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public class Random {private static final int a=48271;private static final int m=2147483647;private static final int q=m/a;private static final int r=m%a;public Random () {This ((int) (System.currentt Imemillis ()%integer. Max_value));} /*construct this b random object with specified inital state * */public Random (int
3757. [noi2014] random number generator (Standard Io) Time limits: 5000 MS memory limits:262144 KB
Description
The first row of the input file contains five integers, which are x0, A, B, C, and D in sequence. This describes the Random Seed required by the
Today with the doctrine in preparation for a party, there is a random number lottery to make the link, want me to make a random number generator, preferably the kind of start after the number of jumps, the key after the pause.This
Matrix Fast power ... + fast multiply on OK--------------------------------------------------------------------------------------#include using namespace std;typedef long Long ll;ll MOD, A, C, X, N, G;ll MUL (ll A, ll b) {ll ans = 0;for (; b; b >>= 1) {if (b 1) ans + = A;if (ans >= mod) ans-= mod;a if (a >= mod) A-= mod;}return ans;}struct Matrix {ll x[2][2];Matrix () {memset (x, 0, sizeof x);}inline void Unit () {x[0][0] = x[1][1] = 1;x[0][1] = x[1][0] = 0;}Matrix operator * (const matrix o) {
Huawei WS318 predictable random number generator Vulnerability
Release date:Updated on:
Affected Systems:Huawei WS318Huawei WS318Description:Bugtraq id: 71787
Huawei WS318 is a wireless router product.
A predictable random number gen
=shared--enable-disk_cache=shared--enable-mem_cache=shared-- enable-proxy=shared--enable-proxy_connect=shared--enable-proxy_ftp=shared--enable-proxy_http=shared-- enable-file_cache=shared--enable-charset_lite=shared--enable-case_filter=shared--enable-case_filter_in=shared- -enable-ssl=shared--WITH-APR=/USR/LOCAL/APR--with-apr-util=/usr/local/apr-utilMakeMake installNot that the first method must have a problem, I have also encountered the first installation is available, if you are the first way
\[\begin{eqnarray*}x_i=x_{i-1}+x_{i-2}\\x_i^2=x_{i-2}^2+x_{i-1}^2+2x_{i-2}x_{i-1}\\x_{i-1}x_i= (X_{i-3}+x_{i-2}) (x_{i-2}+x_{i-1}) \ \=2x_{i-3}x_{i-2}+x_{i-2}x_{i-1}+x_{i-3}^2+x_{i-2}^2\end{eqnarray*}\]Therefore, the transfer matrix can be constructed $a$ recursive.If you wish to set $n\geq m$, you can preprocess $a^0,a^1,..., a^n$ and $a^n,a^{2n},..., a^{nn}$.So the complexity of querying a number is $8^3$.Total time complexity is $o (n (8^3+\log N))
1. Seeds and distribution
Five types of distributions are introduced here, including the following: (a), and (). Parameters required for distribution and use are provided.
2. Test the random number generator.
This section contains only one simple example, which is not described in detail. The following is the procedure for getting a
A whole bunch of borders was not known at first, and after a few random sentences, WAHelpless to download the data, and then crazy to judge all kinds of strange boundariesTo gouge out the boundary problemFirst we consider the situation of a=1X1+k*b=t (mod p)EX_GCD can be solvedConsider the situation of a>1Make s=x+b/(A-1)The original is becoming a geometric series.S1*a^k= (t+b/(A-1)) (mod p)BSGS solution after moving the itemAll other boundaries can b
Prioritize the processing of arrays in the way it describesAnd then, in order to get as many small numbers as possible in the sequence,So 1 is a must to appear, in order to make the whole sequence of the order of the dictionary after the smallest.We thought, if 2 could be in this series, it'd be better.But 2 may not be in this series, that is, 2 walk 1 is impossible to go to the place, you can not walk 2.So from small to large enumeration numbers, if the current
cookie| Program | Random
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At the request of a few colleagues, wrote the program for them, and I never buy lottery tickets, do not understand.
But if you're really in the jackpot, don't forget to tell me. What are you afraid of me splitting your money?
I am not greedy, the most send me a classic music dish I am very happy!
By Jianglixin@163.net (hastily written,
About Return of a functionLi = [11,22,33,44]def f1 (ARG):Arg.append (55)Li = F1 (LI)Print (LI)Because li = F1 (LI) is actually assigned a return of F1, in this case the function F1 does not define return, so the default return is NoneSo the value of Li should be noneIf it isLi = [11,22,33,44]def f1 (ARG):Arg.append (55)F1 (LI)Print (LI)Because the arguments passed by the function are actually references to the arguments, the changes to the arguments in the function affect the original parameters
Php random number code/php random generation number instance lt ;? Php // seed user-defined functions use microseconds as the seed functionseed () {list ($ msec, $ sec) = explode ('', microtime (); return (float) $ sec;} php random
Php random number code php random generation of number instances lt ;? Phpseed user-defined functions use microseconds as the seed functionseed () {list ($ msec, $ sec) explode (, microtime (); return (float) $ sec ;} broadcast the seed of the
Javascript Random Number Generation Code sharing, JS random number code
Let's take a look at the source code
You can use it flexibly. We will share the specific JS
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