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.CCC .... ECBCBB. Dcbcdb. DCCC. B.. D.b.abaad. BBBB. Addddad. Ae... Aaaaeeeeee.Sample OutputEdabcSourceSouthern African 2001 Test instructions:a two-dimensional diagram has several frames (four-edged, hollow rectangles with a border surrounded by the same character), and each border character is different. BorderOverlapping , the order of overlap is obtained. 1. Multiple sets of outputs, with indeterminate conditions all output, sorted in dictionary order. 2. The frame in the diagram gives 4 edg

[]temp =New int[Arr.length];//before sorting, build a temporary array of good one length equal to the original array length to avoid frequent space-opening in recursionSort (arr,0,arr.length-1, temp); } Private Static voidSortint[] arr,intLeftintRightint[]temp] { if(leftRight ) { intMid = (left+right)/2; Sort (arr,left,mid,temp);//left-hand sub-sequence ordered by merge orderSort (arr,mid+1,right,temp);//Right merge sort to make right sub sequence orderlyMerge (Arr,left,mid,

generate different objects. Each time one is generated.So the second way to create multiple "abc" strings, in memory in fact there is only one object. This writing is advantageous and saves memory space. At the same time it can improve the speed of the program to some extent, because the JVM will automatically determine whether it is necessary to create new objects based on the actual data in the stack. In the case of string str = new String ("abc"), the code creates a new object in the heap, r

storage structure to do some good for the classifier program to write adjustments. The single-layer decision tree I implemented adaboost specifies that Classifiertype is desicionstump, that is, the basic classifier uses desicionstump, and each weak classifier is a DS object. So the storage structure can be adjusted as shown (for classification functions):By adjusting the number of weak classifiers in the adaboost algorithm, the adaboost classifier with different classification error rates will

1.BlankTest.cpp: Defines the entry point of the console application.Title: Sorting a set of integers in a file and outputting them to another file#include "stdafx.h"#include #include #include using namespace Std;?int _tmain (int argc, _tchar* argv[]){???? Ofstream out ("11.txt", ios::out);???? for (int i = 0; i ???? {???????? int te;???????? Cin >> Te;???????? Out ????}???? Out.close ();????? Ifstream infile ("11.txt", ios::in);???? Vector???? while (!infile.eof ())???? {???????? int temp;??????

target object.How do I implement nesting of multiple proxy objects?Package Agint;import Java.lang.reflect.invocationhandler;import Java.lang.reflect.method;import Java.lang.reflect.proxy;public class Chackvaluehanlder implements invocationhandler{private Object target; public static object Initnextangient (object target) {return proxy.newproxyinstance (Target.getclass (). getClassLoader ( ), Target.getclass (). Getinterfaces (), new Chackvaluehanlder (target);} Public Chackvaluehanlder (Objec

Write a series of classic algorithms to learn together!1. Quick SortBasic idea:1. First remove a number from the series as the base number.2. The partitioning process will place the number of digits above it to the right, less than or equal to its number to the left of it.3. Repeat the second step for the left and right intervals until there is only one number for each interval.On the internet to see a blog, the quick sort of named digging pit Fill +

actual behavior of the kernel stack, user stack, is:To save the current ESP,SS value, set the value of the ESP SS to the appropriate value for the kernel stackthe actual behavior of the user stack, the kernel stack, is:Restore the value of the original ESP SS(6) the user-state ESP and SS are stored in the kernel stack, and this line is automatically completed by the i386 interrupt instruction by the hardware.(7) When the interrupt occurs, the CPU goes into the kernel state, and then does the fo

that mean?The PID of the recently executed command in the background.59) $? What does that mean?The end state of the last command in the foreground.60) How to output the current shell PID?Echo $$61) How do I get the number of arguments passed to the script?Echo $#(LCTT: And the 3rd question repeats.) ）62) What is the difference between $* and [email protected] $*– output all parameters passed to the script as a string [Email protected]– to list all parameters passed to the script i

the occurrence of deadlocks, some restrictions can be imposed on the philosopher's process, such as:At most four philosophers are allowed to dine at the same time;Only when a philosopher on both sides of the chopsticks are available, he was allowed to grab chopsticks;The Philosopher's order number requires the philosopher to grasp the chopsticks on the left and then turn the chopsticks on the right, while the even number philosopher is the opposite.The positive solution rules are as follows: As

three space-separated integers, a_i, b_i, and l_i, indicating that A trail connects land Mark A_i to landmark b_i with length l_i.Output* Line 1: A single integer which is the minimum possible length of the longest segment of the Farmer John ' s route.Sample Input7 9 21 2 22 3 53 7 51 4 14 3 14 5 75 7 11 6 36 7 3Sample Output5HintFarmer John can travel trails 1-2-3-7 and 1-6-7. None of the trails travelled exceeds 5 units in length. It is impossible for Farmer John to travel from 1 to 7 twice w

The basic idea of fast sequencing (divide-and-conquer method): 1. First remove a number from the series as the base number 2. Partitioning process: Put a larger number than the base on its right, small on its left 3. Repeat partition operations on the left and right intervals until there is only one number for each interval Quick-line Java code Packagequicksorttest;ImportJava.util.Scanner; Public classQuicksorttest {Static int[] Array =New int[10]; Public Static voidMain (

After-school exercises the third wave came, to the third chapter after the code and the like a little bit longer, so I put this chapter of the answer into a few parts. This chapter focuses on the processing of strings, for string problems, usually as long as careful there is no problem, the following few said directly on the detailed.Exercise 3-1 Score Statistics (STAT)Task 1: This is straightforward on the code:#include Task 2: This relative task 1 more difficult, one of the questions, in the u

object. Conversely, when Getfullname () is assigned to the test variable, the context refers to the Global Object (window). This is because test is a property that is implicitly set to the global object. For this reason, the function returns the FullName of the window, that is, the value defined in the first row. Question 5:call () and apply ()Now let you solve the previous problem and make the final Console.log () print Aurelio De Rosa. Answer The problem can change the function context by fo

One, the JSP between the value of the garbled problem solvedRequest.setcharacterencoding ("GBK"); // solve Chinese garbled characters // gets the value passed in on the previous pageSecond, if the value passed is a checkbox then the array is used to receive parameters.Request.setcharacterencoding ("GBK"); // solve Chinese garbled characters String showinfo[] = request.getparametervalues ("Insert"); // Insert is the name of the checkboxThird, response object is used to return information to the c

the user name after opening, then click the "Generate Registration" button, click on the "Copy" button to copy the registration code.Figure 4 Generating the registration codePaste the registration code into the Registration code edit box in the Visual Booster Registration window, and fill in the username that you just entered in the keygen. Finally click OK, then successfully completed the registration! As shown in 5.Figure 5 Registration successInstallation registration Good, you can open a pr

are sent when the bridge receives better BPDUs.In addition, it also controls the transmission of BPDUs while "saving optimal BPDUs". When the bridge is first activated, all its ports start to send BPDUs every 2 seconds (if the default timer configuration is used), but if a port receives a BPDU from another bridge and the BPDU is better than the sent BPDU, the local port stops sending BPDUs. If a better BPDU is not sent from an adjacent bridge within a period of time (the default of 20 second

each VLAN can have a different clock value. Cisco has two important hints for using an instance on each VLAN: Allows you to use many excellent features, such as load balancing and per-VLAN traffic. will make you miserable (if you don't know what you're doing). The goal now is to show you how to maximize 1th and avoid 2nd.In general, a multi-instance spanning tree gives you an amazing tool to control your network. It is important to note that many service providers use only one

forum is definitely worth reading.12. Ultimate VIM Configuration (config)Really, the first thing you need to does, when setting up Vim, are to configure your .vimrc file. This is essential. Steve's "Ultimate. VIMRC File" should provide a great base for your own.When configuring Vim, the first thing to do is to configure your. vimrc file. This is essential. Steve's "Ultimate. vimrc file" is definitely your best choice. SummarizeFrom the personal experience, Vim is so daunting that one day

port belongs to a link only), and the number of each STP consists of table 6-2.Table 6-2. STP components in a Switch and 146 Segment Network STP Component number Root bridge 1 root port 14 Specify port 146 Also, all options are based on the following four-step comparison principle: Minimum root bridge bid Minimum root path overhead Minimum sender bid Minimum Po