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:+ -------- + --------- + ------- +| Q1.sname | q1.sclass | Q1. mathematics | Q1. English | Q1. Chinese | q2.sname | q2.sclass | q2. mathematics | q2. English | q2. Chinese |+ -------- + --------- + ------- +| AAA | 3 | 83 | 65 | 50 | AAA | 3 | 8 | 6 | 8 || BBB | 3 | 95 | 58

| 83 | 65 | 50 || BBB | 3 | 95 | 58 | 86 || CCC | 3 | 75 | 78 | 92 || DDD | 3 | 76 | 77 | 83 |.....| Jjjj | 5 | 97 | 61 | 62 || Ll | 5 | 95 | 80 |+ ------- + ------ + ---- + Transform sum (table3.homeworkscore)Select table3.sname, table3.sclassFrom table3Group by table3.sname, table3.sclassOptional table3.course;+ ------- + ------ + ---- +| Sname | sclass | mathematics | English | language |+ ------- + ------ + ---- +| AAA | 3 | 8 | 6 | 8 || BBB | 3 | 6 | 7 | 7 || CCC | 3 | 7 | 9 | 9 |.....| Jj

. It took me one day to get stuck. At night, the ox told me that it was wrong to give me a second. For example, n = 5 m = k = 3 1 2 3 4 10000 In binary mode, the length is 2. The result is incorrect. The correct answer should be 4. Only scan through the monotonous queue. Maintain a maximum value and a minimum value. Ensure that the upper limit conditions are met when the maximum value-Minimum value is used. Then, if the lower bound condition is met, the answer is updated.

Address: Black Box Question: There is a black box for two operations, one is add to save the number in the box, the other is get to find the number in the box, the default box is always arranged from small to large, and then a (1), a (2 ).... A (M) is the number of boxes to be saved, u (1), u (2 ),.... the number of U (n) is not the number of the given number, but here the number of U (n) is inserted into the box a (m, here there is a P (1 Solution: First, sort timeout is used for each loop.

(Too lazy to typeset... ^ w ^)Today, I refreshed my DP question for a day and made it disgusting. I just got a question that can optimize both the slope and the Quadrilateral inequality: HDU 3480 division.Slope optimization... Okay, I forgot how to write ........YY ....................Bingo ....When the slope of a monotonic queue is optimized, monotonous queues are used to maintain the monotonicity of the "excellent" solution, that is, the better the former...Briefly summarize (using F [I] = min

%' _ Icontains indicates that Ilike '% AAA %' is case-insensitive. However, for SQLite, the effect of contains is equivalent to that of icontains. _ GT greater _ GTE greater than or equal _ Lt is less _ Equal to or less than LTE _ In exists in a list range. _ Startswith starts... _ Istartswith starts with... and ignores case sensitivity. _ Endswith ends... _ Iendswith ends with..., case insensitive _ Range is within the range... _ Year Year of the Date Field _ Month _ Day of the Date Field _ Is

Search for the largest public substring Find the largest common substring in the two strings, for example, "abccade" and "dgcadde". The largest substring is "cad" // Use for to control the loop, which is easier to understand than the following while. Int getcommon (char * S1, char * S2, char ** R1, char ** R2) { Int len1 = strlen (S1 ); Int len2 = strlen (S2 ); Int maxlen = 0; For (INT I = 0; I { For (Int J = 0; j { If (S1 [I] = S2 [J]) // finds the First Equal { Int as = I, B

How does function return a dataset? 1. Create or replace package RomeAsType refcursor is ref cursor;Function getcompany (key in char) return refcursor;End;/Create or replace package body Rome isIsFunction getcompany (key in char) return refcursorIsV_temp refcursor;BeginOpen v_tempSelect * from company where com_id = key;Return v_temp;End getcompany;End;2. (Applicable to PLSQL)Type shifts_ty is record (Comp_code varchar2 (10 ),Shift_code varchar2 (10 ),Sft_flg varchar2 (10 ),Beg_tm number,End_tm

code. T Indicates the number of errors that can be corrected. For example, (28, 24) the RS code represents a total of 28 characters in length of the block. The length of the Information Code is 24, and the verification code has four inspection symbols. In this Code block consisting of 28 symbols, two scattered or two consecutive symbol errors can be corrected in the code block, however, three or more symbol errors cannot be corrected. For an Information Code Symbol

chip communication. Q1, R2, R4, dw2, and four components provide a 12 V voltage for the programmer. R4 and R2 constitute a partial pressure circuit. In normal times, * 13th chip 89C51 (P3.3) output High Level, Q1 conduction, R2 (1 k) Will dw2 (12 V) Down, at this time dw2 voltage from R4, R2 partial pressure, about 3-5 V; when writing a program, the * chip 13th foot (P3.3) Outputs a low level,

($ filename ); Echo "OK, encryption complete! " ?> Encryption Method 2: The code is as follows: Function RandAbc ($ length = "") {// returns a random string $ Str = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz "; Return str_shuffle ($ str ); } $ Filename = 'index. php'; // file to be encrypted $ T_k1 = RandAbc (); // random key 1 $ T_k2 = RandAbc (); // random key 2 $ Vstr = file_get_contents ($ filename ); $ V1 = base64_encode ($ vstr ); $ C = strtr ($ v1, $ T_k1, $ T_k2); // re

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. The median is the mean of the middle value.Examples:[2,3,4], the median is3[2,3], the median is(2 + 3) / 2 = 2.5Design a data structure that supports the following and the operations: void addnum (int num)-Add A integer number from the data stream to the data structure. Double Findmedian ()-Return The median of all elements so far. For example:Add (1) Add (2) Findme

In multi-threaded programming, we often need to use data sharing. C # in how to implement it? You just need to set the data you want to share to static. The keyword static is as follows: Static queue Q1 = new Queue (); Static int B = 0; Here I define an integer variable B and queue Q1. You can create multi-threaded Code as follows: Mythread ACC; Thread [] MYT; MYT = new thread [10]; Py = new mythread (); Fo

result set Q1. (3) traverse the drive result set Q1 and the driven table T2, and retrieve a record from the drive result set Q1, next, traverse T2 and judge whether there is a matching record in T2 according to the connection condition T2.id = T1.id. If yes, the record is retained. If no matching exists, this row is ignored, then retrieve the next record from

Question 1 Can you name the special functions a C ++ compiler can create implicitly?Tip answerQuestion 2 What are the two ways to achieve automatic type conversion from Type X to Type Y?Tip answerQuestion 3 Which of one of these represents an assignment operation? C C1 = c2; C3 = C4; Both Tip answerQuestion 4 Given the classQz4: class Qz4 {enum{ arr_l=5 };int *arr; // array of intint seed;char *name;public:Qz4(char *str, int i) : name(str), seed(i) {arr = new int[arr_l];for(int i=0;i Can yo

Find the largest common substring in the two strings, for example, "abccade" and "dgcadde". The largest substring is "cad" // Use for to control the loop, which is easier to understand than the following while. Int getcommon (char * S1, char * S2, char ** R1, char ** R2) { Int len1 = strlen (S1 ); Int len2 = strlen (S2 ); Int maxlen = 0; For (INT I = 0; I { For (Int J = 0; j { If (S1 [I] = S2 [J]) // finds the First Equal { Int as = I, BS = J, Count = 1; // Save the first equal first address W

] = idx1 ++; } Void addedge2 (int u, int V, int W) { Edge2 [idx2]. W = W; Edge2 [idx2]. To = V; Edge2 [idx2]. Next = head2 [u]; Head2 [u] = idx2 ++; } Bool spfa (int s, int N, int head [], node1 edge [], int Dist []) { Queue Int INQ [N]; For (INT I = 0; I { Dist [I] = inf; INQ [I] = 0; } Dist [s] = 0; Q1.push (s ); INQ [s] ++; While (! Q1.empty ()) { Int

As we all know, it is very efficient to search for ordered sequences using the bipartite method. In addition, the idea of the Bipartite method is applied in many aspects, not only to find a specific data. For example, when we evaluate the zero point of a monotonic function f (x), suppose we know that its zero point is in a range (a, B, then we can use the bipartite method to obtain the root of f (x) = 0. Now, let's look at a practical application. Topcoder SRM338 2nd question, (http://www.topcod

SICP sicp 108: 3.21 exercises 1083.21 andExercise 3-21 original Exercise 3.21. Ben Bitdiddle decides to test the queue implementation described above. He types in the procedures to the Lisp interpreter and proceeds to try them out: (define q1 (make-queue))(insert-queue! q1 'a)((a) a) (insert-queue! q1 'b) ((a b) b) (delete-queue!

],lie[Ten][Ten],sum[Ten][Ten][Ten],x[ -],y[ -]; - intCon,n,ans,c=0; the - voidDfsintm) - { - inti,j,q1,q2; + if(m==N) { - if(c==0) +C=1; A Else atprintf"\ n"); -ans=1; - for(i=0; i9; i++){ - for(j=0; j9; J + +){ - if(j!=0) -printf" "); inprintf"%c", Mp[i][j]); - } toprintf"\ n"); + } - return; the } * for(i=1; i9; i++){ $