quantum 1080

Oracle scalar queries and their own defined functions are sometimes easier to use, and are often used by developers. Small amount of data does not matter. The amount of data is large and there are often performance problems.Here is a test to help you understand the scalar quantum query thoroughly. Sql> CREATE TABLE A (ID int,name varchar2 (10)); Table created. Sql> CREATE TABLE B (ID int,name varchar2 (10)); Table created. Sql> INSERT into a values (1

Label:The statement to be optimized is as follows SelectA.code asCode, A.m_code asM_code,a.stktype asF_stype,a.e_year asE_year, B.sname asSname,a.c_date asC_date,to_char (Sysdate,'YYYYMMDD') asCreatetime, To_char (Sysdate,'YYYYMMDD') asUpdateTime, (Select sum(VALUEF2) fromA TwhereT.code=A.code andT.c_datebetweenTo_char (To_date (A.c_date,'YYYYMMDD')- the,'YYYYMMDD') andA.c_date andT.e_year=a.e_year) e70115_70011, (Select sum(VALUEF1) fromA TwhereT.code=A.code andT.c_datebetweenTo_char (To_date (

Release date:Updated on: Affected Systems:Schneider Electric Modicon QuantumDescription:--------------------------------------------------------------------------------Bugtraq id: 51605Cve id: CVE-2012-0929, CVE-2012-0930, CVE-2012-0931 Schneider Electric is a company that has been committed to improving customers' performance and daily living standards in the power industry. Schneider Electric Group provides products and services for energy and infrastructure, industry, data centers and network

1. Laser(1) Laser principleEinstein's Radiation Theory:Spontaneous emission: The process by which an atom transitions from an energetic state to a low-energy state and emits photons, i.e. H (v) =e2- E1Stimulated radiation: stimulated radiation light amplification is the basic mechanism of laser generation. N21=b21ρ (v) N2Stimulated absorption: n12=b12ρ (v) N1The relationship between Einstein coefficients A12, B21 and B12:A21n2+b21ρ (v) n2=b12ρ(v) N1(2) necessary conditions for laser generationPa

}ilikesanpanilikeluoswimming[[emailprotected] scripts]#echo${liuyifei%like*}ilikesanpani[[emailprotected] Scripts]#echo${liuyifei%%like*}i========================${string/substring/replace} replaces the first encountered match character${string/#substring/replace} prefix match, must match all, replace a strip${string/%substring/replace} to replace the last encountered match character from the back,[[email protected] scripts]# echo ${liuyifei/like/love}I love Sanpan i like Luo swimming[[email pro

${variable/#substring/replace} if the $string prefix matches $substring, $replace is used instead of matching $substring${variable/%substring/replace} if $string end matches $substring, use $replace instead of match $substring#!/bin/shfor i in $ (ls |grep "jpg$");d Oi=${i/%jpg/mp4}doneResults:[Email protected] ~]# sh for2.sh stu_10299_1_.mp4stu_10299_2_.mp4stu_10299_3_.mp4stu_10299_4_.mp4stu_10299_5_.mp4V. Substitution of variables${value:-word} If the variable value has an assignment, use th

others: The topic gives NOP operation, by N (do Nothing), S (1), C (0), F (reverse) and other basic operations, each operation will produce different heat. The initial string and the target string of the NW group are given, which require the heat to be generated at least to convert the initial string into the target string, and there may be no solution at this time to output "NP"Direct BFS, similar to DFS's brute force enumeration, the queue loops, each time to sweep all the NOP operations, and

(Defprotocol X (cat [this other])Define a protocol, which is similar to the objective-C protocol. Different from Java interfaces. User => X {: On-interface user. x,: on user. x,: Sigs {: CAT {: Doc nil,: arglists ([this other]),: Name cat }},: var # 'user/X ,: method-map {: Cat: CAT },: method-builders {# 'user/cat # User => (extend-type string X (cat [this other] (. Concat this other )))This is the objc style. Define a function as an implementation of a type under a protocol. User => (Ca

portal:http://codevs.cn/problem/1080/ The question was a little waking up to me: The tree array is not the same as the line tree (half an hour ago the concept of the intellect is silly). The main idea is to use a tree-like array to store the prefix and then prefix and subtract to get the interval and. The knowledge of the line segment tree appeared in the Blue Book,,, inexplicably from the Purple book upgrade. Mark I read that blog: http://blog.csdn

Question: it is A variant of the longest common subsequence. The characters in this question are only A, G, C, and T, plus '-'; different matches have different weights W. Only matching with the same character has a weight greater than 0, and other

Deformation of Longest Common subsequence The maximum similarity between two gene sequences is obtained. The table in the topic shows the similarity of the Two-to-two deoxidizing nucleotide.   The state transition equation is: DP [I] [J] = max (DP

// DP dynamic planning, deformation of LCS problems. Based on the classic LCS model, we use DP [I, j] to represent the optimal values matching I and j. the final answer is DP [len1] [len2] // obviously there are two situations: // 1. S1 [I] = S2

Calculate the similarity between two DNA base sequences. you can insert spaces to match any base. The question shows the price of any match. Idea: score [I] [J] isMaximum values: seq1 [I] And seq2 [J] match + score [I-1] [J-1]; space and seq1 [I]

Welcome to follow the pan-Thai non-profit third-party development team VegaDevTeam (this team is composed of syhost suky zhaochengw (z) xuefy (big star) tenfar (R master) loogeo crazyi (snow-free world) windxixi) wangsai008) Brief history of

# Include # include # include # include using namespace STD; int map [105] [105]; int pay [105]; int N; queue q; void Init () {memset (pay,-1, sizeof (Pay); memset (MAP, 0, sizeof (MAP )); while (! Q. empty () {q. pop () ;}} int BFS (int x)

#include #include #include #include #define INF 0X3F3F3F3F #define LL unsigned long long #define Lson u>1; Build (Lson); Build (Rson); e[u].s=e[u>1; if (x>1; if (ymid) return query (rson,x,y); else return query (lson,x,mid) +query

//Time 0ms, Memory 288K #include#includeint main(){ int i,j,la,lb,t,map[20][20],dp[105][105],x,y,z; char a[105],b[105]; memset(map,0,sizeof(map)); map[0][0]=map[2][2]=map[6][6]=map[19][19]=5;

# Include # include # include # include # include using namespace STD; Map dicm; // dictionary void myinit () // initialize dictionary {dicm. insert (make_pair ("AA", 5); dicm. insert (make_pair ("AC",-1); dicm. insert (make_pair ("ag",-2);

DFS, unlimited TLE, and ugly code // Version 1 TLE # include # Include # Include # Define MAX_INT 2147483647 # define MAXN 105 using namespace std; int Map [5] [5] = {0,-3,-4,-2,-1 }, {-3, 5,-1,-2,-1}, {-4,-,-3,-2}, {-2,-2, -2},

Given a string, the two strings are composed of A, T, G, and C, and are paired with each other. You can insert a dry space for each of them to obtain the final sum and the maximum value. The following States can be defined. f [I] [J] indicates that 1