psr slim

Find a spanning tree to minimize the difference between the maximum edge and the minimum edge. Because the data is too small, the lower bound of the brute force enumeration is obtained. Take Min as the final result. 1 #include [Kruscal] [Minimum Spanning Tree] poj3522 slim Span

Is it because of reality that all dreams are so slim, including Love, including career. I gave up my idea of starting a business because of all objective reasons. I told myself that I found my position and I am only applicable to technology. What about love? Is it the same in reality? Can love really end like this? I keep asking myself why. Is it true that she does not take care of me? Is it all objective? No hea

Label: style blog color Io OS for SP Div on #include Uvalive 3887 slim Span

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Test instructions: Given the graph of n nodes, the spanning tree with the lowest weight of the minimum edge is calculated for the maximum edge weight value.Analysis: This is similar to the minimum spanning tree, from small to large enumeration of the left endpoint, for each left endpoint, and then enumerate the right endpoint, constantly update the minimum value. It's a very simple question.#include The code is as follows:UVa 1395 Slim Span (minimum s

margin difference, output-1 if no spanning tree exists.Ideas:Enumerate the minimum edges with the Kruskal algorithm1#include 2#include 3 using namespacestd;4 Const intN = the, M = the;5 structSIDE6 {7 int from;8 intto ;9 intdistance;Ten }edge[m]; One intCnt[n]; A BOOLcmpConstSIDE A,ConstSIDE B) { - returnA.distance b.distance; - } the intFind (intx) { - returnCNT[X] = = x?X:find (cnt[x]); - } - intMainvoid) + { - intN, M, A, B, MIN, OK; + while(SCANF ("%d%d", n, m)

Test instructionsWhat is required is the smallest of the largest and smallest edge differences in all spanning trees.Analysis:You can actually use the minimum bottleneck to generate the tree, which is the nature of the minimum spanning tree, enumerate the smallest edges of the original, and then find the maximum edge of the corresponding spanning tree.Code:　#include#include#include#include#includeUsingNamespace Std;Constint MAXN=110;Constint INF=10000000000;struct Edge{int xY;int D;booloperatorC

Main topic:Give you n points (nProblem Solving Ideas:Or according to the idea of the minimum spanning tree, start with all the edges according to the weight size, from small to large sort. Then, for an interval [l,r], each time we enumerate, if this [l,r] makes all n points connected, then the definition of their thinness is:Maximum value-the minimum value. This slender degree must be Code:# include　　　　11.2.2 example 11-2 UVA 1395 Slim Span (maximum-m

1. Title Description: Click to open the link2. How to solve the problem: In essence, the Kruskal algorithm is used to generate MST. First, according to the Benquan value from small to large order, for a continuous edge set [L,r], if the n points are all connected, there must be a slender degree not exceeding w[r]-w[l] of the spanning tree. Therefore, can be small to large enumeration L, for each L, using the Kruskal algorithm to generate a minimum spanning tree, calculate the degree of thinness,

namespacestd; - -typedefLong LongLL; the Const intINF =0x7fffffff; - Const intmaxn=10005; - intP[MAXN]; - + structedge{ - intv,u,w; + BOOL operatorConstedge RHS)Const{ A returnwRHS.W;} at }; - - - - intFindintx) {returnP[x]==x? x:p[x]=find (P[x]);} - in intMain () { - intN,m,i,j,ans; to while(SCANF ("%d%d", n,m)!=eofN) { +Vectore; - Edge ee; the for(i=0; i){ *scanf" %d%d%d",ee.v,ee.u,EE.W); $ e.push_back (EE);Panax Notoginseng } - the sort (

]); - } - voidJointintAintb) + { -A=find (a); +b=find (b); A if(a!=b) pre[a]=b; at } - - - intKruscal (inti) - { - intq=Vect[i].first; in intp=Vect[i].second; - intCnt=0; to for(intI=0; ii; + - for(intJ=i; j) the { * intA=Vect[j].first; $ intb=Vect[j].second;Panax Notoginseng if(Find (a)! =find (b)) - { thecnt++; + if(cnt==n-1)returng[a][b]-G[q][p]; A Joint (A, b); the } + } - returnINF; $ } $ - intcal

Few points, sort by edge weights, enumerate enumerations L and R, check connectivity. Once connected, update the answer.Judge even General can O (1), before I was O (n) sentenced, previously written over, and later wrote T ... #include using namespacestd;Const intMAXN =101;Const intMaxe = maxn*maxn>>1;intn,m;intU[maxe],v[maxe],w[maxe];intPa[maxn];inlineBOOLcmpintAintb) {returnw[a]w[b];}intR[maxe];inlinevoidIdxsort () { for(inti =0; I i; Sort (R,r+m,cmp);}intFind (intx) {returnx==pa[x]?x:pa[x]=Fi

Topic Link http://poj.org/problem?id=3522kruskal+ and check the collection, attention to special cases such as 1, 0, 0, 1,1#include 2#include 3#include 4#include 5 using namespacestd;6 #defineMAXN 50057 structedge{8 intU,v,cost;9 };Ten intCompConstedge E1,ConstedgeE2) { One returne1.costE2.cost; A } - Edge ES[MAXN]; - intv,e; the intPAR[MAXN],RANK[MAXN]; - voidinit () { - for(intI=1; i){ -par[i]=i; + } - } + intFindintx) { A if(par[x]==x)returnx; at returnpar[x]=find (par[x]);

The problem with UVA is to make people bright, different from the naked tree water problem, the problem is slightly changed, not to seek the smallest spanning tree, but to find the most slender spanning tree.Because there are many spanning trees, the difference between the maximum and minimum edges of each spanning tree is uncertain. So you can only enumerate all spanning trees.Applying the minimum spanning tree template, we can enumerate the start position of the spanning tree, then push the en

POJ 3522 Slim Span Given an undirected weighted graphG, You shoshould find one of spanning trees specified as follows. The graphGIs an ordered pair (V,E), WhereVIs a set of vertices {V1,V2 ,...,VN} andEIs a set of undirected edges {E1,E2 ,...,EM}. Each edgeEEHas its weightW(E). A spanning treeTIs a tree (a connected subgraph without cycles) which connects allNVerticesN-1 edges. The slimness of a spanning treeTIs defined as the difference between the l

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Link: Http://poj.org/problem? Id = 3522 Question: Slim Span Time limit:5000 Ms Memory limit:65536 K Total submissions:4962 Accepted:2587 Description Given an undirected Weighted GraphG, You shoshould find one of spanning trees specified as follows. The graphGIs an Ordered Pair (V,E), WhereVIs a set of vertices {V1,V2 ,...,Vn} AndEIs a set of undirected edges {E1,E2,...,Em}. Each edgeEεEHas its weightW(E). A Spann

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