular polygon is a polygon whose edges are all parallel to the coordinate. The polygon must have a single, non-intersecting boundary. No two adjacent sides must be parallel.
Johnny has several sticks of various lengths. He would like to construct a rectangular polygon. It planning to use sticks as h
We will give you a detailed analysis of photoshop software users and share with you how to create a shoe poster with the design ink splash effect.Tutorial sharing:1. Create backgroundStep 1Create a new canvas in Photoshop and set the size to 960 pixels * 638 pixels. Select the paint bucket tool and set the color to dark blue # 1f222a for filling.Copy and paste the watercolor material into the canvas, and press Ctrl + T to adjust the size of the canvas
To give you illustrator software users to detailed analysis to share the design of the happy heartily theme poster Painting system Tutorial.
Tutorial Sharing:
1, select the "File/new" menu, open the "new" or CTRL + + dialog box, the name is: Children's Day, Width: 210mm, Height: 297mm, "mode" for CMYK color documents, click OK button, as shown in Figure 1.
Figure 1
2. Select the Rectangle tool in the toolbo
Just change the parameters to draw the polygon you want, the code is simple! Have to marvel at the power of canvas!Code to serve.DOCTYPE HTML>HTML>Head>MetaCharSet= "gb2312">title>Drawingtitle>Head>Body> CanvasID= "MyCanvas"width= ' $ 'Height= ' $ '>Canvas Draw Line TipsCanvas>Script> varMyCanvas=document.getElementById ("MyCanvas"); varContext=Mycanvas.getcontext ("2d"); functionDrawPath (x, y, N, r) {varI,ang; Ang=Math.PI*2/N//Angle of rotationC
Usually when you slice out the output of the page, generally use the common slicing tool for output. But if you encounter a lot of navigation, slicing overlap, with the general method can not be processed, then the advantages of the variable slicing tools appear, the following I will elaborate on the use of variable slicing tools!
1. Open a good navigation picture, in the first frame to do the general state graphics, in the second frame, do the button over state graphics, as shown:
2. Go bac
I have previously written an article, irregular graphic UV mapping, (http://blog.csdn.net/itolfn/article/details/17240131) used triangulation algorithm, but the algorithm is not complete, There is one rule: optimality: the diagonal of a convex quadrilateral formed by any two adjacent triangles if interchangeable, the smallest angle in the six inner corners of two triangles does not become larger. is to take four of the maximum triangular angle of the triangle to join the diagonal, grouped two tr
Good Harvest: Line Segments and straight lines are more skillful, and some details are also improved.
It gives you a polygon, a straight line. Note that it is a straight line that determines the sum of the length of this line inside the polygon.
It is clear that all the intersections are sorted in one direction. The line segments between two adjacent points must be either within the
Link: http://poj.org/problem? Id = 1654Area
Time limit:1000 ms
Memory limit:10000 K
Total submissions:14952
Accepted:4189
DescriptionYou are going to compute the area of a special kind of polygon. one vertex of the polygon is the origin of the orthogonal coordinate system. from this vertex, you may go step by step to the following vertexes of the
Reprinted please indicate the source: http://blog.csdn.net/u012860063
Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1115
Lifting the stone
Problem descriptionthere are eclipsecret openings in the floor which are covered by a big heavy stone. when the stone is lifted up, a special mechanic detects this and activates initialize ONED arrows that are shot near the opening. the only possibility is to lift the stone very slowly and carefully. the ACM team must connect a rope to the
Document directory
Common polygon operations
OpenGL template test implementation
Implementation under the glut framework:
Reference
Common Operations on Polygon: Region operations in the android API sample are as follows: This article implements these polygon operations based on OpenGL's stenric buffer. Test Implementation of OpenGL templates: for example,
/***************************************: A polygon has n vertices. Input m straight lines and output their length in the polygon respectively. The boundary is also calculated as an algorithm: obtain all the intersections between a straight line and a polygon. After sorting, determine whether each line segment is within the p
Question: give you some polygon points to determine the intersection between each polygon and those polygon. The numbers are output in Lexicographic Order.
Idea: enumerate each side of each polygon to see if there is any intersection. The intersection here includes the endpoint. The key is to find the other two points
Lifting the stone
Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 5432 accepted submission (s): 2273
Problem descriptionthere are eclipsecret openings in the floor which are covered by a big heavy stone. when the stone is lifted up, a special mechanic detects this and activates initialize ONED arrows that are shot near the opening. the only possibility is to lift the stone very slowly and carefully. the ACM team must connect a rope to the st
Lifting the Stone (calculate the center of gravity of any polygon)Lifting the StoneTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission (s): 5432 Accepted Submission (s): 2273Problem DescriptionThere are eclipsecret openings in the floor which are covered by a big heavy stone. when the stone is lifted up, a special mechanic detects this and activates initialize ONED arrows that are shot near the opening. the
The main idea: start with the origin and then add an x, Y value each time, find out how many points at the end of the polygon edge, how many internal points, polygon area is how much.Analysis:1, with the lattice point as the vertex of the line segment, the number of points covered is gcd (Dx,dy), wherein, dxdy respectively for the segment of the horizontal and vertical points accounted for. If DX or dy is 0
http://acm.hdu.edu.cn/showproblem.php?pid=2036Reform Spring breeze blowing everywhereTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 22973 Accepted Submission (s): 11889Problem Description "Reform spring breeze blowing everywhere,no AC okay;I really can't go back to my hometownThere is another acre of land.Thank you! (band playing) "Saying that some students are very good mentality, every day to know the game, the exam is so simple topic, but a
Topic Links:Test instructionsGiven n points, a polygon of n points (which can be concave polygons, but n points must be all on a polygon)In all polygons that can consist of n pointsThe perimeter of the polygon with the smallest area-the minimum perimeter.Ideas:First we select a fixed point, then the next number of a permutation, there is (n-1)! permutations.This
To give you illustrator software users to detailed analysis to share the design cool fashion polygon background of the drawing tutorial.
Tutorial Sharing:
First open the illustrator, draw a square on the artboard, then select the Pen tool, randomly draw the curve, through the square.
You can turn on the smart Guides (ctrl+u) so that you can snap to existing points and continue to draw some of these lines.
C
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