ps month

echo Date ("Ymd", Strtotime ("Now"), "\\n"; echo Date ("Ymd", Strtotime ("1 week Monday")), "\\n"; echo Date ("Ymd", Strtotime ("1 week Sunday")), "\\n"; echo Date ("Ymd", Strtotime ("+0 Week Monday")), "\\n"; echo Date ("Ymd", Strtotime ("+0 Week Sunday")), "\\n"; echo "********* months:"; echo Date (' n '); echo "********* Week of the week:"; Echo Date ("W"); echo "********* Days of the Month:";

weeks to add information, painstakingly add data, the customer also nodded, the problem came, to the money appeared problems, customers said that the site was included in Baidu, because space is his own, no way to tamper , so the bitter wait for half a month included, the customer said no hurry, I made a fortune will not treat you, I made money you also earned, we this is a win. The implication is that I haven't made any money yet, and I've made the

Do some things from the last day of each month to on January 1, 4th day of next month: 05 0 28-31,1-4 ** ['date-d tomorrow + \ % e'-ge 1-a' date + \ % e'-le 4] do something With crontab time format introduction: F1 F2 F3 F4 F5 Program F1 indicates the minute, F2 indicates the hour, F3 indicates the day of the month, F4 indicates the

If object_id ('pubs .. tb') is not nullDrop table TBGoCreate Table TB(Noteid varchar (10 ),Saledate datetime)Insert into Tb (noteid, saledate) values ('v1 ', '2017-09-12 ')Insert into Tb (noteid, saledate) values ('v2', '2017-09-12 ')Insert into Tb (noteid, saledate) values ('v3 ', '2017-09-12 ')Insert into Tb (noteid, saledate) values ('v4 ', '2017-08-12 ')Go If object_id ('pubs .. mymonths') is not nullDrop table mymonthsGoCreate Table mymonths(Mymonths varchar (7)) Declare @ dt1 as dateti

1st day of last month 00:00:00 Select to_char (add_months (last_day (sysdate) + 1,-2), 'yyyy-mm-dd') | '00:00:00 'firstday from dual; 23:59:59 on the last day of last month (the last day of each month is the first day of next month minus one day + 23:59:59) Select to_char (add_months (last_day (sysdate),-1), 'yyyy

1 Echo Date("Ymd",Strtotime("Now")), "\ n";2 Echo Date("Ymd",Strtotime("-1 week Monday")), "\ n";3 Echo Date("Ymd",Strtotime("-1 week Sunday")), "\ n";4 Echo Date("Ymd",Strtotime("+0 Week Monday"), "\ n";5 Echo Date("Ymd",Strtotime("+0 Week Sunday"), "\ n";6 7 8 //date (' n ') months9 //date ("W") Week of the weekTen //date ("T") days of the month One A Echo' ; - Echo Date("Y-m-d h:i:s",Mktime(0, 0, 0,Date("M"),Date("D")-Date("W") +1-7,Date("Y")),

#region determines the maximum number of days per month based on month private int setdate (string time) { int intyear; int intmonth; int intday; String year = time. Substring (0,4); String month = time. Substring (4,2); Int. TryParse (year, out intyear); Int. TryParse (

/*************************************** ************************C LanguageAUTHOR: liuyongshui**************************************** ***********************//*Question 14: define a struct variable (including year, month, and day). Enter the year, month, and day to calculate and output the day of the year.*/ # Include Struct date{Int year;Int month;Int day;}; I

I used to query the database today or yesterday, for the last seven days, for the last 30 days, and for the last month, the data was directly determined through php. This is an additional step, next I will introduce an article that uses SQL statements to calculate the data statements of the current day, yesterday, last 7 days, last 30 days, this month, and last month