ps4 dungeon game

-1; J >=0; j--)9DP[I][J] = max (min (dp[i][j +1], Dp[i +1][J])-dungeon[i][j],1);Ten returndp[0][0]; One } A};Of course, the 2d array can be simplified to a 1d array if we ' ve been clear of what DP is updated (in the above CO DE, dp is updated row by row from the bottom one to the top one and the all row it is updated from right to left) . The 1d version is as follows.1 classSolution {2 Public:3 intCALCULATEMINIMUMHP (vectorint>>

Letcode-Dungeon Game The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. the dungeon consists of M x N rooms laid out in a 2D grid. our valiant knight (K) was initially positioned in the top-left room and must fight his way through the

. Analysis: set a m x N's two-dimensional array f,f[i][j] represents the lowest point of the Warrior's blood trough, from the points [i][j] to the lower right. From the lower right corner, always find the upper left corner. The value in the lower-right corner of F is the value in the lower-right corner of the input array. The reason for this is to reverse the derivation ( from the lower right to the upper left corner), the local optimal solution is not necessarily the global optimal solut

https://oj.leetcode.com/problems/dungeon-game/PUBLICNBSP;CLASSNBSP;SOLUTIONNBSP;{NBSP;NBSP;NBSP;NBSP;PUBLICNBSP;INTNBSP;CALCULATEMINIMUMHP (int[][] NBSP;MAP) {//DP //Definea2DM*Narrayblood. //blood[i][j]meanstheminbloodwhen arrivethispoint.//So,the lastpoint,blood[m-1][n-1]=1 ////blood[i][j]=max (1, //Atleast1// min (blood[i][j +1]-map[i][j+1],//goright// blood[i+1][j]-map[i+1][j]) // goup// // if (map==nu

Dungeon Game-leetcode Topic: This is another topic of dynamic planning.The idea at first is to record the maximum number of lives that can be left in the (i,j) position with a two-dimensional array, but this is not true.Then came the idea of another method, starting from the lower right corner, to record the minimum health required in the (I,J) position. Then push toward the beginning.After walking to the