= S.startswith (' B ', 3,5) #索引都是顾头不顾尾# Print (S7)#strip Remove the first space, tab \ t, line break.# S8 = S.strip ()# Print (S8)# NAME = input (' >>> '). Strip () write the project must add strip# if Name = = ' Oldboy ':# Print (' Login successful ')#不仅仅是去除空格等, the specified element is removed until a non-specified element appears# Lstrip () rstrip (0) Remove the left or right side only# #split (
. If we are to repeat the shuffling again, the result would be be:c1, H5, S3, J2 , D13.Input Specification:The Each input file contains the one test case. For each case, the first line contains a positive integer kkk (≤20\le 20≤20) which is the number of repeat Times. Then the next line contains the given order. All the numbers in a line is separated by a space. Output Specification:For each test case, print the shuffling results on one line. All the cards is separated by a space,
cards:s3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result would be:j2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result would be be:c1, H5, S3, J2, D13.Input Specification:Each input file contains the one test case. For each case, the first line contains a positive an integer K (Output Specification:For each test case, print the shuffling results on one line. All the cards is separated by a space, and there must is no extra space at the end of the lin
skb,skb in a domain called Control_buffer, that is, SKB->CB, is a 48-byte memory area, this area is designed to store some private data in each layer of the protocol stack, when the packets are passed between different layers, such as from the network layer to the link layer, the data of this domain is useless, can safely be written to the new data by the link layer, Link layer in the data packet to the physical layer to send, you need to specify a number of parameters, such as the packet to us
front of its arguments, this is a variable positional parameter, and a two asterisk * * indicates a variable keyword parameter.defFoo (*args, * *kwarg): forIteminchargs:PrintItem forKvinchKwarg.items ():Printk,vPrint30*'='if __name__=='__main__': foo (1, 2, 3, a=4, b=5) foo (2, 3, a=4, b=5, c=1)The output is as follows:" C:/python s8/develops/day 2 control statement/asterisk usage. PY "12345**************************************************2345 1***
In the "Query algorithm" and "associated place names and sites," two articles, has been implemented through the name or site route query algorithm, but in reality, from the beginning to the end of the journey is not necessarily the whole ride, for example, there are the following 3 routes:
R1:s1->s2->s3->s4->s5
R2:s6->s7->s2->s8
R3:s8->s9->s10
If you want to S1 from the site to S7, if you use inquiry qu
There are a lot of WLAN and Eutran switch types, the main distinction is a variety of interfaces (such as S2A, S2B, S5, S8), as well as various ways (such as PMIPV6, PIMIP) but for the interface, the basic is the same (I am the terminal test, so the basic value of attention to the interface message)
Example: Handover fromtrusted or untrusted non-3gpp IP Access to E-utran with PMIPv6 ons2a or S2B and GTP on S5/S8
= S.class }) 3.distinct Remove the duplicate 1 Query teachers All units are not duplicates of the depart column.2 SELECT distinct depart from teacher3 Linq:4 from T in Teachers.distinct ()5 Select T.depart6 Lambda:7 4. Connection query between and 1 query all records in the score table with scores from 60 to 80.2 Select * from score where degree between and 803 Linq:4 from s in Scores5 where S.degree >= S.degree 6 Select S7 LAMBDA:8 Scores.where (9
read nor write access
The locked area of the table.
• Enhancedwrite lock (exclusive lock without cumulating)
Works like a write lock into t that theenhanced write lock also protects from further accesses from
Same transaction.
3. Lock and unlockWhen you use a logical lock to lock table entries, the system automatically writes records to the lock table.When you call the FM to set the lock, if the lock parameters parameter is not specified, the system locks the entire table. Of course, lock para
pthread_mutex_trylock (). No matter which type of lock, it cannot be obtained by two different threads at the same time, you must wait for unlocking. For common locks and adaptive locks, the locker can be any thread in the same process, and the error locks must be unlocked by the locker; otherwise, the EPERM is returned. for nested locks, the document and implementation requirements must be unlocked by the
; Count++; Unlockcourse (Prerequisites, queue, cur, used); } returnCount = =numcourses; } Public voidUnlockcourse (int[] Prerequisites, queueintCurBoolean[] used) { intm =prerequisites.length; for(inti = 0; I ) { //search through BFS must tag the visited element if(Prerequisites[i][cur] = = 1 used[i] = =false) Queue.offer (i); }} The above solution is wrong forfollowing reasons:1. The graph is represented in edges rather than adjacency matrix.
1. Mutual exclusion Lock (volume) and condition variableBy default, mutexes and condition variables are used for inter-thread synchronization, and can be used for inter-process synchronization if they are placed in a shared memory area.1.1 Mutual exclusion Lock1. Overview:Mutexes (mutexes, also known as mutexes), prevent multiple threads from doing read and write operations on a common resource to ensure the integrity of the shared data.To protect critical sections to ensure that only one thread
. Why should we unlock it, think about it. If you don't unlock it, there will be no external permission to modify X and Y. If you want to modify these two values for the other two threads, You need to lock qclock.
After thread 1 is ready, thread 2 will be run. Let's look at the thread function of thread 2. The function is also locked at the beginning, but when pthread_cond_wait of thread 1 is unlocked, it can continue to run, and, after that, it modif
means to release the resources it occupies, the lock is currently open. In Linux, mutex locks do not occupy any resources. Therefore, pthread_mutex_destroy () in linuxthreads has no action except checking the lock status (ebusy is returned when the lock status is locked.
2. mutex lock attributes
The mutex lock attribute is specified when the lock is created. There is only one lock type attribute in the linuxthreads implementation. Different lock types are different when trying to lock a locked
answer is no. This is also illustrated by writing verification code. This gives me a greater interest in the re-entry lock, which is indeed a non-blocking lock. The following code may explain the problem: Four threads are running, and the current status of lock is printed before each running. Wait 5 seconds after running.
Public static Void Main (string [] ARGs) Throws Interruptedexception { Final Executorservice exec = executors. newfixedthreadpool (4 ); Final Reentrantlock loc
The mutex has a reentrant, non-reentrant score. In the C + + standard library, a mutex is used to represent a non-reentrant mutex, and a recursive_mutex is used to represent a reentrant mutex. For these two classes to increase the ability to block threads based on time, there are two new mutex locks: timed_mutex (non-reentrant locks), Recursive_timed_mutex (reentrant locks).Mutexes are used solely for mutual exclusion of shared resources, that is, only one thread can use it at the same time to p
following table:
Macro definition
Function description
Spin_lock_init (Lock)
Initialize the spin lock and set the spin lock to 1, indicating that a resource is available.
Spin_is_locked (Lock)
If the spin lock is set to 1 (unlocked), 0 is returned, otherwise 1 is returned.
Spin_unlock_wait (Lock)
Wait until the spin lock is unlocked
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