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Topic Say you has an array for which the I-th element is the price of a given-stock on day I. If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit. Method It is similar to finding the maximum and minimum values in an array at the same time. Constraints: The minimum value can only be preceded by the maximum value. 1. First initi

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Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.We solve the problem by examples:Suppose the input array is: [2, 1, 3, 4, 5, 4].Then, the corresponding diagram is as the following:5/ \4/4/ \ /3 32/\ /1So, what we actually has to does is to find the difference val

An extension of the best time to Buy and Sell Stock III. The idea was still to use dynamic programming (see here for detailed introduction). However, in this problem, some trick (the quickprofit function below) are required to pass the TLE.The code is rewritten below.1 classSolution {2 Public:3 intMaxprofit (intK, vectorint>prices) {4 intn =prices.size ();5 if(k >= N/2)returnQuickprofit (prices);6vectorint> > dp (k +1, vectorint>

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).1 Public classSolution {2 Public intMaxprofit (int[] prices) {3 if(prices.length) {4 return0;5 }6 7 int[] left =New int[prices.length];8

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analyse:dp[i] = max (dp[i-1], prices[i]-lowest[0,..., i-1]).Runtime:8ms.1 classSolution {2 Public:3 intMaxprofit (vectorint>prices) {4 Const intn =prices.size ();5 if(n = =0)return 0;6 7

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit. Public classSolution { Public intMaxprofit (int[] prices) { if(Prices.length = = 0) return0; intProfit = 0; intMin = prices[0]; for(inti=0;i){ if(prices[i]min) {min=prices[i];//keep tr

best time to Buy and Sell Stock IIIProblem:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Ideas:Dynamic planningMy Code: Public classSolution { Public intMaxprofit (int[] prices) { if(Prices = =NULL|| Prices.length return0; intSize =prices.length; int[] left =New int[size]; int[] right =New int[size]; intMin = prices[0];

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Problem:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Hide TagsArray Dynamic ProgrammingTest instructions: Given a stock price list, there is a maximum of both hands trading, seeking maximum profit. A very classical algorith

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again). Public classSolution { Public intMaxprofit (int[] prices) { /*each point in the entire interval is cut, then the maximum values of the left and right sub-intervals are co

Original title address: https://leetcode.com/problems/best-time-to-buy-and-sell-stock/The content is in the code and comments, it is not wordy.Class Solution {Public:int Maxprofit (vectorbest time to Buy and Sell Stock--leetcode

Given a vector, the vector represents the price of a stock in the first day, Y to make the stock yield the largest should be bought on the day I, the first i+n days to sell, to find out the value of the maximum profit is how muchIdea: Record the minimum value with a variable, a variable record the maximum benefit, scan the price from beginning to end, when scanning to the price of the day I, if the price is smaller than the minimum value, then replace

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Problem Description:Say you has an array for which the i-th element is the price of a given-stock on dayI.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Basic idea:Dynamic Planning method‘‘‘// f[k, ii] represents the max profit up until prices[ii] (Note: NOT ending with prices[ii]) using at most k transactions.

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Title:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.idea: A single scan can be. You just need to find the maximum growth . Max (prices[j]–prices[i]), I From the point of travel, the current price minus the previous lowest price is the maximum profit that can b

Title Link: click~/* Test instructions: An array, the element I represents the price of the stock of day I, allow up to two times to buy and sell, for maximum profit *//** * idea: Record the maximum profit of the day with the Currprofit array, scan the array from start to finish to get the * Currprofit = max (Currpor Fit[i], prices[i]-low) * * Record the maximum profit after the day with a futureprofit array, from the tail to the end of the scan can b

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