polygon poster

Can someone tell me why the output of sum_area is always 0 (the polygon center of gravity) and the sum_area center of gravity?Polygon Center of Gravity Problem time limit: 3000 MS | memory limit: 65535 KB difficulty: 5 Description On a polygon, n points are obtained. The n points are given in order and adjacent points are connected in a straight line

After judging whether a coordinate point is within a polygon, there is another requirement that when I have this coordinate point outside the polygon, I need to calculate whether the distance from the polygon to the polygonal is calculated by the latitude and longitude coordinates of the two locations in the range of the coordinates (C # version).Turn from: 78423

should contain exactly and numbers separated by one space. These numbers is the coordinates of the centre of gravity. Round the coordinates to the nearest number with exactly, digits after the decimal point (0.005 rounds up to 0.01). Note that the centre of gravity may outside the polygon, if it shape is not convex. If There is such a case in the input data, print the centre anyway.Sample Input245 00 5-5 00-541 111 111 111 11Sample Output0.00 0.006.0

Title Link: http://poj.org/problem?id=1179Time limit:1000ms Memory limit:10000kDescriptionPolygon is a game for one player this starts on a Polygon with N vertices, like the one in Figure 1, where n=4. Each vertex are labelled with a integer and each edge are labelled with either the symbol + (addition) or the symbol * (pro Duct). The edges is numbered from 1 to N. On the first move, one of the edges is removed. Subsequent moves involve the foll

"Dichotomy + Computational Geometry" HDU 4033 Regular polygon Topic Link: hdu 4033 Regular Polygon TopicThe edge length of the polygon is known by the distance from one of the inner points in the regular polygon to all vertices.Binary problems generally exist with an unknown amount of equation (equation relationship),

// Declaration: polypolygon (DC: HDC; {Device environment handle} var points; {point array} var npoints; {array, the array element is the number of vertices of each polygon} P4: INTEGER {Number of polygon, that is, the number of npoints elements}): bool; // Example: Procedure tform1.formpaint (Sender: tobject); var PS: array [0 .. 9] of tpoint; PN: array [0 .. 1] of integer; begin {

Inside a polygon, the distance between the point and each point of the polygon is given to determine the side length of the polygon. Starting from the definition of a positive polygon, each side is equal to a polygon with equal angles. The

1. theoretical support: If a Ray from the point to be judged has an odd number of focal points with the polygon, The point is within the polygon; otherwise, the point is outside the polygon. (Rays cannot interwork with polygon vertices) 2. Programming ideas: The idea of this program is to make a horizontal Ray (paralle

Polygon center of gravity, center of gravityPolygon Center of Gravity Problem time limit: 3000 MS | memory limit: 65535 KB difficulty: 5 Description On a polygon, n points are obtained. The n points are given in order and adjacent points are connected in a straight line (the first and last connections ), all line segments do not overlap with other line segments, but can overlap. You can obtain

Description Returns the coordinates of each point of a convex polygon for its area. Input Multiple Input groups. The first positive integer t represents the number of groups. A positive integer N (1 ≤ n ≤ 1000) In the first line of each group indicates the number of vertices in the polygon, In the next n + 1 line, each line has two int

Ke mi friends to collect the tutorial! Today, a Kobe Bryant flying shooting poster tutorial, the effect of cool, meticulous process, the operation of the interface of Chinese, to ensure that beginners can easily learn, the weekend to one. Let's start my drawing process by building a new canvas that matches the size of my display. Create a new layer to fill the gradient. I have a picture of the clouds from Baidu right.

This is a very cool jQuery and CSS3 imitation AppleTV poster background visual effect. When the Visual Difference effect moves the mouse around the screen, the various elements in the poster move at different speeds to form the Visual Difference effect, and also has some special effects of streamer. The results are as follows: View demo download source code HTML Structure Apple TV is a HDTV set-top box la

This is a very cool jQuery and CSS3 imitation AppleTV poster background visual effect. When the visual difference effect moves the mouse around the screen, the various elements in the poster move at different speeds to form the visual difference effect, and also has some special effects of streamer. The results are as follows: View demo download source code HTML structure Apple TV is a HDTV set-top box la

This tutorial is intended to introduce PS simple production pretty popular low polygon background method to PHP chinnet friends. the polygon background produced in this tutorial is very beautiful and difficult, it is very suitable for beginners to learn. we recommend you to the PHP Chinese web. if you like it, you can come and create it. in this tutorial, I would like to introduce PS to my friends in the PH

Meaning of the title:Given an n just n vertex. This is achieved by the N-point coordinate polygon.Http://acm.hdu.edu.cn/showproblem.php?pid=1115Topic Analysis:/*** Source: http://blog.csdn.net/ysc504/article/details/8812339*① quality centered on vertices* N Vertex coordinates are (xi,yi). The mass is MI, then the center of gravity* X =∑ (XIXMI)/∑mi* Y =∑ (YIXMI)/∑mi* in particular. If the quality of each point is the same. The* X =∑xi/n* Y =∑yi/n*② Uniform mass Distribution* in particular. Unifo

2618: [Cqoi2006] Convex polygon Description counter-clockwise gives the vertex coordinates of n convex polygons, and asks them to cross the area. For example, when n=2, two convex polygons such as: The area of the intersecting portion is 5.233.Input The first line has an integer n, which represents the number of convex polygons, and the following describes each polygon in turn. The first line of th

The area of a triangle can be obtained using the cross product of the vector; For a triangle, the area is equal to [(x2-X1) * (Y3-Y1)-(Y2-Y1) * (X3-X1)]/2.0. However, the area is oriented. For a polygon, we can select any point (usually 0, 0) to connect to the fixed point of the polygon, For ordered vertices, we calculate the cross product of a triangle composed of the origin point and a pair of adjacent