In front of the second multi-threaded fourth a classic multi-threaded synchronization problem, proposed a classic multi-threaded synchronization mutex problem, This problem includes the main thread and Sub-thread synchronization, Sub-thread Mutual exclusion, is a very classic multi-threaded synchronization mutex problem example, followed by four"second-kill multithreaded fifth" Classic thread synchronization key section CS"second-kill multithreaded sixth" Classic thread synchronization events ev
being preempted), or acquiring a lock and reopening the preemption again.Preempt_disable ();Kernel configuration option, currently the kernel default configuration#ifdef Config_mutex_spin_on_ownerThe following is an important note in the source code, and the core point is the realistic basis on which the mutex optimization is based: a process that obtains a mutex is extremely likely to release it in a very short period of time. So unlike the implementation of
Programming in linux: semaphore and linuxsemaphore
Thread Synchronization-semaphores (semaphore)Reflections on producer and consumer issues
In real life, as long as there is a commodity, consumers can consume it. This is no problem. However, the production of producers is not infinite. For example, warehouses are limited, raw materials are limited, and production indicators are restricted by consumption ind
cyclicbarrier A synchronization helper class that allows a set of threads to wait until a common barrier point is reached. In programs that involve a set of fixed-size threads, these threads must wait for each other at a time. Package Org.github.lujiango;import Java.util.concurrent.brokenbarrierexception;import Java.util.concurrent.cyclicbarrier;import Java.util.concurrent.executorservice;import Java.util.concurrent.executors;import Java.util.concurrent.timeunit;public class Test16 {publ
(); +System.out.println ("2 sub-threads have been executed"); ASystem.out.println ("Continue with the main thread"); the}Catch(interruptedexception e) { + e.printstacktrace (); - } $ } $ - -}The results of the implementation are as follows:1 child thread thread-0 executing 2 waiting for 2 child threads to finish ... 3 Child thread thread-1 executing 4 child thread thread-0 execution completed 5 child thread thread-1 executed 6 2 Sub-threads have been executed 7 Continue with the
Semaphore, that is, the meaning of the semaphore. is the kernel synchronization object originally provided by the operating system.New Semaphore (23, "Semaphore1");Explain the meaning:The first parameter is: Initialcount, which means the initial quantity. Semaphore This object is used: the WaitOne () method blocks dire
Semaphore is a class under system.threading that restricts the number of threads that can access a resource or resource pool at the same time.Common construction methodshttps://msdn.microsoft.com/zh-cn/library/e1hct27h (v=vs.110). aspxPublic Semaphore (int initialcount,int maximumcount)Parameters
Initialcount
Type:
System.Int32
The number of initial requests for the
Link: http://hi.baidu.com/reversefish/blog/item/7e2ddb1e4f11a11740341716.html
Control Methods for mutual exclusion of four processes or threads1. critical section: accesses public resources or code segments through multi-thread serialization, which is fast and suitable for controlling data access.2. mutex: designed to coordinate separate access to a shared resource.3. semaphore: designed to control a limited number of user resources.4. Event: it is u
Next, we will continue to discuss how to use pthread_cond_t to implement sem_t. Currently, the Linux kernel supports sem_t, but some old OS such as aix4 and earlier Solaris do not support semaphores. After all, semaphore is not included in the POSIX standard. In this case, it is necessary to use pthread_mutex_t + pthread_cond_t to simulate semaphore. (What? Pthread_mutex_t pthread_cond_t is not supported ei
Process Lock:
Why should have process lock: If now have a printer, QQ to use printer, Word document also want to use printer, if not using process lock, may cause some problems, such as QQ task Print to half, word inserted, so print out the result is the respective half.
Process lock creation and use:
1. Import module, from multiprocessing import Lock
2. Create lock object: Lock=lock ()
3. Where the lock is needed: Lock.acquire ()
4. In place of release: Loc
Semaphore is another way to implement synchronization after JDK1.5. Semaphore can maintain the number of threads currently accessing itself and provides a synchronization mechanism. Use semaphore to control the number of threads concurrently accessing resources. If you have 3 resources, there are 10 threads to use the resource, and only 3 threads are used, so the
Http://www.cnblogs.com/maxupeng/archive/2011/07/21/2112282.htmlOne, mutex (mutex)The mutex is essentially a lock that locks the mutex before accessing the shared resource, releasing the lock on the mutex after the access is complete.When the mutex is locked, any other thread that attempts to lock the mutex again will be blocked until the current thread releases the mutex. If multiple threads are blocked when a mutex is released, all blocked threads in the mutex become operational, the first thre
When Semaphore semaphores are used, it is useful for fair scheduling. When multiple threads can be controlled to compete for resources, the maximum number of threads can be executed. The code is tested by hand as follows:Note:1. acquire () to obtain a license. If not, wait.2. release a license for release ()3. Semaphore can control the number of resources that can be accessed at the same time. The number of
Consider this scenario: a parking lot only contains a certain number of parking spaces, and only when there is space in the parking lot, the entry of the parking lot will open. C # provides the semaphore class to handle this scenario. The semaphore class can specify the number of resources during construction. The waitone method is used to wait for a resource and the release method is used to release a reso
Original blog, reproduced please indicate the sourceHttp://blog.csdn.net/hello_hwc?viewmode=contentsWhat is the semaphore?The simple thing is to control the number of access resources, such as the system has two resources can be exploited, while there are three threads to access, can only allow two threads access, the third should wait for resources to be released before access.Note: In the GCD, only the scheduled thread will enter the kernel state fo
A count semaphore. Conceptually, semaphores maintain a set of licenses. If necessary, block each acquire () before the license is available, and then obtain the license. Each release () adds a license that may release a blocked fetch. However, instead of using the actual license object, Semaphore only counts the number of available licenses and takes action accordingly. The thread that gets the
In a driver, when multiple threads access the same resource at the same time (a global variable in the driver is a typical shared resource), "race" may be thrown, so we must have concurrent control over the shared resource. The most common way to solve concurrency control in the Linux kernel is to spin the lock and Semaphore (most of the time as a mutex). Spin lock and semaphore "similar but not class", sim
The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion;
products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the
content of the page makes you feel confusing, please write us an email, we will handle the problem
within 5 days after receiving your email.
If you find any instances of plagiarism from the community, please send an email to:
info-contact@alibabacloud.com
and provide relevant evidence. A staff member will contact you within 5 working days.