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Ask how to get the timestamp for the beginning and end of this week, last week, this month, and last month

How do I get the timestamp of this week, last week, this month, the beginning and the end of the month How do I get the timestamp of this week, last week, this month, the beginning and the end of the month ------to solve the idea---------------------- echo Date ("Ymd", Strtotime ("Now"), "\ n"; echo Date ("Ymd", Strtot

MySQL Query SQL code for this week, last week, this month, and last month's data

Tags: SQL data submit between interval and code curd ROMquerying data for the current week SELECT Name,submittime from the Enterprise WHERE Yearweek (Date_format (submittime, '%y-%m-%d ')) = Yearweek (now ());query last week's dataSELECT Name,submittime from the Enterprise WHERE Yearweek (Date_format (submittime, '%y-%m-%d ')) = Yearweek (now ())-1;querying data for the current monthSelect Name,submittime from Enterprise where Date_format (Submittime, '%y-%m ') =date_format (now (), '%y-%m ')que

MySQL query today, yesterday, 7 days, nearly 30 days, this month, last month data

-%m-%d ')) = Yearweek (now ());Query last week's dataSELECT Name,submittime from the Enterprise WHERE Yearweek (Date_format (submittime, '%y-%m-%d ')) = Yearweek (now ())-1;Querying data for the current monthSelect Name,submittime from Enterprise where Date_format (Submittime, '%y-%m ') =date_format (now (), '%y-%m ')Query data that is currently 6 months from nowSelect Name,submittime from Enterprise where Submittime between Date_sub (now (), Interval 6 mont

MySQL queries the SQL statements used for data from today, this week, last week, this month, last month, this quarter, last quarter, and last year.

MySQL queries the SQL statements used for data from today, this week, last week, this month, last month, this quarter, last quarter, and last year. Recently, due to work requirements, various report data needs to be collected. SQL statements are written in ultra-long and ultra-complex ways. Now, we only summarize some basic SQL statistics on time. Assume that there is an order data table: Create table 'orde

PHP obtains code for last week, this week, last month, this month, this quarter, and the last quarter.

PHP obtains code for last week, this week, last month, this month, this quarter, and the last quarter. Echo date ("Ymd", strtotime ("now"), "\ n "; Echo date ("Ymd", strtotime ("-1 week Monday"), "\ n "; Echo date ("Ymd", strtotime ("-1 week Sunday"), "\ n "; Echo date ("Ymd", strtotime ("+ 0 week Monday"), "\ n "; Echo date ("Ymd", strtotime ("+ 0 week

Obtains the last day of a month or the number of days of a month.

Obtains the last day of a month or the number of days of a month. // Obtain the last day of a month or the number of days of a month Function getMonthLastDay ($ month, $ year) { Switch ($ month)

Mysql Study Notes query data of today, yesterday, 7 days, last 30 days, this month, and last month

Paste the study notes of a webmaster. The SQL statements include the data statements of today, yesterday, 7 days, last 30 days, this month, and last month. If you need them, you can refer to them. Paste the study notes of a webmaster. The SQL statements include the data statements of today, yesterday, 7 days, last 30 days, this month, and last

PHP displays the start and end timestamps of today, this month, last month, and this year

$ T = time ();$ T1 = mktime (0, 0, 0, date ("m", $ t), date ("d", $ t), date ("Y", $ t ));$ T2 = mktime (0, 0, 0, date ("m", $ t), 1, date ("Y", $ t ));$ T3 = mktime (, 0, date ("m", $ t)-, date ("Y", $ t ));$ T4 = mktime (, 1, date ("Y", $ t ));$ E1 = mktime (, 59, date ("m", $ t), date ("d", $ t), date ("Y", $ t ));$ E2 = mktime (, 59, date ("m", $ t), date ("t"), date ("Y", $ t ));$ E3 = mktime (, 59, date ("m", $ t)-1, date ("t", $ t3), date ("Y ", $ t ));$ E4 = mktime (, 31, date ("Y", $ t

Code that displays the start, end, and timestamp of today, this month, last month, and this year

Code that displays the start, end, and timestamp of today, this month, last month, and this year /** Example of a php timestamp combination application Date: 2013/2/19 Link: http://bbs.it-home.org */ $ T = time (); $ T1 = mktime (0, 0, 0, date ("m", $ t), date ("d", $ t), date ("Y", $ t )); $ T2 = mktime (0, 0, 0, date ("m", $ t), 1,

Use the switch statement to program, determine whether a leap year is based on the years entered, and determine how many days of the month, based on the month entered

#include int main (){int year, month, flag = 0;printf ("Enter Year and month:!\n");scanf ("%d%d", year, month);If (year% of 4 ==0 year%!! = 0 | | Year% 400 ==0){flag = 1;printf ("The year you entered is a leap years \ n");}Else{Flag = 0;printf ("The age you entered is common year!! \ n ");}Switch (month){Case 1:printf

Use php to obtain the date of this week, next week, this month, next month, and this quarter (abstract)

Use php to obtain the echodate (Ymd, strtotime (now), n ;?? Echodate (Ymd, strtotime (-1 weekMonday), n ;?? Echodate (Ymd, strtotime (-1 weekSunday), obtained this week, last week, this month, last month, and this quarter date using php (abstract) Echo date ("Ymd", strtotime ("now"), "\ n ";?? Echo date ("Ymd", strtotime ("-1 week Monday"), "\ n ";?? Echo date ("Ymd", strtotime ("-1 week Sunday"), "\ n "

How do I get the timestamp of this week, last week, this month, the beginning and the end of the month

How do I get the timestamp of this week, last week, this month, the beginning and the end of the month Reply to discussion (solution) echo Date ("Ymd", Strtotime ("Now"), "\ n";echo Date ("Ymd", Strtotime ("1 week Monday")), "\ n";echo Date ("Ymd", Strtotime ("1 week Sunday")), "\ n";echo Date ("Ymd", Strtotime ("+0 Week Monday")), "\ n";echo Date ("Ymd", Strtotime ("+0 Week Sunday")), "\ n"; Date (

C # and SQL computing time: Monday, Sunday, beginning of month, end of month, beginning of the quarter, end of the quarter...

Public void GetDate (DateTime thisDate, out DateTime endWeek, out DateTime endMonth, out DateTime endQuarter, out DateTime endYear) {// DateTime dt = Convert. toDateTime (thisDate. toString ("yyyy-MM-dd"); // DateTime startWeek = dt. addDays (1-Convert. toInt32 (dt. dayOfWeek. toString ("d"); // Monday of the week // endWeek = startWeek. addDays (7 ). addSeconds (-1); // this week's Sunday // DateTime beginMonth = dt. addDays (1-dt. day); // the beginning of this

JQuery select year month Day (birthday) selector, jquery year month day

JQuery select year month Day (birthday) selector, jquery year month day In actual projects, when editing user data in the user's personal center, you may often encounter the problem of choosing the birthday option. Because the jQuery UI plug-in drop-down list is not used in my project, select + option native mode to implement selector. Accurately calculates the year, mo

PHP displays the start and end timestamps of today, this month, last month, and this year

$ T = time (); $ T1 = mktime (0, 0, 0, date ("m", $ t), date ("d", $ t), date ("Y", $ t )); $ T2 = mktime (0, 0, 0, date ("m", $ t), 1, date ("Y", $ t )); $ T3 = mktime (, 0, date ("m", $ t)-, date ("Y", $ t )); $ T4 = mktime (, 1, date ("Y", $ t )); $ E1 = mktime (, 59, date ("m", $ t), date ("d", $ t), date ("Y", $ t )); $ E2 = mktime (, 59, date ("m", $ t), date ("t"), date ("Y", $ t )); $ E3 = mktime (, 59, date ("m", $ t)-1, date ("t", $ t3), date ("Y ", $ t )); $ E4 = mktime (, 31, date ("

PHP this month, next month time

PHP month, Month time This can get the time of the day $SQLJRFW = "Select Ttotal from Total_number where to_days (tdate) = To_days (now ())"; This tdate is a Time field type of 2012-08-16 this type, then how can I get all the data for this August? Data for the last one months of August? ------Solution-------------------- Date_format (tdate, '%y-%m ') = ' year-month

Java Programming Basics-------> Enter an integer from the keyboard, representing the month, and programmatically determine which quarter of the year the specified month belongs to. If it is December, January, February, it belongs to winter.

Enter an integer from the keyboard, representing the month, and programmatically determine which quarter of the year the specified month belongs to. If it's amonth, January, February, belong to winter, if it is March, April, May, it belongs to the spring, if it is June, July,August, it belongs to the summer, if it is September, October, November, fall. When you enter a different number, you are prompted for

SQL Server gets the data for today, yesterday, this week, last week, this month, and last month in the table

Label:The DateDiff () function and the GETDATE () function are needed when you are doing SQL Server development and sometimes need to get the data in the table today, yesterday, this week, last week, this month, and last month.DATEDIFF (DatePart, StartDate, EndDate)Explanation: Calculating the time differenceDatepare Value: Year | Quarter | Month | Week | Day | Hour | Minute | Second | MillisecondStartDate:

JavaScript time operations-Year-month-day-week cascade operations, javascript year-month-day

JavaScript time operations-Year-month-day-week cascade operations, javascript year-month-day This article introduces the detailed code of the cascade date selection operation for JavaScript time operations. The details are as follows: : Code: I hope this article will help you learn about javascript programming. Articles you may be interested in: Core code of javascript interaction by year,

Php gets next week, this week, next month, this month, this quarter, next quarter

Php obtained last week, this week, last month, this month, and this quarter. Source: hudeyong926.iteye. comblog729193 lt ;? Phpechodate (Ymd, strtotime (now), n; echodate (Ymd, strtotime (-1 weekMonday), n; php get last week, this week, last month, this month, this quarter, last quarter Source: http://hudeyong926.it

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