pots landline

Pots Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 12022 Accepted: 5078 Special Judge DescriptionYou are given the pots of the volume of A and B liters respectively. The following operations can be performed: Fill (i) Fill the pot i (1≤ i ≤ 2) from the tap; DROP (i) empty the pot I to the drain; Pour (i,

I-pots Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64D %i64u Submit Status Description You are given the pots of the volume of A and B liters respectively. The following operations can be Performed:fill (i) FILL the pot i (1≤ i ≤ 2) from the tap; DROP (i) empty the pot I to the drain; Pour (i,j) pour from pot i to pot J; After this operation either the pot J was full (and there may be some wate

H-pots Time limit:1000ms Memory limit:65536kb 64bit IO format:%i64d %i64u Submit Status Practice POJ 3414 Description You are given the pots of the volume of A and B liters respectively. The following operations can be performed: Fill (i) Fill the pot I (1≤i≤2) from the tap; DROP (i) empty the pot I to the drain; Pour (i,j) pour from pot I to pot J; After this operation either the pot J was full (and

http://poj.org/problem?id=3414Record bottle status, breadth first search#include 　　POJ 3414 Pots violence, BFS difficulty: 1

); } } //DROP A 3333333333 if(now.a!=0) {Next=Now ; NEXT.A=0; next.b=now.b; if(!v[next.a][next.b]) {v[next.a][next.b]=1; Next.step=now.step+1; Next.way[next.step]=3; Que.push (next); } } //DROP B 444444444444 if(now.b!=0) {Next=Now ; NEXT.A=NOW.A; next.b=0; if(!v[next.a][next.b]) {v[next.a][next.b]=1; Next.step=now.step+1; Next.way[next.step]=4; Que.push (next); } } //pour (5555555555555) if(now.a!=0) {

Pouring Water. Give two cups A and B respectively. By connecting the water from the tap (each time it is filled with water), all the water in the cup is dumped, and the water in one cup is poured into the other three operations to make the water in one cup C. Solution: 6-entry BFs. The difficulty lies in how to save the path. #include Poj3414 pots (BFS)

Tags: poj BFS Link: poj 3414 Question: The capacity of two bottles a, B, and a target water volume C are given. You can perform the following operations on A and B: Fill (I) fills the bottle with water Drop (I) Empty the bottle I Pour (I, j) pour the water in bottle I into bottle J. After this operation, either the bottle J is filled with water or the bottle I is empty Perform at least several operations to make the water in A or B Package C and output the specific operation. Analysis: BFS can b

Link: http://poj.org/problem? Id = 3414 http://acm.hust.edu.cn/vjudge/contest/view.action? Cid = 22009 # Problem/jpots Time limit:1000 ms Memory limit:65536 K Total submissions:8253 Accepted:3499 Special Judge Description You are given two pots, having the volumeAAndBLiters respectively. The following operations can be saved med: Fill (I) fill the potI(1 ≤I≤ 2) from the tap; Drop (I) Empty the potITo the

Title Link: http://poj.org/problem?id=3414Pots Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14306 Accepted: 6033 Special Judge DescriptionYou are given the pots of the volume of A and B liters respectively. The following operations can be performed: Fill (i) Fill the pot i (1≤ i ≤ 2) from the tap; drop (i) Empty the PotNBSP; i to the drain; p

DescriptionYou are given the pots of the volume of A and B liters respectively. The following operations can be performed:Fill (i) Fill the pot I (1≤i≤2) from the tap;DROP (i) empty the pot I to the drain;Pour (i,j) pour from pot I to pot J; After this operation either the pot J was full (and there could be some water left in the pot I), or the pot I was empty (and All its contents has been moved to the pot J).Write a program to find the shortest poss

DescriptionYou are given the pots of the volume of A and B liters respectively. The following operations can be performed: Fill (i) Fill the pot i (1≤ i ≤ 2) from the tap; DROP (i) empty the pot I to the drain; Pour (i,j) pour from pot i to pot J; After this operation either the pot J was full (and there may be some water left in the pot I), or the PO T I was empty (and all its contents has been moved to the pot J). Write a progr

; Tmp.op[++tmp.step] =4;//DROP2Bayi Q.push (TMP); the } the if(P.a >0 P.B B) { - intt = min (p.a, B-p.b); - if(!vis[p.a-t][p.b+T]) { theVIS[P.A-T][P.B+T] =true;//pour1->2 theTMP = P; Tmp.a-= t; Tmp.b + = t; Tmp.op[++tmp.step] =5; the Q.push (TMP); the } - } the if(P.b >0 P.a A) { the intt = min (p.b, A-p.a); the if(!vis[p.a+t][p.b-T]) {94VIS[P.A+T][P.B-T] =true;//pour2->1 theTMP = P; Tmp.a + = t; TMP.B-=

DescriptionYou are given the pots of the volume of A and B liters respectively. The following operations can be performed: Fill (i) Fill the pot i (1≤ i ≤ 2) from the tap; DROP (i) empty the pot I to the drain; Pour (i,j) pour from pot i to pot J; After this operation either the pot J was full (and there may be some water left in the pot I), or the PO T I was empty (and all its contents has been moved to the pot J). Write a progr

Pots Time Limit: 1000MS Memory Limit: 65536K Total submissions: 19042 accepted: 8027 Special Judge DescriptionYou are are given two pots, having the volume of A and B liters respectively. The following operations can be Performed:fill (i) FILL the pot i (1≤ i ≤ 2) from the tap; DROP (i

C # Wonderful choice for Microsoft. VisualBasic My object Author: qingyueer Home page:Http://blog.csdn.net/21aspnet/Time: 2007.4.24 1. Add reference 2. reference the Microsoft. VisualBasic namespace 3. All My object applications come from the

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Title Link: http://poj.org/problem?id=3414 Idea: Very simple, is the search can, just a cup of water in the state transfer when the code is a bit less good to write. Code: #include #include #include #include #include #include #include

Cell phone:var reg=/^1[34578]\d{9}$/;if (Reg.test ("You enter the mobile number")){Alert ("Phone number entered correctly")}Else{Alert ("Phone number entered incorrectly")}Qq:var reg=/^[1-9]\d{4,11}$/;Mailbox:var reg=/^\w+@[0-9a-za-z\-]+ (\.[ a-za-z]

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This reminds me of the three Coke cans of hangdian. It seems that only the number of output times is enough, and all the paths need to be output here, in this way, BFs alone will have a lot of space redundancy in the state of retention. Therefore,