showcase idx

, end) assigns the elements of the range [beg, end)C1.swap (C2) swaps the data of C1 and C2Swap (C1, C2) same (as global function)Table 6.5. Direct element access of vectors operation effectC. At (idx) returns the element with index idx (throws range error exception if idx is out of range)C [idx] returns the element wi

function to plot% the progress of k-means[centroids, idx] = Runkmeans (X, Initial_centroids , Max_iters, True); fprintf (' \nk-means done.\n\n ');K-means Clustering Algorithm Core code:function [Centroids, idx] = Runkmeans (X, Initial_centroids, ... Max_iters, plot_progress) [m n] = size (X); K = Size (initial_centroids, 1); centroids = Initial_centroids;previous_centro

Linear_model From Sklearn import tree From Sklearn.metrics import Confusion_matrix X_min, X_max = 0, Y_min, Y_max = 0, ten Step =. 1 # to plot the boundary, we ' re going to create a matrix of every possible point # then label each point as a wolf or cow using our classifier xx, yy = Np.meshgrid (Np.arange (x_min, X_max, Step), Np.arange (y_min, Y_max, Step)) DF = PD. DataFrame (data={' x ': Xx.ravel (), ' Y ': Yy.ravel ()}) df[' color_gauge ' = (df.x-7.5) **

Idx=1sum=0 while idx: sum=idx+sum idx=idx+1 Print (' sum = ', sum)======================== restart:d:/pythondata/11.py ========================Sum 100 = 5050Idx=1sum=0 while idx: sum=

,f2,l,d, representing the distance from the node F1 to F2 to L,d as ' e/w/s/n ', representing the F1→F2 is the east/West/south/north;Now there is a person to ask for K, each query contains F1,f2,idx, which represents the distance between the querying node F1 and F2, this query occurs after the input of the data of the IDX (that is, the second idx+1 of the data ar

This example describes how JavaScript converts numbers to uppercase Chinese. Share to everyone for your reference. The implementation methods are as follows: function Inttochinese (str) { str = str+ '; var len = str.length-1; var idxs = [', ' ten ', ' hundred ', ' thousand ', ' million ', ' ten ', ' hundred ', ' thousand ', ' billion ', ' ten ', ' hundred ', ' thousand ', ' million ', ' ten ', ' hundred ', ' thousand ', ' billion ']; var num = [' 0 ', ' one ', ' II ', ' San ', ' Restaur

Importjava.util.arrays;publicclasscollection_4_23_01{publicstaticvoid main (String[]args) {/** container **/arraylist_pyarraylist_py1 =newarraylist_py (); Arraylist_py1.add ("Ppyy"); Arraylist_py1.add ("Ooii"); Arraylist_py1.add ("Xxqq"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist_py1.add ("Qqxx"); Arraylist

consumption;Instance scenario:1>. System various role permission assignment;2>. The system appears many kinds of states, or the combination state needs corresponding, and this correspondence, can occur very many other types of objects above, you can use the enjoy meta-mode;Example Source: pure (shared) to enjoy the yuan1. Custom JavaScript Hashtable:functionHashtable () { This. Values = [];} Hashtable.prototype.getJson=function() {return This. Values;} Hashtable.prototype.add=function(key, val

preceding code: zval* Array; Alloc_init_zval (array); Z_type_p (array) = Is_array; HashTable *h; Alloc_hashtable (h); Z_arrval_p (array) =h; Zend_hash_init (H, M, Null,zval_ptr_dtor, 0); zval* Barzval; Make_std_zval (Barzval); Zval_string (Barzval, "value", 0); Zend_hash_add (H, "key", 4, barzval, sizeof (zval*), NULL); Convenient array macro operations The kernel provides us with a convenient macro to manage arrays. Add_assoc_* Series functions: Add_assoc_null (Zval *aval, char

//Template water Problem enemy soldier HDU-1166classtreearray{ Public: Const Static intCMAXN = 1e5;///Todo: Modify the maximum value of the interval intCDATE[CMAXN]; intMAX_SZ;//represents the number of elements in init initialization voidInitintsize) {memset (CDate,0,sizeof(CDate)); MAX_SZ= size;//initialize the number of elements in this sample } voidInitintSizeintArray[],intLen) {memcpy (CDate, array,sizeof(int)*Len); MAX_SZ=size; } InlineintLowbit (intIDX) {returnIDX -

Topic description Given an array a[0,1,..., n-1], build an array b[0,1,..., n-1], where the elements in B b[i]=a[0]*a[1]*...*a[i-1]*a[i+1]*...*a[n-1]. Cannot use Division idea: cannot use division, then according to a from top to bottom, from bottom to top connect1 classSolution {2 Public:3vectorint> Multiply (Constvectorint>A) {4vectorint>B;5 if(A.size () 1)returnB;6vectorint>arr1;7vectorint>arr2;8Arr1.push_back (1);9 intsum=1;Ten for(intidx=0; Idx2; ++

the input is empty, then this binary treeis an empty binary tree.else//below prepare to implement element insertion{root = new binodeRoot->data = x; Assigning values to a nodeCreat (Root->lchild, none); Creates the left child of the root node, at which point the number of left dial hand is emptyCreat (Root->rchild, none); Creates the right child of the root node, at which point the right number is empty}//The current node assignment succeeds, and its child creation is also successful} // The se

Java, the following code will not compile: Get the index of the lowest-indexed item on the array //That's > MaxValue for (int i = 0; i In Python, however, the same code always goes smoothly and gets the expected result: For IDX, value in Enumerate (y): if value > Max_value: break processlist (y, idx) This code will work correctly unless the child y is empty, at which poi

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode 031. Next permutation (Medium) link : Title: https://oj.leetcode.com/problems/next-permutation/Code (GitHub): Https://github.com/illuz/leetcode : Find the next permutation of a sequence. Analysis : You can use the STL in the ' next_permutation ' lazy. The specific algorithm is: First of all, starting from the end to look forward to two adjacent elements, so that the first element is I, the seco

;}; Thingy.removeclass = function (name) { var classes = This.className.split (/\s+/); var idx =-1; for (var k = 0; k if (classes[k] = = name) {idx = k; k = classes.length;} } if (idx >-1) { Classes.splice (idx, 1); This.classname = Classes.join ("); } return this; }; Thingy.hasclass = function (name) { Re

Tags: arc sele nvarchar function body Object POS expr style--Returns the string delimited by the nth (1/2/3 ... ) Character Changer Use [EPICOR10] GO /** * * * object:userdefinedfunction [dbo]. [Ah_entry] Script date:2017-12-23 16:30:39 * * * * **/ SETAnsi_nulls on GO SETQuoted_identifier on GO /*changed from: Ice.entry (@idx int, @char_expr nvarchar (max), @delim nchar (1)) Select Ice. Entry (1, ' Http://192.168.0.251/PackInfo/Tiger/FM/TG17/PC/C

conservedDECLARE @Idx intDECLARE @n INT--records data that needs to be inserted every dayDECLARE @m INT--record number of days to executeDECLARE @Doccode varchar (30)Declare @GoodsID char (10)DECLARE @Amount decimal (18,6)DECLARE @BatchNo varchar (40)DECLARE @EffDate datetimeDeclare @StockArea char (2)Declare @Station char (2)Declare @CheckResult char (2)Declare @DoMethod char (2)Declare @MakID char (10)DECLARE @MakDtm datetime-the difference between

1 Topic Description:There is an array: 2,1,4,3. For arrays, there is an operation op (idx): Moves the number corresponding to the index to the first place. Like what:OP (3): 2 1 3 2 1 4OP (1): 3 2 2 3 1 4OP (2): 2 3 1 4, 1 2 3 4Q for a given array, the elements of an array are arbitrary integers, there may be duplicate values, and how many OP operations are required to make the array orderly?For the above example, it takes 3 times.2. Problem Resolutio

)# Endif{Uint8 idx = 0; Osaltimeupdate (); // Update TimeHal_processpoll (); // This replaces mt_serialpoll () and osal_check_timer (). (round-robin of device messages such as uart and timer)Do {If (tasksevents [idx]) // task is highest priority that is ready.{Break;}} While (++ idx If (idx {Uint16 events;Halintstate_

Heap Sort Algorithm Heap-Sort uses Max heap data structure to sort a sequence. The steps are: We need construct a max heap in place firstly, so that we can make sure that the bigest value locates on the first position of the heap. Swap the top value with the last value of the sequence, and shrink the size to nSize-1, and reconstruct the max heap. Swap loopsly and the sequence will be sorted. The key issue is how to present a max heap data structure by an array. # Define left_child_index