pry rescue

fix was Windows boot Ubuntu.To solve this problem, I used the method of first entering Win7, and then using "EASYBCD" to repair the MBR to solve this problem.The way to do this is simple: Start EasyBCD, select "BCD Deployment" on the left, and then select "Install Windows vista+ in MBR bootloader" on the right, which is the default first item, and finally click the "Write MBR" button.In this case, the grub repair is done directly, and Ubuntu can be booted with Windows.References:http://blog.csd

#include #includestring>#includestring.h>#include#include#include#includeusing namespacestd;intN,m,di,dj,ok,ss;Charmapp[ About][ About];intvis[ About][ About];//There should be more than one friendstructnode{intx, y; intstep; FriendBOOL operator(node A,node b) {returnA.step > B.step;//Ascending }};intdir[4][2]={{1,0},{0,1},{-1,0},{0,-1}};p riority_queuePQ;voidBFS () {node temp,next; ints,d; while(!Pq.empty ()) {Temp=Pq.top (); //coutPq.pop (); if(temp.x==ditemp.y==DJ) { } for(i

++) - { the intxx = u.x + dir[i][0]; * intyy = U.y + dir[i][1]; $ //coutPanax Notoginseng if(XX 0|| XX >= N | | yy 0|| yy >= M | | MP[XX][YY] = ='#')Continue; - if(Mp[xx][yy] = ='a')returnU.d+1; the +Node temp =Node (xx, yy, u.d); Atemp.d++; the if(Mp[xx][yy] = ='x') temp.d++; + if(Dist[xx][yy] >=temp.d) - { $ Q.push (temp); $DIST[XX][YY] =TEMP.D; - } - } the

fresh e-commerce relying on community stores, layout from the point of the formation of a more powerful sales channels, even through the southern black Sesame has not successfully entered the three-tier distribution channels of the following cities. This is also a solution to the "convenience" of this bottleneck.At least for now, the general line of Southern black Sesame has not changed and has been right, is to continue to focus on-black.Zhang Shule: zsl13973399819 book has "cross-border-the I

] = ='.') - {WuyiT.step = Temp.step +1; theMAP[T.X][T.Y] ='o'; - Q.push (t); Wu } - Else if(Map[t.x][t.y] = ='#') About { $T.step = Temp.step +2; -MAP[T.X][T.Y] ='o'; - Q.push (t); - } A Else if(Map[t.x][t.y] = ='m') + { theT.step = Temp.step +1; -MAP[T.X][T.Y] ='o'; $ Q.push (t); the } the } the } the } - return-1; in } the the intMain () A

1. Simulate the destruction of MBR boot.DD If=/dev/zero OF=/DEV/SDA bs=400 count=1This will not start the system.Put the Linux system CD and boot. Select the third rescue mode.650) this.width=650; "style=" Float:none; "title=" 1.png "src=" http://s3.51cto.com/wyfs02/M01/72/CE/ Wkiol1xtow7zjkwcaahylx8db8a072.jpg "alt=" Wkiol1xtow7zjkwcaahylx8db8a072.jpg "/>Omitted part of the unimportant, directly to the following interface.650) this.width=650; "style=

Topic linkshttp://acm.hdu.edu.cn/showproblem.php?pid=1242Water problem, BFSCode#include #include #include #include using namespace Std;int n,m,success;int Stx,sty,ex,ey;Char map[210][210];int dx[4]={0,1,0,-1};int dy[4]={-1,0,1,0};struct node{int x,y,g,cnt;};Queue void BFs () { node s,e; while (Q.size ()) Q.pop (); S.x=stx; s.y=sty; s.cnt=0; s.g=0; Q.push (s); br> while (Q.size ()) { S=q.front (); Q.pop (); if (S.x==exs.y==ey) { Success=1; printf ("%d\n", s.cnt); return; } for (int i=

=x; T2.y=y; t2.cnt=t.cnt+1; Q.push (T2); }Else if(mp[x][y]==' x ') {visit[x][y]=1; RAC T2; T2.x=x; T2.y=y; t2.cnt=t.cnt+2; Q.push (T2); }Else if(mp[x][y]==' A ') {ok=true;printf("%d\n", t.cnt+1); Break; } } } }if(!ok)printf("Poor ANGEL have to stay in the prison all his life.\n");//cannot reach}return 0;} Copyright NOTICE: This article

RescueTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 19478 Accepted Submission (s): 6939Problem DescriptionAngel was caught by the moligpy! He was Vladimir Prison by Moligpy. The prison is described as a n * M (n, M Angel ' s friends want to save Angel. Theirtask Is:approach Angel. We assume that "approach Angel" are to get tothe position where Angel stays. When there's a guard in the grid, we must Killhim (or his?) to move into the grid. We a

Topic Link: Click Open link http://acm.hdu.edu.cn/showproblem.php?pid=1242#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. HDU 1242 Rescue bfs+ Priority queue

A coma is a continual loss of consciousness. When the normal function of the human brain is seriously disturbed, people tend to fall into a state of unconsciousness, shouting or shaking can not wake up, this is a coma. Coma can be slow to form, can also happen suddenly, therefore, everyone should put health management up.There are many causes of coma, common cases are:(1) Respiratory disorders: asphyxia, carbon monoxide poisoning.(2) Circulatory disorders: severe bleeding, heart standstill, elec

], G[MAXN][MAXN], N;voidFloyd () { for(intk=1; k) { for(intI=1; i) { for(intj=1; j) { if(G[i][j] > G[i][k] +G[k][j]) {G[i][j]= G[i][k] +G[k][j]; PATH[I][J]=Path[i][k]; } } } }}voidPutpath (intStar,intEnd) { while(Star! =End) {printf ("\t%d", Star); Star=Path[star][end]; } printf ("\t%d\n", Star);}intMain () {intA; CIN>>N; for(intI=1; i) { for(intj=1; j) {Path[i][j]=J; CIN>>G[i][j]; if(G[i][j] = =-1) G[i]

integer, standing for the minimal time needed. If Such a number does no exist, you should output a line containing "Poor ANGEL have to stay in the prison all he life."Sample Input7 8#.#####.#.a#. r.#. #x ..... #.##...##...#..............Sample Output13 Authorchen, XueSourcezoj Monthly, October 2003Recommendeddy | We have carefully selected several similar problems for you:1240 1010 1072 1253 1372 Statistic |Submit |Discuss | Note You can also use DFS to do the BFS here.#include Cop

The main topic: a grid chart, some of the points above may have some kind of key. There may be gates between nodes and nodes. Some doors require specific keys to pass, and some do not. The shortest time to start from (m,n).Idea: Hierarchical graph + state compression.F[i][j][k], where I and J describe the current location. K is the current key that has been compressed (because the number of keys is CODE:#include Network Flow 24 Questions 14 Island rescue