A simple shell that collects multiple services using the Logback jar package, different services use different ports, different instances of the same service use the same port, service name and port mappings are stored in the App.list
App.list, Support # annotations
# app List
# Asset port at 570x
#asset-www 5701
#asset-api 5702
asset-m 5703
# Asset-admin 5704
# Peer port at 560x
P2p-core 5600
# MS ports at 580x
ms-www
5801 Ms-api 58
can also draw SVG rectangles with rounded corners. The rx and ry attributes are used to determine the size of the rounded corner of a rectangle. The rx attribute determines the width of the rounded corner, and the ry attribute determines the width of the rounded corner. In the following example, the rounded corners of the three rectangles are set to 5 pixels, 10 pixels, and 15 pixels respectively. Observe
Line sequence of RJ45 plug
568a Standard
Pin sequence media direct connection signal color
1 Tx + (transmission) white green
2 TX-(Transport) Green
3 RX + (receive) White orange
4. Do not use blue
5. Do not use white or blue
6 RX-(receive) Orange
7. Do not use white Brown
8. Do not use brown
568b StandardPin sequence media direct connection signal color1 Tx + (transmission white orange2 TX-(Transport) O
:
/* Cur_rx is the next buffer pointer to be transmitted. if the cur_rx pointer is greater than dirty_rx, each Transport buffer in the rx-ring that has been opened in the rx-ring is exhausted, in this case, you need to call refill_rx_ring to open up a new buffer for some rx-ring receiving units that have submitted data to the network layer, increase the dir
It's probably called multiplication Floyd?Obviously up to 200 points ... f[i][j][k] represents the smallest distance from J to K, taking the 2^i step. It's just a random shift.The query is to get up the n bits that are 1.1#include 2#include 3#include 4#include 5#include 6 #definell Long Long7 #defineull unsigned long Long8 #defineD Double9 using namespacestd;Ten Const intmaxn=1023, inf=1002333333; One structmat{intf[202][202];} F,c; A intid[1023]; - inti,j,k,n,m,cnt,st,ed; - the intRA,FH;CharRx
The conclusion is that: Move the characters in string A to the nearest occurrence of this character in string B to be optimal ...Find the character at each position in a string, and then where to move it. Then ask for a wave of reverse order is the answer.1#include 2#include 3#include 4#include 5 #definell Long Long6 #defineD Double7 using namespacestd;8 Const intmaxn=1000023;9 intpos[ -][MAXN],T[MAXN];Ten intnum[ -],top[ -]; One inti,j,k,n,m; A ll ans; - CharS1[MAXN],S2[MAXN]; - the intRA,FH;
Finally filled in this million-years giant pit .... I have heard of this problem since second day ... And never dared to write Qaq.It's not very annoying now (but I'm still writing trouble.)Discretization of a wave, pre-processing the number of combinations of what?To maintain the number of legitimate scenarios for the current row, above and below the nodes of each column.Then for the current line on the two adjacent evergreen tree, the left and right of the legal scheme number, multiply the mid
network stop // stop a network service
Service network restart // restart the network service
Service network status // view the network service status
Ifconfig eth0 192.168.10.222 netmask 255.255.255.0 // temporarily modify the interface IP address (no need to restart the interface)
[Yeger @ yeger ~] $ Sudo ifconfig wlan0 192.168.21.199 netmask 255.255.255.0
[Yeger @ yeger ~] $ Ifconfig wlan0
Wlan0 Link encap: Ethernet HWaddr 00: 02: 72: 77: BB: D1
Inet addr: 192.168.21.199 Bcast: 192.168.21
Use heap maintenance doubly linked list to greedy ...The data range obviously does not allow O (nm) of the dp>_Probably think of greedy mess ... Initially want to greedy through a few small negative numbers to connect a positive number into a paragraph, but in the end is to join or directly throw away bad judgmentThen I ran to the puzzle ... The solving is very good, even I have read >_Although the choice of positive and negative values is different, the actual operation is to combine the number
(...).subscribe(fn, fn, fn) pieces, Let the jquery youths confused.It is always bad to be out of the woods, when the birds in the forest are talking about FRP, we should also keep up with:
Reactivex is the abbreviation for reactive extensions, generally abbreviated as RX, originally an extension of LINQ, developed by Microsoft architect Erik Meijer led team, open source in November 2012, RX is a pr
Using nicstat to view the NIC status I previously used scripts to implement Xml code for real-time Nic traffic #! /Bin/bash NAME = nic_flow PIDFILE =/var/tmp/$ NAME. pid LOGFILE =/var/tmp/$ NAME. log function start () {if [-f "$ PIDFILE"]; then echo $ PIDFILE exit 2 fi ((;;)); do eth = $1 [-z "$ {eth:-}"] eth = eth0 time_range = $2 [-z "$ {time_range: -} "] amp; time_range = 1 ifconfig | awk '{print $1}' | grep" eth ">/dev/null [$? -Gt 0] echo "wrong NIC device" exit 10 RX_1 =_1 (cat/proc/ne
Example, in the CentOS test
First look at the results after the test
Code
# vi/etc/rc.d/traffic_monitor.sh
----------------------------------------------
#!/bin/bash
Path=/bin:/usr/bin:/sbin:/usr/sbin:/usr/local/bin:/usr/local/sbin;
Export PATH
function Traffic_monitor {
os_name=$ (sed-n ' 1p '/etc/issue)
While ["1"]
Todo
# The name of the network port
Eth=$1
# status
status= "Fine"
# Get the current time the network port to receive and send traffic
rxpre=$ (Cat/proc/net/
Using nicstat to view the NIC status I previously used scripts to implement Xml code for real-time Nic traffic #! /Bin/bashNAMEnic_flowPIDFILE/var/tmp/$ NAME. pidLOGFILE/var/tmp/$ NAME. logfunctionstart () {if [-f quot; $ PIDFILE quot;]... using nicstat to view the NIC status I previously used scripts to implement Xml code for real-time Nic traffic #! /Bin/bash NAME = nic_flow PIDFILE =/var/tmp/$ NAME. pid LOGFILE =/var/tmp/$ NAME. log function start () {if [-f "$ PIDFILE"]; then echo $ PIDFIL
Memory search, force double can be too ... The data is simply.1#include 2#include 3#include 4#include 5#include 6 #defineLD double7 using namespacestd;8 Const intmaxn=1023, maxm=10023;9 ConstLD eps=1e-8;Ten structzs{intToo,pre;ld v;} e[maxm1];intTOT,LAST[MAXN]; One BOOLU[MAXN]; A ld VAL[MAXN]; - intI,j,k,n,m,ans; - BOOLFlag; the - intRA,FH;CharRx; -InlineintRead () { -Rx=getchar (), ra=0, fh=1; + while((rx
At first I thought it was 2-sat. QaqMembrane of the following: After discretization of each of the answers, the connection between each logarithm and the answer is to see if the maximum number of matches equals n1#include 2#include 3#include 4#include 5 #definell Long Long6 using namespacestd;7 Const intmaxn=25232;8 structZs1{ll v;intID;} A[MAXN];9ll B[MAXN];intcnt,n1;Ten structzs{ One intToo,pre;BOOLflow; A}e[233333];intTOT,LAST[MAXN]; - ShortDIS[MAXN]; - intDL[MAXN],X[MAXN],Y[MAXN]; the i
Slope optimization: Because the variance is required by m^2 ... that is, the sum of squares of each distance and the mean and multiply M.F[I][J] Indicates the minimum sum of squares of J-sections after I am gone.To find the least squares and then multiply by a M is ok = =Need to be careful, can stay in situ ...1#include 2#include 3#include 4#include 5#include 6 #defineD Double7 #definell Long Long8 using namespacestd;9 Const intmaxn=3023;Ten intI,j,k,n,m,now,pre,l,r; One ll PR[MAXN],V[MAXN]; A i
It is clear that the minimum distance traveled by the DFS sequence is the total distance.If not modified, it is actually a virtual tree.Now that the changes have been brought ... In fact, it is the DFS sequence that maintains the key points.It's good to maintain a balance tree, which involves inserting, deleting, finding the predecessor, and finding the maximum minimum value.It's a two-point journey and an LCA.(So this problem becomes treap full board ...)1#include 2#include 3#include 4#include
corresponding F array together (recorded as G).The final answer is max{G[0][i]}, (I is the node on the automaton.)Time complexity O (N^3*LOGL): CF evaluation Maggie Fast. Only ran the 1200+ms.1#include 2#include 3#include 4#include 5#include 6 #definell Long Long7 #defineull unsigned long Long8 #defineD Double9 using namespacestd;Ten Const intmaxn=203; One Constll inf= (1ll +)-1ll; A intch[maxn][ -],next[maxn][ -],tot; - intDL[MAXN],FAIL[MAXN],VAL[MAXN],V[MAXN]; -ll f[maxn][ A][maxn],g[maxn][2]
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