rooster crowing

Hundred money to buy hundred chicken problem is a very classical problem of indefinite equation, the topic is simple: Rooster 5 Money A, hen 3 money A, chicken 3 only a penny,Buy 100 chickens with 100 cents, among them cocks, hens, chickens all must have, ask the rooster, hen, chicken to buy how many only just to make up 100 text money.Analysis: It is estimated that pupils can now manually calculate the pro

Hundred money to buy hundred chicken problem is a very classical problem of indefinite equation, the topic is simple: Rooster 5 Money A, hen 3 money A, chicken 3 only a penny,Buy 100 chickens with 100 cents, among them cocks, hens, chickens all must have, ask the rooster, hen, chicken to buy how many only just to make up 100 text money.Analysis: It is estimated that pupils can now manually calculate the pro

There is an interesting question today:A group of friends wrote with a shell:#!/bin/bash# hundred million chicken, each chicken at least buy one all= -# Cocks per how many yuan read-P'Rooster How many text one:'gongji# hen per how many yuan read-P'How many hens a hen:'muji# can buy a few chickens per dollar read-P'chick How many only one article:'xiaoji# hundred dollars to buy a few cocks gongji_count=`Expr${all}/${gongji} 'Echo "======== hundred yuan to buy hundred chicken ========"Echo "

How to Use php for multiplication, how to buy a chicken for a hundred dollars, and how to bridge the bridgeExercise Question 1: crossing the bridge Suppose someone has 100,000 in cash. Each time you pass through an intersection, you need to pay a fee. The payment rule is that when his cash is greater than 50,000, he must pay 5% each time. If his cash is less than or equal to 50,000, he must pay 5,000 each time. Please write a program to calculate how many times this person can pass through this

day, you cannot. Go with each passing day;Guotai Min An Yu dog. Every day;Year Old Ji nanxiang dog. Lu Jing, Panasonic data center;Jiashou.com. Yue Ming Liu Xiyu Jing;Yangguang human rooster. Sun-like new rooster news;The year-old auspicious dog opens the door. Cool generations play lion night;The weather enters the dog year with thousands of ends. Fang guanzhu Shu Chicken claw;And mei Hua Yin

The original: The classic algorithm daily exercise--the first question hundred money to buy hundred chickensHundred money to buy hundred chicken problem is a very classical problem of indefinite equation, the topic is simple: Rooster 5 Money A, hen 3 money A, chicken 3 only a penny,Buy 100 chickens with 100 cents, among them cocks, hens, chickens all must have, ask the rooster, hen, chicken to buy how many

The problem of buying a chicken with a hundred dollars is a very classic problem of the indefinite equation. The question is very simple: a rooster has five yuan, a hen has three yuan, and a chicken has three yuan, buy 100 chickens with one hundred yuan, of which the rooster, hen, and chicken must have them. Ask the rooster, hen, and how many chicks are required

Chaos first points, Zodiac branch just timed, the Jade Emperor ordered Pu the world animals, to press sub, ugly, Yin, Mao, Chen, have, noon, not, Shen, unitary, Xu, Hai 12 to select 12 Zodiac. After the news, the cat and mouse were alerted to the two friends. The cat said to the mouse: "Tomorrow just before dawn to heaven mayors, I have a sleeping problem, when you can shout me!" "The mouse repeatedly said:" Say, say! " But the next morning, the non-Lutheran mouse but secretly get up without say

Case Description: The ancient Chinese mathematician Zhang Chujian in his "calculation of the book" put forward a famous "hundred Money Hundred Chicken problem": A rooster worth five money, a hen worth three money, three chickens worth a money, now to use hundred money to buy hundred chickens, ask rooster, hen, chicken how many only? Case study: If you buy only one chicken with 100 bucks, then the

becomes a dead loop. Customary if the change is irregular or the number of times is not sure to use while (for example, from the console to get a more than 10 odd, it is possible to enter many times, that is, with this) while (N Ask 1-50 and int sum = 0;//for the For loop, if the control condition of the second part is not written, then the default is true, and this time it becomes a dead loop. for (int i = 1; i 　　Practice: Hundred Money Hundred Chicken---3 text money 1

PHP exercises (2): php exercises. PHP exercise (2), php exercise program 6. question: If a person has 100,000 yuan in cash and needs to pay a fee every time he passes through an intersection, the rule is that when his cash is greater than 50,000, he needs PHP exercises every time (2). php exercises Program 6.Question:Assume that a person has 100,000 yuan in cash and must pay 50,000 yuan each time after the intersection. if the cash is less than or equal to 50,000, 5,000 yuan is required each ti

For poor lifting method, iterative methodPractice of poor lifting method: //Poor lifting method://1. Find the number of 7 related to 100 or less//2, Xiao Ming unit sent 100 Yuan shopping card, he went to the supermarket to buy cleaning supplies, one is shampoo (15 yuan), two is soap (2 yuan), Three is toothbrush (5 yuan) how can just put 100 yuan spent. //3, Rooster Two money A, hen a penny, chicken half text money A, spend 100 text money t

x 200/15=20Set the ball y 200/3=66Set Water 200/2=100int sum = 0;for (int x = 1; x {for (int y = 1; y {for (int z = 1; z {if (15*x+3*y+2*z==200){sum++;Console.WriteLine ("Badminton Racket" +x+ ", Ball" +y+ ", Water" +z+ "bottle");}}}} Console.WriteLine (sum);Console.ReadLine ();CaseHundred Chicken Hundred Money: The Rooster 2 text Money One, the hen 1 money one, the chicken half article money one,A total of only 100 cents, how to gather enough 100 ch

PHP exercise (2) program 6. question: If a person has 100,000 yuan in cash, he needs to pay 50,000 yuan each time he passes through an intersection, if the cash value is less than or equal to 50,000, 5,000 is paid each time. ask how many times this person can pass through this intersection. 1 $ money100000; 2 $ i0; 3 while ($ money gt; 5000) {4i PHP exercise (2) Program 6.Question:Assume that a person has 100,000 yuan in cash and must pay 50,000 yuan each time after the intersection. if the ca