ruckus 1100

smallest legal $f[m][k] (f[m][k]!=-1) $.Because $f[m][k]=\sum a[i]+\sum b[i]$$k =\sum a[i]-\sum b[i]$So the answer to the $\sum a[i]= (f[m][k]+k)/2$$\sum b[i]= (f[m][k]-k)/2$Finally, the output of the scheme is traced forward with the $path$ array, and the previous selection of $path[j][k]$ is $path[j-1][k-v[path[j][k]]]$.The resulting scenarios are sorted out. To avoid negative numbers the following table, to move the second dimensional plane, pay attention to the details.1#include 2#include 3

string T.1≤t≤100Each character of S, T would be between ' a ' and ' Z '.1≤length of String s≤10001≤length of String t≤1000OutputFor each set of test data, the output is yes, or no.Sample Input2RrrjjRrrjRjJrSample OutputYesNoHintThe first example of a topic:First box of sweets: Rrrjj, RRJJ, RJJ, RJSecond box of Sweets: RJ RRRJ-RRJAnalysis: I think it is a string match, and then test instructions understand the wrong, and then began to write new, see this sentence "two consecutive same category o

On three nodes, configure the Hosts file, both the new node and the original node are configured for the same12.16.10.5 Rac112.16.10.6 RAC212.16.10.4 RAC312.16.10.7 RAC1-VIP12.16.10.8 RAC2-VIP12.16.10.5 RAC3-VIP12.16.12.5 Rac1-priv12.16.12.6 Rac2-priv12.16.12.4 Rac3-priv12.16.10.9 ScanFind the UID and GID of 1 nodes and 2 nodes (enter ID at the corresponding user to view or ID UID=1200 (Oracle) gid=1000 (oinstall) groups=1000 (Oinstall), (DBA), 1201 (Oper), 1300 (ASMDBA)Uid=

RTP (H264) First package (single NAL unit mode) ————-SPS 80{v=10,p=0,x=0,cc=0000}60{m=0,pt=110 0000}5370{Sequence Number}9A FC AF27{timestamp}69 25 77 {ssrc} 67 4 d 40 33 54 0c 04 B4 20 00 00 03 00 00 00 0 c D1 E3 06 54 (SPS H264) RTP (H264) second package (single NAL unit mode) ——— PPS 80 {V=10,p=0,x=0,cc=0000} 60 {m=0,pt=110 0000} 53 71{sequence number} 9A FC AF 27 {timestamp} 69 25 77 65 {ssrc} 68 EE 3C 80 {pps H264}RTP (H264) 3rd packet (fu-a) ———— data 80 {v=10,p=0,x=0,C

required for a Chinese character, but some Chinese characters are written after 3 strokes, in this case, a fixed stroke is needed for filling, (And); alignment of two binary values. consider 1 as true and 0 as false. perform the parallel operation on each bit, for example; 12 = 0000 1100 5 = 0000 0101 12 5 = 0000 0100 = 4 | (Or); alignment of the two binary values. consider 1 as true and 0 as false. perform or operations on each bit, for examp

*/ . Quad 0x00cf9200000ffff/* 0x18 kernel 4 GB data at 0x00000000 */ . Quad 0x00cffa00000ffff/* 0x23 user 4 GB code at 0x00000000 */ . Quad 0x00cff200000ffff/* 0x2b user 4 GB data at 0x00000000 */ The first and second items in the GDT table are not required. The third and fifth items correspond to the values of the previous four register segments. Expand the content of the four descriptions: K_CS: 0000 0000 1100 1111 1001 1010 0000 0000 0000 0000 000

[Original question link] Http://acm.pku.edu.cn/JudgeOnline/problem? Id = 1260 [Topic] I want to buy several kinds of valuable pearls, but I have to pay 10 more for a pearl, and if I want to buy 100 pearls worth 1, I have to pay 110 yuan. A pearl can be filled with pearls that are more expensive than it. Therefore, it may be more cost-effective to replace them cheaply when you buy a variety of pearls. For example, if you buy 100 products with a value of 2 and 1 value of 1, then the best

of magnitude and still uses the above method to process large numbers. #include #include #include using namespace std;long long a[1100][110],b[1100][110],inf;int main(){ int n,k,i,j; for(inf=1,i=0;i In fact, we can also optimize the space, look at this formula a [I] [j] = a [I] [j-1] + a [I-j] [j] we found that, if the

"; var file = url. substring (url. lastIndexOf ('/') + 1); alert (file );Javascript bitwise Operator | Yes or operatorThe basic principle of the or operation is: if the bits corresponding to two numbers are 1 or one of them is 1, the result is 1. If both are 0, the result is 0.For example:For example1000 for everyone in 8Then 4 | 8 is 1100To convert to a 10-digit system, the value is 12.It can be understood in plain terms, or operations can overlay the two states, for example0100 stands for brav

Bitwise AND operator (A B) output result 12, binary explanation: 0000 1100 | Bitwise OR operator (A | B) output result 61, binary explanation: 0011 1101 ^ Bitwise OR operator (A ^ B) output result 49, binary explanation: 0011 0001 ~ Bitwise Inverse Operator (~ A) output result-61, binary explanation: 1100 0011, in the form of a signed binary num

-minus 1), + (take positive),-(take negative)2. binocular: +,-, *,/, %3. Category 3 :? : For example, a> B? A: BIii. Relational OPERATOR: --- return result true/false1. equal to the symbol: =2. Not equal to the symbol :! =3. Greater than the symbol:>4. Less than symbol: 5. symbol greater than or equal to:> =6. less than or equal to the symbol: Iv. Logical OPERATOR: -- return result true/false1. And (): false Short Circuit2. Or (|): True short circuit3. Non (!) :V. bitwise OPERATOR: -- convert th