python tutorial with exercises

absolute value of the coefficients is required, and the increment or decrement function has been determined by the coefficient symbol.Since the coefficients have been determined, the following need to solve is the intercept problem (according to the geometrical meaning I understand the term), if according to the concept of geometrical intercept is very well understood, if x=0, y>=0, then the symbol of intercept is "+", and vice versa is "-", since the symbol is determined, Then the value can on

fromFunctoolsImportReducedefStr2Int (s):defChar2int (c):return{"0": 0,"1": 1,"2": 2,"3": 3,"4": 4, "5": 5,"6": 6,"7": 7,"8": 8,"9": 9}[c]returnReduceLambdaX, Y:x * 10 +y, Map (Char2int, s))Print(Str2Int ("98986553"))Title, change the string to int1.# using the map () function, the user entered an irregular English name, the first letter capitalized, the other lowercase canonical name.# input: [' Adam ', ' Lisa ', ' Bart '], output: [' Adam ', ' Lisa ', ' Bart ']:m = map (Lambda s:

)Sys.Setdefaultencoding(' Utf-8 ')X= Int(Raw_input("net profit:"))IfX100000:Bonus=X*0.1 PrintU"bonus:",Bonus,U"yuan"Elif 100001X200000:Bonus=10000+(X-100000)*0.075 PrintU"bonus:",Bonus,U"yuan"Elif 200001X400000:Bonus=10000+7500+(X-200000)*0.05 PrintU"bonus:",Bonus,U"yuan"Elif 400001X600000:Bonus=10000+7500+10000+(X-400000)*0.03 PrintU"bonus:",Bonus,U"yuan"Elif 600001X1000000:Bonus=10000+7500+10000+6000+(X-600000)*0.015 PrintU"bonus:",Bonus,U"yuan"elif 600001x1000000: Bonus=10000+7500+ 10000+6000

numbers, ranging from large to small. (b) is the same as a, but it is arranged in a dictionary order from large to small. " # (a) Defget_num (): globalnum_listnum_list= []num= ' whilenum!= '! ': num=raw_input (' Enter some numbers to '! "End"). Strip () ifnum!= '! ': try: num=float (num) except: print ' input is wrong, please re-enter ' get_num () else: num_list.append (num) else: breakreturnnum_listdefsort_descending (): get_num () printsorted (num_list,reverse=true) print '---------------

For the first time on the weekend, try writing code exercises"Stupid way to learn Python"--author Zed A.shaw, translation Wang Dingweiex1.pyPrint (' Hello World ')---------------------------------------ex2.py#A comment, this was so you can read the your program later.#Anything after the # are ignored by Python.Print (' I could has code like this ') # and the comment are ignored.#you can also use a comment t

Chapter three function exercises and their answers 1. Why is it good to add a function to a program?A: The function reduces the duplicated code. This makes the program shorter, easier to read, and easier to modify.2. When does the code in the function execute: When the function is defined, or when the function is invoked?A: The code in the function executes when the function is invoked, not when the function is defined.3. What statement creates a func

Python Basics Exercises 11. Two ways to execute Python scriptsAnswer: command line execution, editor execution2, briefly describe the relationship between bits and bytesA : Byte byte bit: bit, 1 bytes = 8 bits3. brief description of the relationship between ASCII, Unicode, Utf-8,GBKFor:ASCII is the first United States to use the standard Information Interchange c

all the odd bit indexes of an incoming list or tuple object and returns it as a new list to the caller Def func1 (P,Q): result = [] for i1 in range (Len (P)): if i1% 2 = = 1: result.append (P[i1]) for i2 in range (len (q)): if i2% 2 = = 1: result.append (P[i2]) print (result) R = func1 ([11,22,33], (11,22,33)) Result: [22,22]Write functions, check the length of each value passed in the dictionary, and if it is greater than 2, retain only the first tw

#!/usr/bin/env python#-*-Coding:utf8-*-age = Int (Input ("Enter your Age")) if Age This article is from the "shallow blog of Pinellia ternate" blog, please be sure to keep this source http://sublime.blog.51cto.com/8856101/1829637Python Grammar Exercises--if judgment

1. Leap year (need to be optimized, can only be cycled once)year = Int (input ("Please enter the number of years:"))ifYear% 4: Print("not a leap year")#It can't be divisible by 4.Else: ifYear% 400: ifYear% 100: Print("Leap Year")#That can be divisible by 4, but not divisible by 100. Else: Print("not a leap year")#Divisible by 4 and divisible by 100, but not evenly divisible . Else: Print("Leap Year")#Divisible by 4 can be divisible by 400. E

Python exercise questions: multi-level menu (dict exercises), pythondict Menu = {'beijing': {'haidian ': {'wudaokou': {'soho ':{}, 'netease' :{}, 'Google ':{}}, 'zhongguancun ': {'iqiyi' :{}, 'car home' :{}, 'youku ':{},}, 'upgrade': {'Baidu ': {},}}, 'changping ': {'shahe': {'beihang ':{},}, 'tiantongyuan' :{}, 'huilongguan ': {},}, 'chaoyang ':{}, 'dongcheng' :{},}, 'shanghai': {'minhang ': {"People's Squ

Download the pictures of the girl on the specified website. here, only the pictures on the first 100 pages are captured. you can set the cat value of the number of pages to the image type as needed. you can change the cat value on your own, if you have any questions, please leave a message to me and I will answer the question. 2 = big breasts and sisters 3 = beauty leg control 4 = face filter value 5 = hodgedge 6 =... download the pictures of the girl on the specified website. here, only the pic

1 string formatting1 #!/urs/bin/env python2 3Name = input ("Name:")4age = Int (input ("Age :"))5Job = input ("Job:")6Salary = input ("Salary:")7 8Info1 ="""9 Ten -----------Info1 of%s--------- One Name:%s A Age :%s - Job:%s - Salary:%s the """%(name, name, age, job, salary) - - Print(INFO1) - +Info2 =""" - + -----------Info2 of {_name}---- A Name: {_name} at Age : {_age} - Job: {_job} - Salary: {_salary} - """. Format (_name=name, -_age=Age , -_job=Job, in_salary=salary) - to Print(Info2) +

Topic from Project Euler 20th: https://projecteuler.net/problem=20"Project euler:problem 20:factorial Digit sumn! means NX (n? 1) x...x3x2x1for example, 10! = 10x9x...x3x2x1 = 3628800,and The sum of the digits in the number 10! IS3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.Find The sum of the digits in the number 100! answer:648 "n = 100FAC = 1 #初始化阶乘结果while n >= 1: FAC *= n n = # extract each number of factorial results, form a list lstlst = [Int (i) for I In STR (FAC)]res = 0 #初始化相加结果for i in rang

1. Given the list L, such as [2,5,3,8,10,1], sort it in ascending order and output.Code: list = [2,5,8,10,1]Print (list)List.sort ()Print (list)2. Given a string s, such as ' 123456 ', reverse it out, using slicesCode: str = ' 123456 'Print (Str[::-1])3. Given the dictionary dict, such as {' A ': 1, ' B ': ' 2 ', ' C ': ' 3 '}, output its key and value, respectively. Insert the dictionary {' d ': 4} into it and output the new ZidCode:Dict = {"A": "1", "B": "2", "C": "3"}Print (Dict.keys ())Print

conjecture, Ulam conjecture, or the "idea of"--is that for every positive integer, if it is odd, it is multiplied by 3 plus 1, and if it is an even number, divide it by 2, so that the loop will eventually get 1.The judging condition is very clear, so the problem-solving mentality is also very clear: to judge all the numbers between 1-999999, calculate the number of steps to decompose each number to 1, the number with the largest number of steps (starting numbers) is the solution.To solve this p

the last target only needs to be a file path. A the @AutoNext + defprintinfo (): - whileTrue: $F =yield $ if(F not inchDISTINCT):#append f to the distinct list when f this path value does not exist in distinct - distinct.append (F) - Print(F) the -Chioce = input ("Please enter the keywords you want to retrieve:")Wuyi #Here's the call in fact, not difficult, careful analysis will be easy to understand theGene =Inputgetpath (OpenFile (Catfile (Grepline (Printinfo (), Ch

#学习笔记#用以练习Python基础#Original title Link: https://www.patest.cn/contests/pat-b-practise/10111011. A+b and C (15)for 3 integers a, b, and C within a given interval [-2 to 2 31], determine if A+B is greater than C. Input format:Enter line 1th to give the positive integer t (Output format:For each set of test cases, output "case #X: True" in one row if a+b>c, otherwise the output is "case #X: false", where X is the number of the test cases (starting at 1).