remove duplicates from ipod

Title: Remove Duplicates from Sorted List Pass Rate: 34.5 Difficulty: Simple Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .I feel that the problem is relatively simple. Overall quite smo

Follow "Remove duplicates": What if duplicates is allowed at most twice?For example, Given sorted array A = [1,1,1,2,2,3],Your function should return length = 5, and A is now [1,1,2,2,3]Analysis: Array elements can only appear at most two times. Public classSolution { Public intRemoveDuplicates (int[] nums) { if(Nums.length returnnums.length; intindex = 2;

Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted Array A = [1,1,1,2,2,3] ,Your function should return length = 5 , and A is now [1,1,2,2,3] .Analysis: Starting with the third number, each number is only compared to the second number in front of it, and if it is different, the number is added to the result,

Title Description Link Address Solution Title DescriptionGiven a sorted linked list, delete all duplicates such this each element appear only once.Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3.Link Addresshttp://www.lintcode.com/en/problem/remove-duplicates-from-sorted-list/SolutionListNode*Deleteduplicates (ListNode*Head)

Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] ,Your function should return length =, with the first 5 five elements of nums being 1 , 1 2 2 ,, and 3 . It doesn ' t matter what are you leave beyond the new length.Topic: Given a well-ordered array, there are repeating elements,

Topic:Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted Array A = [1,1,1,2,2,3] ,Your function should return length = 5 , and A is now [1,1,2,2,3] .Analysis:1. You can add a variable to record the number of repeating elements.2. If the array is not ordered, you can use HashMap to record the number of elemen

Problem:Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted Array A = [1,1,1,2,2,3] ,Your function should return length = 5 , and A is now [1,1,2,2,3] .Hide TagsArray of PointersTest instructions: The array is de-iterated, the same element appears up to 2 times, the new array size is returned, and the arrays

Topic:Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] ,Your function should return length =, with the first 5 five elements of nums being 1 , 1 2 2 ,, and 3 . It doesn ' t matter what are you leave beyond the new length.Ideas:Go ahead and judge one step more PackageArray; Public

Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] , Your function should return length = 5, with the first five elements ofNumsBeing1,1, 2 , and 2 3 . It doesn ' t matter what are you leave beyond the new length. 1 classSolution {2 Public:3 intRemoveDuplicates (vectorint

https://oj.leetcode.com/problems/remove-duplicates-from-sorted-list/Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 ./*** Definition for singly-linked list. * public class ListNode {* int val; * ListNode Next; * ListNode (int X) {* val = x; * ne

Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] ,Your function should return length =5, with the first five elements ofNumsBeing1,1,2,2and3. It doesn ' t matter what are you leave beyond the new length.Idea: The subject allows the array to have a maximum of two repetitions, so y

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Idea: This problem is similar to the previous one, the concrete solution is as follows:/** * Definition for singly-linked list. * public class ListNode {* int val; * ListNode Next; * listnode (int x) {val = x;}}} */public class Soluti On {public ListNode deleteduplicates

Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] ,Your function should return length =, with the first 5 five elements of nums being 1 , 1 2 2 ,, and 3 . It doesn ' t matter what are you leave beyond the new length.is the 26th version of the extension, 26 is to give a sorted arra

Topic:Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] ,Your function should return length =, with the first 5 five elements of nums being 1 , 1 2 2 ,, and 3 . It doesn ' t matter what are you leave beyond the new length. test instructions and analysis : An ascending array is giv

Topic:Follow up for "Remove duplicates":What if duplicates is allowed at the most twice?For example,Given sorted array nums = [1,1,1,2,2,3] ,Your function should return length =, with the first 5 five elements of nums being 1 , 1 2 2 ,, and 3 . It doesn ' t matter what are you leave beyond the new length.Idea: Record the number of times for each number, and maint

Because the list is used, there are several ways to remove duplicate data. Recorded in this ...Test data:listMethod One:hashsetSeveral ways to remove duplicates in the list collection-reproduced

/** Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * ListNode (int x) : Val (x), Next (NULL) {}}; */classSolution { Public: ListNode* Deleteduplicates (listnode*head) { if(Head ==null)returnHead; if(Head->next ==null)returnHead; ListNode*res =Head; intHead_val; while(head) {Head_val= head->Val; if(Head->next head->next->val = =head_val) { while(Head Head->val = = head_val)//Remove the beginning of

do not know the size of the problem, it is very bad. It also caused me to waste a quick 2 hours =.= (listnode* res,*tmp;STD:: mapint,int>Ans ListNode *deleteduplicates (ListNode *head) {ListNode * I,*K,*AA;intJBOOLflag=true;if(head = = NULL | | head->next = = NULL)returnHead for(j=-65536;j65537; j + +) Ans.insert (STD::p airint,int> (J,0)); for(I=head;i!=null;i=i->next) {ans[i->val]++;//cout} for(I=head;i!=null;i=i->next) {if(ans[i->val]==1){int*a =New int; ListNode L (i->val);//cout

found that Prev is Fakenode node initially. Because the Fakenode node initially points to the head node.Runtime:8ms/** * Definition forsingly-linked list. * struct ListNode {*intVal * ListNode *Next; * ListNode (intx): Val (x),Next(NULL) {} * }; */classSolution { Public: listnode* deleteduplicates (listnode* head) {ListNode * fakenode=NewListNode (0); Fakenode->Next=head; ListNode *prev=fakenode; while(head!=NULL) {if(head->Nexthead->val==head->Next->val) {intvalue=head->val; while(Headhead-

; * ListNode *next; * ListNode (int x): Val (x), Next (NULL) {} *}; */class Solution {public:listnode* deleteduplicates (listnode* head) {if (head==null) return NULL; if (Head->next==null) return head; listnode* P=head; listnode* Q=head; listnode* k=p->next; BOOL Flag=false; while (k) {if (p->val==k->val) {if (p==q) {p=q=k; Head=k; k=k->next; } else {listnode* tobedeleted=k; p->next=tobedeleted->next; k=p->next; Delete tobedeleted; Tobedeleted=nu