rapid rope

Descriptionn Sets of M operationsOperation:1 A B merges the set of A and a2 k back to status after K-operation (query counts as action)3 A B asks if a, a, or not belongs to the same set, is output 1 otherwise output 00Inputoutputsample Input5 6 1 1 2 3 1 2 2 0 3 1 2 2 1 3 1 2Sample Output1 0 1SolutionUse rope to implement a persistent array, using the rope history function to achieve persistence and search,

Tutorials require support for the CS5 version. Using a tool for manipulating variants, the tutorial authors describe in detail how and how the tool is used. Using this tool you can twist a rope or other object into a desired effect, very practical. Final effect 1, first of all we want to have a very long rope (hehe precision best high, rope can be repeated

Ural 1020. Rope (ry), ural1020rope ry Link: ural 1020. Rope N vertices are given in order. Each vertex has a radius R. The length required to enclose N vertices by line. Solution: because a circle is needed, the rotation angle must be one week, and the plate diameter is the same, so the distance between the two points is directly added with a perimeter. # Include

Label: style HTTP color Io OS AR for SP on Link: Ural 1020. Rope N vertices are given in order. Each vertex has a radius R. The length required to enclose n vertices by line. Solution: because a circle is needed, the rotation angle must be one week, and the plate diameter is the same, so the distance between the two points is directly added with a perimeter. #include Ural 1020. Rope (ry)

1. Title Description: Click to open the link2. Problem-Solving ideas: The topic is a calculus, first of all according to the conditions of the problem of the equation: Interval number N=ceil (b/d), each interval width d1=b/n, each length of rope l1=l/n. The next step is to calculate the height of the bottom from the ground on the d1,l1 to Y. However, we will find that this equation is difficult to find the formula, so we should transfer the idea, tryi

2705: Skipping games Total time limit: 1000ms Memory Limit: 65536kB Describe children play rope skipping competitions, to calculate how many jumps in a minute. Assuming a jump every second, it will take three seconds to start the jump if it fails halfway. The average child jumps a minute to jump a few times. It is now given the total number of hops that a chi

13th Pass: Small make up think this pass to try more than a few times, first, by constantly clicking on the blue, let blue squeeze candy, is its left and right swing, then let lick out the tongue, catch the falling blue, finally, cut the rope, let Candy eat 3 stars, the following figure is small series of Samsung clearance map: 14th Pass: 1. First click on the left blue, candy to eat the first star. 2. Continue clicking on the blue on the left

The code can pass the test case, but it's still wrong. It's the end of tonight, two days later.In just the past 38 knots, the school carried out a group skipping game to calculate how many jumps in a minute. Assuming a jump every second, if you fail halfway, it takes three seconds before you start to jump again. Usually each team one minute jump rope skipping more or less to break a few times. Now give the total number of hops each team has jumped eac

(1) Windows camp (2) C/C ++ camp ........................................ ........................................ ...... This results in four groups of people:(1) [narrow sense] A person who can swim at both ends of the rope has a deep skill .....(2) Monographs in one camp, just like the sun in a magnifying glass, the power will go in ,................. how hard is cross-platform?(3) work, learning, and helpless rush at the ends of the

Round 1C 2010, C Round of test questions. I thought it would be more difficult, but the first question is still relatively simple. Rope Intranet: calculates the intersection of ropes. The algorithm traverses all the ropes directly and accumulates the number of intersections between the ropes and the rest. The Code is as follows: #!/usr/bin/python#encoding:UTF-8#Filename:RopeIntranet.pyimport sysdef compareWire(a,b): if (a[0] Test passed. However, i

the Fedora operating systemThe repo file is a configuration file for the Yum source (software repository) in fedora, typically a repo file defines the details of one or more repositories, such as where we will download packages that need to be installed or upgraded, and the settings in the repo file will be read and applied by Yum!Yum's work is not complicated, and every RPM software's head (header) records the dependencies of the software, so if you can record the contents of the header and an

The number of jumps in one minute is calculated when a kid is playing a rope skipping competition. for example, if a hop fails every second, it takes three seconds to start the re-hop. generally, children skip rope several times a minute. now we will show you the total number of hops that children have jumped when they break down. AC code: 1 #include 16 if(t Wa code: 1 # include

Rope Tutorial: http://blog.csdn.net/iamzky/article/details/38348653 Code (bzoj3673 ): 1 # include [Persistent array] [Rope] bzoj3673 bzoj3674 persistent and query set by zky

Note that there is only one factor in the case.1#include 2#include 3#include 4 5 using namespacestd;6 7typedefLong Longll;8 Const intINF =0x3f3f3f3f;9 Const intMAXN = 4e3+Ten;Ten structCake One { A intw,l; - cake () {} - BOOL operatorConstCake b)Const the { - returnL >B.L; - } - }CK[MAXN]; + - intN,LEN[MAXN]; + A intMain () at { -scanf"%d",N); - - for(intI=0; i) - { -scanf"%d%d",ck[i].w,ck[i].l); in if(Ck[i].w >ck[i].l) Swap (CK[I].W,CK[I].L); - }

Development trends: How much does the rapid development platform know?First, what is the rapid development platformIn short, it is the platform that can make development faster. When the development platform has been generated, although the programmer has reduced the number of programming time, but many development platforms to add links to describe the effect is not very good, such as some development plat

Rapid app development. This rapid development framework integrates PC and mobile development to make development more enjoyable !, Apppc I have published many articles on rapid PC development, but now more and more projects require the combination of PCs and mobile terminals. So, I will introduce you to the APP version of the previous quick development platform,

Failure phenomenon: Intel Rapid Start error your system does not appear to have enabled the Intel Rapid start Technology, as shown in the following figure: Reason Analysis: 1. The Intel Rapid Start technology is not enabled under the BIOS. 2. The hibernate partition is corrupted or does not exist under the system with the Intel

RSTP = 802.1wNote The main points: Fast convergence is based on switch-related process synchronization To open a command:-Spanning Tree mode MST-Spanning Tree mode Rapid-pvst The synchronization process only occurs on the peer Non-edge port (the full Duplex,non-edge to have the Bpdu,edge port configured portfast command) Note: If Portfast is not configured on the edge port and the port is full duplex, the host does not rep

Rap overviewRAP (Rapid application Platform) Rapid Application development Platformis a b/s way to operate the platform data lightweight tools, easy to achieve the development of files, documents and reports, ordinary users without writing any code, you can easily complete complex functions, really do what is WYSIWYG.The development platform is based on the. NET system is the process of automatic generation

Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4549 F [0] = a ^ 1 * B ^ 0% P, F [1] = a ^ 0 * B ^ 1% P, f [2] = a ^ 1 * B ^ 1% p ..... f [N] = a ^ fib [n-1] * B ^ fib [N-2] % P. Here, P is a prime number and a and P are mutually Prime, So we calculate a ^ B % P. When B is very large, we need to reduce the power of B. Because a and P are mutually unique, a ^ (p-1) % P = 1 is known by the Fermat theorem. Make B = K * (PM) + B ', a ^ B % P = a ^ (K * (PM) + B ') % P = a ^ (K P-1) % P * a ^ B '%