properties of rectangle

OpenglES2.0 for Android: Draw a rectangle.in the previous section we drew a triangle, and we completed the rectangle drawing on the basis of the previous section. OK, start doing it, first create a new class--square (Square.java) under the shape directory in the previous section of the project, and then define the coordinates of the four vertices of the rectangle, at which point the code is as follows (Squa

Collision Detection TechnologyIn the game, collisions are the most frequently encountered technology. Of course, many game engines have already done collision detection, and we just need to call them. This lesson is explained from the principle of collision, we have to achieve basic collision detection.Principle of rectangle detectionIn the game, whether more than one element touches together, in fact, is usually implemented with the principle of "

In the cocos2dx of the collision detection of the rectangle needs to do a collision check of the rotated rectangle, because the game does not use the box2d and other physical engine, so the obb (oriented bounding box) direction bounding box algorithm, the algorithm is based on the SAT ( Separating axis theorem) separates the Axis law.　　Separation Axis law: Two convex polygon objects, if we can find an axis,

First of all, this tutorial can only be used as a topic of discussion, the center of the discussion is caused by a problem, I hope that we can consider the same problem through a variety of angles. The questions are as follows: Question: How do you create such a rectangular frame--two rounded corners, two right angles? For example, the following effect picture shows: If you're upset about the effect above, take a look at this single effect chart: There are a lot of ways to make it, you can th

PackageCom.hanqi;//import java.util.*; Public classjuxing {//Properties Private DoubleChang//Long Private DoubleKuan//Wide Public DoubleGetchang ()//Read { returnChang; } //Write Public voidSetchang (DoubleChang) { //Add Validation if(Chang > 0) { This. Chang =Chang; } Else{System.out.println ("Invalid length value"); } } Public DoubleGetkuan () {returnKuan;

Largest rectangle in a Histogram Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others) Total submission (s): 7496 accepted submission (s): 2106 problem descriptiona histogram is a polygon composed of a sequence of rectangles aligned at a common base line. the rectangles have equal widths but may have different heights. for example, the figure on the left shows the histogram that consists Rectangles with the heights 2, 1, 4,

Find the largest rectangle in the column chart: Give a group of non-negative integers to represent a column chart, design an algorithm to find the largest area of the rectangle that can fit into the column chart. For example, there are two possible solutions for the number of groups, 1 2 3 4 1, one is suitable for the rectangle within 2 3 4, and the area is 2*3;

Problem-solving ideas: Uh, is to see the purple book above the practice, a rectangle and another rectangle between the relationship between only two, (because it is not nested itself), can be nested, not nested, is a two-yuan relationship, if it can be nested, it is recorded as 1, if not nested, then recorded as 0, can be converted to the DAG ( There is a graph of the direction of the loop, that is, a point

The largest rectangle Time limit: 1.0s Memory Limit: 256.0MB Problem Descriptionn adjacent rectangles are placed on the horizontal axis, the width of each rectangle is 1, and the height of the first (1≤i≤n) rectangle is hi. These n rectangles form a histogram. For example, the height of the six

This section describes how to dynamically draw rectangular frames in Sivlerlight. This technique allows you to customize rectangular frames. The key to this technique is to use its events in a Canvas to draw a rectangle. Note that Canvas is used here because Canvas. Top and Canvas. Left are a good method for locating. When a user wants to dynamically draw a rectangle, the user presses the left mouse button

Import Java.awt.Cursor;Import Java.awt.Graphics;Import Java.awt.Graphics2D;Import Java.awt.Point;Import Java.awt.event.MouseAdapter;Import java.awt.event.MouseEvent;Import Java.awt.event.MouseMotionListener;Import Java.awt.geom.Point2D;Import Java.awt.geom.Rectangle2D;Import java.awt.geom.Rectangle2D.Double;Import java.util.ArrayList;Import javax.swing.JComponent;public class Mousecomponent extends JComponent {private static final int sidelength = 10;Private arraylistPrivate Rectangle2D current;

Largest Rectangle in a histogram http://poj.org/problem?id=2559 Time limit:1000ms Memory limit:65536k Description A histogram is a polygon composed of a sequence of rectangles aligned in a common base line. The rectangles have equal widths but may have different. For example, the "figure on" the left shows the histogram, consists of rectangles with the Heights 2, 1, 4, 5, 1, 3, 3, Measured in units where 1 is the width of the rectangles: Usual

Ar secondRect: Rectangle = new Rectangle (1, 3, 11, 13 );Why does the above code report an error? The Rectangle parameter cannot exceed two. Why? Let's talk about it.Var secondRect: Rectangle = new Rectangle (1, 3, 11, 13); no error is reported. Check whether the script

Description gives the N rectangle (1≤n≤100) and its length and width (not more than 1000), write a program to find the largest k, so that there is a K rectangle satisfies the layer contains the relationship, that is, the inner rectangle is contained by all outer rectangles. One rectangle P1 contains another