singly linked list java

(node.next, node); = prev; return re; }}(3) Recursive Method 2. The last node is found first, then the next point is pointed to the current one from the method body of the node before the last node, and then the node behind it is reversed when the current node is reversed, and no tubes are required. Finally, return to the original last node. Public node Reverse3 (node node) { if(node.next==null)return node; = Node.next; NULL ; = Reverse3 (next); = node; re

The basic operations of a single-linked list include the creation of single-linked lists, lookup operations (search by order and lookup by value), insert operations (pre-and post-interpolation), and delete operations. The following is a specific Java implementation program:Package com.zpp.test;//first creates a node cl

= = Head | | null = = Head.getnextnode ()) {return head;} Node reversedhead = reverse (Head.getnextnode ()); Head.getnextnode (). Setnextnode (head); Head.setnextnode (null); return reversedhead;} /** * Traversal, the next node of the current node is cached after the current node pointer is changed * */public static nodes Reverse2 (node head) {if (null = = head) {return head;} Node pre = head; Node cur = head.getnextnode (); Node next;while (null! = cur) {next = Cur.getnextnode (); Cur.setnextn

Package com.kpp;/** * Single-linked list reverse * Disconnect the single-linked list from the first and second nodes, then 2nd, 3 ... Each node is inserted before the first node in turn * @author KPP * */class lnode{private String data;private lnode Next;} public class Linkedlistreverse {private static void reverse (Ln

When I started to touch Java for a long time, I always feel that the deletion of the Java linked list has its own bug.The first version of the bug:The call i--should be displayed after Removebyforlist.remove (j) is only receivedpublic static void Testremovebyfor () { listThe second version of the bug:First intro

In this paper, according to the "Big talk Data Structure" a book, the implementation of the Java version of the single-linked list .The linear table abstract data type definition in the book is as follows (page 45th):Implementation program:Package linklist;/** * Description: * 1. There is no linear table length in the big talk data structure, but it refers to the

} -Prenode =Curnode; theCurnode =Curnode.next; +i++; A } the return true; + } - $ //return node length $ Public intLength () { - intLength = 0; -Node tmp =head; the while(TMP! =NULL) { -length++;WuyiTMP =Tmp.next; the } - returnlength; Wu } - About $ //to sort a linked list - PublicNode orderlist () { -Node NextNode =

/** * * @authorAdministrator * Function: Drop handkerchief problem*/ PackageCom.litao; Public classDemo4 {/** * @paramargs*/ Public Static voidMain (string[] args) {//TODO auto-generated Method StubCyclink Cyclink =NewCyclink (); Cyclink.setlen (9); Cyclink.createlink (); Cyclink.show (); }}//nodeclasschild{intNo; Child Nextchild=NULL; PublicChild (intNO) { //give a number This. No =No; }}//Ring Linked listcl

Title:Given a binary tree, flatten it to a linked list in-place.For example,Given 1 / 2 5 /\ 3 4 6The flattened tree should look like: 1 2 3 4 5 6Test Instructions:Given a binary tree, it turns itself into a single-linked list.For example, gi

Reverse a linked list from position m to N. Do it in-place and in One-pass.For example:Given 1->2->3->4->5->NULL , m = 2 and n = 4,Return 1->4->3->2->5->NULL .Note:Given m, n satisfy the following condition:1 ≤ m ≤ n ≤length of list.Problem Solving Ideas:Pointer operation, rotate reference Java for Leetcode 025 Reverse Nodes in K-group

Given a linked list, return the node where the cycle begins. If There is no cycle, return null .Follow up:Can you solve it without using extra space?The idea of solving problems is very similar to the above problem, but it is necessary to observe a rule, refer to leetcode:linked List Cycle IIThe Java implementation is

One-way linked list inversion is currently interviewing for a job in the direction of Android applications. Basic knowledge can also, but the algorithm, hehe. Do the basic mobile phone client related algorithms are not many, mostly architecture design, decoupling, as well as functional optimization, Ui,io and so on. Well, the nonsense is not much to say. Get to the point. One-way

The LinkedList class extends Abstractsequentiallist and implements the list interface. It provides a linked table data structure.The LinkedList class supports two constructors. The first constructor establishes an empty list:LinkedList() The following constructor establishes a list of elements initialized with the element in set C.OriginalContents of LL: [A,A2,F,

Down-Stack (linked list implementation):Import Java.util.iterator;public class LinkedstackFIFO Queue (linked list implementation):Import Java.util.iterator;public class Linkedqueue Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Algorithm (fourth edition)

Remove all elements from a linked list of integers, that has value Val.Examplegiven:1 2--and 6--and 3--4--5--and 6, val = 6return:1--and 2--and 3--and 4-- 5Test instructions: Deleting nodes in a linked list/***definitionforsingly-linkedlist.*publicclasslistnode {*intval;*ListNode Next;*listnode (intx) {val=x;}* }*/publ

element, the last is also assigned as Nulllast = null;} First = first.next;//Set next to Firstreturn temp.ddata;//return to the original first}public void Displaylist (){System.out.println ("List (first-->last):"); Link_long current = first;//is used to continuously change the position implementation traversal while (current! = null) {Current.displaylink (); current = Current.next;}}} Class Name: linkqueue//property://Method: Implement Queue class Li

Sort the linked list with insert sortProblem Solving Ideas:The most time-saving method is to use the priority queue, but cannot pass, then insert the order directly. Public ListNode insertionsortlist (ListNode head) {ListNode root = new ListNode (Integer.min_value), while (head! = null) {Li Stnode temp = Root;while (Temp.next! = null head.val >= temp.next.val) temp = temp.next;if (temp.next==null) {T Em

On Weibo, it was said that 8 graduating students did not write the O (1) spatial complexity, O (n) time complexity of the reverse unidirectional linked list.(Not my own thought) Public void reverselist (ListNode head) { null; while NULL ) { = head.next; = Newhead; = head; = next; } return Newhead;}I have thought for a long time, similar to:Head--A->b1.next =

Oops, bad, leetcode another easy question, long time no on, directly on the site A. The problem is to put a linked list upside down ...Public ListNode reverselist (ListNode head) { if (head = = NULL) return null; ListNode prenode = null; ListNode Curnode = head; ListNode nxtnode = Head.next; while (Curnode! = null) { curnode.next = Prenode;

null.The code is as follows:1 Public voidFlatten (TreeNode root) {2TreeNode cur =Root;3 while(cur!=NULL) {4 if(cur.left!=NULL) {5TreeNode leftright =Cur.left;6 while(leftright.right!=NULL)7LeftRight =Leftright.right;8Leftright.right =Cur.right;9Cur.right =Cur.left;TenCur.left =NULL; One } ACur =Cur.right; - } -}Attached: A pre-order traversal approach using the stack implementation:1 Public voidFlatten (TreeNode root) {2StackNe