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Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Topic Analysis:When doing, want to use dynamic planning to do, at that time do not write a better expression of the recursive style. Because there is a relationship between the maximum value and the minimum value: W

188 best time to Buy and Sell Stock IVThis question is the best I've ever had to look at the way I've run out of all the Python solutions.classSolution:def __init__(self): Self.start=0 Self.end=0 Self.ans=0 SELF.P= [] defMaxprofit (self, k, prices): I= 1ifLen (prices) : return0 whileI Len (Prices): Self.p.append (Prices[i]-Prices[i-1]) I+ = 1ifK >=Len (SELF.P):returnSUM ([x forXinchSelf.pifX >0]) J=0 whileJ K:ret=Self.getprofit ()ifR

Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Ideas:1. The transaction is similar to the practice of trading once, simply split the array into two arrays, and then calculate the maximum value of two array transactions

Say you had an array for which the ith element was the price of a given stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.This is very intuitive, the direct difference between the highest value on the line, the start of the tle once, because the use of O (n^2)method, and later found O (n) to be able.The first code:classSolution { Publi

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.First, the problem is converted to a mathematical language: array a[n], and for any i The results can be obtained using O (n^2) method.The following dynamic planning methods are analyzed:For input prices[n], if know

Title: Given an array of shapes, indicating stock movements, stocks can buy and sell at random times. The maximum profit that can be savedAlgorithm: the equivalent of the rise in the stock trend sumFor example: Stock trend: 1,1,3,2,5,7,1,3,2,0. The maximum profit is (3-1) + (5-2) + (7-5) + (3-1) =9public class Solution {public int maxprofit (int[] prices) { if (0 = = prices.length) { //Empty array Retu RN 0; } int maxprofile

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. Transactions at the most K.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Credits:Special thanks to @Freezen for adding this problem and creating all test cases.Analyse:assume Global[i][j] represents the maximum profit at day I with J transactions, Local [I][j]

Say you has an array for which the i t H element is the price of a given stock on day i .Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Thinking of solving problemsCreate two arrays left and right store the maximum benefits that can be obtained from the left and r

title :Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.1 Public classSolution {2 Public intMaxprofit (int[] prices)3 {4 intMaxprofit=0;5 intMinelement= integer.max_value;6 for(inti=0;i)7 {8Minelement=math.min (Minelement

Three types of stock trading algorithmsFirst, there is no limit to the number of transactionsUse greedy strategy to find the longest increment sequence and accumulate the corresponding profit.Second, only one transactionUsing the dynamic programming algorithm, the minimum price before the corresponding time node is recorded from the point of travel, and the maximum profit at this node is obtained while the minimum price is updated.Three, up to two timesUse two-time dynamic planning1, from left t

Only every time I look at this picture of the C + + does not have a white learning AH ~ ~ ~ usually with the time of the different Miss Eclipse, all kinds of nostalgia java~~~ This is the biggest profit, originally I think is to find the minimum and maximum, the difference is not the maximum profit, and then think, the minimum may be after the maximum value, can not be said to buy back in number 3rd to sell the stock and then think, record the m

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Solution 1:Find each minimum, find a maximum value after each minimum, and calculate the maximum benefit. Compare each of the maximum benefits. Public classSolution { Public intMaxprofit (int[] prices) { if(P

Idea: Add two of the largest profit, the maximum profit of a period is not necessarily only in one rise period, for example, there are two ascending intervals between the Green Line As long as the maximum profit before I is calculated and the maximum profit after I is added, because I cannot be a peak or a valley value at the same time, it is guaranteed not to buy and sell on the same day The Green Line profit plus the red line profit is the biggest

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analysis: Greedy algorithm. Record the minimum value of the price that appears earlier, and then update the maximum benefit with Max (Maxprofit, Prices[i]-min). The code is as follows:classSolution { Public: intM

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Example 1:Input: [7, 1, 5, 3, 6, 4]output:5max. difference = 6-1 = 5 (Not 7-1 = 6, as selling-price needs-be-larger than buying price)Example 2:Input: [7, 6, 4, 3, 1]output:0in this case, no transaction was done, i.

Dry Wine If you sell the recursive algorithmRemember that old song, if the wine is not sold, it contains a story of how bitter. Life is not easy, thrift resources recovery and reuse it!Children's winter vacation homework has not been done, there must be so that adults are blindfolded, the computer's liquor that is seconds to kill millions of bottles!Topic: Beer 2 yuan 1 bottles, 4 caps for a bottle, 2 empty bottles for 1 bottles Q: How ma

Source of the topic:https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iii/ Test Instructions Analysis:Similar to the above question, Array[i] represents the price of items for the first day, if only 2 times can be traded. Ask for maximum profit. Topic Ideas:This is a dynamic planning issue. It is not difficult to think of splitting the entire array into two parts. Then use two arrays First,second respectively array[:i] and arra

Title Link: Http://codeforces.com/contest/810/problem/BTest instructions: Given the number of days and the number of days the goods can be doubled, every day there is a certain amount of goods and the number of customers, ask how the goods can sell the most (the day before the goods will not be left to the next, each customer can only buy one goods).Simple greedy question, greedy strategy is: if two times the volume of goods sold out more, choose twic