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Use the fast Fourier transform to calculate the big integer multiplication

We know that the multiplication of two n-digit integers, if the regularAlgorithmThe time complexity is O (n2 ). However, using the fast Fourier transformation, the time complexity can be reduced to O (n logn ). Assume that we want to calculate the product of the following two n-digit numbers: A = (aN-1aN-2... a1a0) 10 = aN-1x10N-1 + aN-2x10N-2 +... + a1x101 + a0x100 B = (bN-1bN-2... b1b0) 10 = bN-1x10N-1 + bN-2x10N-2 +... + b1x101 + b0x100 Multiply the two formulas to obtain the follo

Shell Text Extraction

For details, refer to shell Text Extraction-general Linux technology-Linux technology and application information. The text content is as follows: **************************************** *************************************** * Sub-Circuit Netlist :* ** * Block: ZXQ_INV_STD * * Last Time Saved: Dec 24 15:48:29 2008 * **************************************** *************************************** . Subckt ZXQ_INV_STD in_bar in *. NOPIN GND *. PININFO in_bar: O in: I MI1 in_bar in GND N18 w =

Summary of association rule mining algorithms)

which is a recursive algorithm based on the two-phase frequency set thinking. This association rule belongs to single-dimension, single-layer, and boolean association rules in classification. All the items with a higher degree of support than the minimum level are called frequency sets. 4.1.1 basic idea of Algorithms First, find out all frequency sets. The frequency of these item sets is at least the same as the predefined minimum support. Then, strong association rules are generated by t

SAP ck40n FAQs

Many of the causes of ck40n errors include:1, raw materials: whether to maintain the standard unit price, no cost accounting (ncost) This paragraph, procurement type, material status These fields are maintained correctly2, semi-finished products and finished products in terms of more problems, in addition to the above mentioned:1), whether there is an exhibition BOM2), whether there is a route3), whether to maintain the job type, the job price, whether the cost center is available, etc.4), wheth

Winform form (2) -- controls and winform controls

subclass radiobutton if (ctr is RadioButton) {// if the conversion is RadioButton rd = ctr as RadioButton; if (rd. text = "female") {rd. checked = true ;}}}}Radiobutton -- set selected ※Use the code to add a tool to the container:Private void Form1_Load (object sender, EventArgs e) {// create the tool's object RadioButton radiobutton4 = new RadioButton (); // assign the value radiobutton4.Text = "ha "; // There is a parent class in the brackets, and the rdsx principle is panel1.Controls. add (r

Summary of association rule mining algorithms

则中,对数据的多层性已经进行了充分的考虑。 3)基于规则中涉及到的数据的维数,关联规则可以分为单维的和多维的。 在单维关联规则中,我们只涉及到数据的一个维,如用户购买的物品 在多维关联规则中,要处理的数据将会涉及多个维。 4算法综述 4.1经典的频集算法 Agrawal等于1994年提出了一个挖掘顾客交易数据库中项集间的关联规则的重要方法[AS94a, AS94b],其核心是基于两阶段频集思想的递推算法。该关联规则在分类上属于单维、单层、布尔关联规则。 所有支持度大于最小支持度的项集称为频繁项集,简称频集。 4.1.1算法的基本思想 首先找出所有的频集,这些项集出现的频繁性至少和预定义的最小支持度一样。然后由频集产生强关联规则,这些规则必须满足最小支持度和最小可信度。 挖掘关联规则的总体性能由第一步决定,第二步相对容易实现。 4.1.2 Apriori核心算法分析 为了生成所有频集,使用了递推的方法。其核心思想简要描述如下: (1)L1= {large 1-itemsets}; (2)for (k=2; Lk-1¹F; k++) dobegin (3)

Fourth chapter of DSP

it is a periodic signal, so the frequency domain is also discrete and has n components. The time domain is discrete, which causes the frequency domain to be periodic. And the cycle is also nThe discrete-time signal is obviously also considered power spectrum (the power here is the same as the previous, average power). The amplitude is also the square of the coefficient modulus.Fourier coefficients have a property of ck=

Introduction of frequent pattern mining Apriori algorithm and Java implementation

the items that meet the minimum support level, and find the collection of frequent 1 itemsets. The collection is recorded as L1. Then, using L1 to find the collection of frequently 2 itemsets L2, use L2 to find L3, so go on until you can no longer find frequent k itemsets.As you can imagine, the computational complexity of the algorithm is very large. In order to improve the efficiency of frequent itemsets, it is necessary to use a priori nature ( all non-empty sets of frequent itemsets must be

Solve the problem of Chinese garbled cookies in ASP.

When setting a cookie, if the content in the cookie is in Chinese, it will be garbled after reading, and no such problem exists in English or in numbers. The solution is not to access directly, but to use coded methods for access.1. Set Cookiespublic void Setcookies (){HttpCookie ck = new HttpCookie ("Cklogin");Ck. Values.add ("CID", Httputility.urlencode (UserID));Ck

JQuery Performance Optimization

(Array.join ("));You can contact the StringUtils join () in Java, and use the Stringbulider,stringbuffer usage comparison.V. Using the native JS methodFrequently judging whether a multi-box is selected:var $ck = $ ("#ck");$ck. Click (function ()) {if ($ck. Is (": Checked")) {Alert ("Checked");}})Switchvar $

Action on jquery check box

Summary: jquery action check box. Use more concise, clear thinking, logic more clear, very practicalmin. js to top-- min. js to top--jquery takes the selected value out of the check boxclass= "ck" value= "Zhangdian"/>Zhangdianclass= "ck" value= "Zichuan"/>Zichuanclass= "ck" value= "Zhoucun"/>Zhoucunclass= "ck" valu

Naive Bayesian Method-Maximum posteriori probability

Then go on to write the last article.When the naive Bayes method is classified, a posteriori probability distribution P (y=ck|) is computed for a given input x by learning the model. X=X), then output the class with the largest posteriori probability as the class of X. The posterior probability calculation is based on Bayesian theorem:P (y=ck| x=x) =p (x=x| Y=ck

VNX NETAPP NAS Backup Recovery

How many times a snapshot is made is customized, such as it can be done every 4 hours.For example there are a,b,c,d of four files.1) First Snapshot (COW):The snapshot is instantaneous, when the camera creates a snapshot space, for example, 20%, then changes the a file to A1 (the change is compared to the time of the photo), Checkpoint/snap shot is a file, and then back up the CK. Restore the words according to CK's pointer (pointing to the source file

Chico and dico--guess 5th card According to any 4 cards

. This is the answer. Assuming that there are n cards, the arrangement of arbitrarily taking K-j cards is n!/(n+j-k)! species, which can have so many different encodings, the combination of randomly selected K-sheets is a C (n,k) species. To determine the entire K combination according to the order of the former k-j, the C (n,k) ≤n!/(n+j-k) must be met!, i.e. (n+j-k)!≤k! (N-K)!. So the mapping to find is to make k-j this arrangement of all the cards are in C (n,k) This K-card mapping. Of course,

C + + self-study notes four times

Common methods of data sharing global variables have great limitations and undermine encapsulation. Static members, as a data member of a class, can implement data sharing between multiple objects, and the use of static data members does not return the principle of concealing information, guaranteeing the security of the program.A static member belongs to a class, and if a static member is defined in a class, then each object can manipulate it.#include using namespace Std;Class

Easy Grid Table Control simple usage

);}Me.cleardiv = me.table.nextSibling;Me.wrap = wrap;Me.fireevent ("Render", ME);},On:function (EN, FN, scope) {var me = this;if (en = = "Rowdblclick") {Easy.each (me.rows, function (r, i) {Easy.DOM.on (R, "DblClick", Easy.delegate (FN, scope | | me, [R, I]));})}(Scope | | me) ["On" + Easy.String.toPascal (en)] = easy.delegate (FN, scope | | me, easy.slice (arguments, 3));},Onrender:function () {var me = this, style = {};if (me.height) {Style.height = Math.max (me.height-me.table.offsetheight-75

JS Remove duplicate string Two kinds of implementation method _javascript skill

Results var str2 = ""; for (Var key in JSON) { STR2 + = "," + Json[key]; } var s = str2.tostring (); Remove the first comma if (s.substr (0, 1) = = ', ') { s = s.substr (1); } return s; } function Add_all () { var ck = document.getelementsbytagname ("input"); for (i = 0; i if (Ck[i].type = = "checkbox") { Ck[i].checked = true; Checkre (

How does thinkph output the excel file?

'), 'File name! '); */Function exportexcel ($ data = array (), $ title = array (), $ filename = 'report') {header ("Content-type: application/octet-stream "); header (" Accept-Ranges: bytes "); header (" Content-type: application/vnd. ms-excel "); header (" Content-Disposition: attachment; filename = ". $ filename. ". xls "); header (" Pragma: no-cache "); header (" Expires: 0 "); // export xls to start if (! Empty ($ title) {foreach ($ title as $ k => $ v) {$ title [$ k] = iconv ("UTF-8", "GB2

thinkph in the end how to output Excel, little brother quickly crazy

($stu); Exportexcel ($arr, array (' ID ', ' account ', ' Password ', ' nickname '), ' filename! '); */function Exportexcel ($data =array (), $title =array (), $filename = ' report ') {header ("Content-type:application/octe T-stream "); Header ("Accept-ranges:bytes"); Header ("Content-type:application/vnd.ms-excel"); Header ("Content-disposition:attachment;filename=". $filename. ". XLS "); Header ("Pragma:no-cache"); Header ("expires:0"); Export xls

Description and usage of Cookie status in ASP. NET, asp. netcookie

information into the URL statement used by the user. For example, when a user uses cookies, the URL of a webpage is http: // yourserver/folder/default. aspx, now the Cookie-free configuration is set, the URL of the called statement will be changed to: http: // yourserver/folder/(session ID here)/default. aspx, where "session ID here" represents the location of the user's resource information. This information has been inserted into the URL statement. Because the user resource information is uni

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