polygon poster

polygon area, and the result is exactly one decimal point after the decimal.The output for each instance takes up one row.Sample Input3 0 0 1 0 0 14 1 0 0 1-1 0 0-10Sample Output0.52.0Topic Analysis:Calculates the area of a freeform polygon. Tool: Vector fork multiplication. The Vector fork is twice times the direction area of the triangle. Therefore, you can select any point, such as the origin and the tw

OpenGL Vertex ArrayAlthough the example given above contains only a small number of coordinate positions, it is generally much more complex to describe a scene that contains several objects. Let's consider describing a simple, very basic object: the unit cube in Figure 3.58, which uses integer coordinates to simplify the subsequent discussion. The direct way to define vertex coordinates is to use a double subscript array, for example:Glint points [8][3] = {{0,0,0},{0,1,0},{1,0,0},{1,1,0},{0,0,1}

Solving the area (inside the plane) of any polygon and solving the area plane The calculation of the polygon in the plane, that is, the calculation of the polygon in the plane coordinate system. It is known that the coordinates of each point are sequential, clockwise or clockwise. Calculate the area based on the given coordinates. Here is a simple method to cal

Note: The article is translated from http://wgld.org/, the original author Sambonja 広 (doxas), the article if there is my additional instructions, I will add [Lufy:], in addition, The WEBGL research is not deep enough, some professional words, if the translation is wrong, you are welcome to correct. The results of this demo runincrease the number of vertex attributesLast time, we finally drew a triangle, but only a pure white polygon was drawn.This ti

= true; Flag *= Line[i-1]; if (i = = count-1) { Linelast = (pt[0].y-pt[i].y) * Px + (pt[i].x-pt[0].x) * Py + (pt[0].x-pt[i].x) * pt[i].y-(PT[0].Y-PT[I].Y) * pt[i].x; Flag *= Linelast; if (flag = 0) { if (Px Online = true; Else Online = false; } } if ((Flag { MessageBox.Show ("The isolated point is outside the polygon"); Break } else if (flag = 0 i = count-1 online = True) { MessageBox.Show ("The isolated point is on the border of the

This article describes how to make a polygon form using the making interface functions provided by Windows. The key to making a polygon form is to set the area of the polygon and change the shape of the form according to the specified area. Windows CREATEPOLYGONRGN and SETWINDOWRGN functions can solve both of these difficulties. You can set the form to a Pentag

Array Polygon Questions#include From: http://www.cnblogs.com/graphics/archive/2010/08/24/1761620.html#Array Polygon Questions

Cupid ' s Arrow Time limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 1037 accepted submission (s): 385Problem Description legend in the world there is a cupid's arrow, anyone who is shot by this arrow, will deeply fall in love with the archery person.Countless people in the world have ever dreamed of this arrow. Lele, of course, is no exception. But he thought he had to learn archery before he got the arrow.Days go by, Lele's arrows are getting stro

Description On a two-dimensional plane, give for you n integer points. Your task is to figure out how many different regular polygon this can make. Input The input file consists of several test cases. Each case the the "a" is a numbers n (n Output For each case, the output a number means how many different regular polygon this points can make. Sample Input 4 0 0 0 1 1 0 1 1 6 0 0 0 1 1 0 1 1 2 0 2- 1 Sa

For your illustrator software users to detailed analysis to share the production of stylish cool polygon background tutorial. Tutorial Sharing: Well, the above information is small set for you illustrator this software users bring the detailed production of stylish cool polygon background of the tutorial to share the full content of the You see the users here, small knittin

To give you illustrator software users to detailed analysis to share the design cool fashion of the polygon background of the production tutorial. Tutorial Sharing: Well, the above information is small knitting to you illustrator of this software users to bring the detailed design of the cool fashion of the polygon background of the production of a tutorial to analyze the e

If you want to reduce the running time, you can try: In the plane, if a convex polygon has inscribed circle, then the relationship between the area S, Perimeter C and inscribed circle radius r of the convex polygon is S=CR/2 #if 1 #include

Http://codeforces.com/problemset/problem/755/DEach time a new diagonal line is drawn, consider crossing a few of the existing diagonal lines.You can use the tree array interval to modify the point query to maintain the vertices of the polygon. Each time the answer increases the left end of the new diagonal in how many intervals + the right end point within the number of intervals + 1, each time the new picture of the diagonal coverage of the smaller i

Given a convex polygon with n vertices (numbered 1 to n clockwise), the weights of each vertex are known. Ask how to divide this convex polygon into N-2 disjoint triangles, making the sum of the weights of the vertices of these triangles a minimum. F[I][J] represents the smallest weight from the numbered I to J (clockwise) after the successive vertices are divided; then the problem solved becomes f[1][n]

Freeform Polygon Intersection: Private voidBtnpolygon_click (Objectsender, EventArgs e) { Double[] Xs =New Double[] { -,260, the, -, -, the, the, the, -, -, -, -, -,260 }; Double[] Ys =New Double[] { $,260, the, Max, the, About, $,260 }; intm = xs.length/2; varcoords =NewCoordinate[m]; varCoordscheck =NewCoordinate[m]; for(vari =0; I 2; i++) { varx = Xs[i *2]; vary = xs[i *2+1]; Coords[i]=Newcoordinate (x, y); Coo

1. Create a polygon based on 4 pointsCreate a graph based on 4 points , order clockwise1234public static Ipolygon createpolygonby4points (IPoint pnt1, IPoint pnt2, IPoint pnt3, IPoint pnt4){Ipointcollection Ppntcol = new Polygonclass ();Object missing = Type.Missing; Add ClockwisePpntcol.addpoint (pnt1, ref missing, ref missing);Ppntcol.addpoint (Pnt2, ref missing, ref missing);Ppntcol.addpoint (PNT3, ref missing, ref missing);Ppntcol.addpoint (PNT4,

Test instructions: A bar of length n, randomly select K position to cut it into k+1 section, ask this k+1 section can make up the probability of the polygon k+1 edge . Analysis: This problem, obviously and N is not any relationship, because no matter how much n is how many segments can be, only with the number of segments of the cut. Then we have to convert it, can't do it directly, because it's not good to do.Convert to a circle to the election m+1 p

Using Dotspatial.controls;Using Dotspatial.data;Using DotSpatial.Data.Forms;Using DotSpatial.Plugins.Measure;Using Dotspatial.symbology;Using Dotspatial.topology;Using DotSpatial.Topology.Algorithm;Using point = DotSpatial.Topology.Point;Using Pointshape = DotSpatial.Symbology.PointShape;Shapefiles s = new Shapefile ();Polygon FeaturesFeatureSet fs = new FeatureSet (Featuretype.polygon);Add FieldFs. DATATABLE.COLUMNS.ADD (New DataColumn ("ID", typeof

When creating a polygon div, the younger brother encountered a problem: he wanted to generate a polygon div. the front div protruding a triangle, and the back div was concave into a triangle, embed and overlap the protruding and concave parts of the two divs. how can this problem be achieved ?, It is implemented by image spoofing. PHP self-painting is not beautiful. canvas painting is not compatible. it is

After a simple polygon is generated, it is sometimes necessary to judge the concave and convex of each vertex of the polygon. Calculate the two vectors of the vertex to be processed and the adjacent vertex, and then calculate the cross multiplication of the two vectors. Based on the positive and negative values of the obtained result, we can judge the concave and convex. If the result is negative, it is a c