smi collision

Using unityengine;using System.collections;public class Move:monobehaviour {gameobject go;//use this for initialization void Start () {go= gameobject.find ("C4"); Cubego.renderer.material.color = color.red named C4; Set its material to red}//update is called once per framevoid update () {//To detect in real time in each frame whether the keyboard is pressed and to control the direction of C4 movement via W, S, A, D keys if (Input.getkey (K EYCODE.W)) {go.transform.Translate (

A classic tutorial Translated From DT: Introduction to unity. Trigger usage in game production is very convenient and practical. This document briefly introduces how to use a simple trigger to automatically open and close the door. First, make sure that you have set the animation for the door. The specific process is as follows. Choose WINDOW> animation to open the animation window. Select the animation door to be added and click the red button to create a new animation. After selecting

Rigidbody's motion or rotation, if necessary) + custom control script Movementwhen using charactercontroller, movement is accomplished by calling the functions exposed by charactercontroller. interaction with other objects (platforms, crates, etc .) is accomplished by implementing the collision events exposed by charactercontroller and applying forces to the objects the character collides with, or moving the character in response to the movement

(float dt){ if(hero!=NULL) { CCTMXLayer* collionLayer=map->layerNamed("collionLayer"); CCPoint tilePos=positionToTid(hero->getPosition()); if(collionLayer->tileGIDAt(tilePos)) { CCLOG("collion"); collionLayer->removeTileAt(tilePos); } } }CCPoint HelloWorld::positionToTid(CCPoint position){ int x = position.x /map->getTileSize().width; int y = (map->getMapSize().height*map->getTileSize().height - position.y) /map->

education philosophy collide. Collision comes from different causes. Here we need to talk about my understanding of the philosophy of education for the African, Asian, and white people: the philosophy of education for the African people focuses on the process. If the process is unhappy, the result would be best. In this case, the mother of Akira always does not agree to participate in the spelling contest. Her reason is: the fact that Akira is not su

HDU 4793 Link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4793 For a circular area with the center radius of () as R, A () disc with the center radius of RM is placed in the center, in the coordinates (x, y) place a coin with a radius of R outside (strictly outside the circular area), and the movement direction and speed are (VX, Vy). When the disc is in motion, will rebound according to the collision problem (the disc is fixed ), ask how long th

Comments: Drag and drop a wall on the canvas, and use the arrow keys to control the movement of the top, bottom, and left polygon. When a wall is encountered, the following describes the problems to be solved and the specific implementation code, interested friends can learn to play gamesDrag and Drop the canvas to add a wall and use the arrow keys to control the movement of the polygon between top, bottom, and left. When a wall is displayed, the polygon cannot move forward.Problems to be Solved

Topic PortalTest instructions: There are two a big small concentric circle, the center of the origin, a small circle outside the circle, its center has a speed (VX, VY), if the small circle will rebound, ask the circle in the large circle of time to moveAnalysis: The small circle outside the circle as a point, judging the intersection of the line and the concentric circle, according to the number of intersections to calculate the time. Using the definition of a line, the definition of a circle,

functionHashTable () { This. Table =NewArray (137);//137--Official better set the value of the array size This. Buildchains =Buildchains; This. Simplehash =Simplehash; This. Showdistro =Showdistro; This. put =put; //This.get=get; } functionBuildchains () {//Core Approach for(vari = 0; I This. table.length; ++i) { This. table[i] =NewArray (); } } functionSimplehash (data) {varTotal = 0; for(vari = 0; i i) { total+=data.charcodeat (i); } returnTotal% This. T

); var hash = md5provider.computehash (bytes); for (int i = 1; i 　　The simple thing is to put the salt in the cipher. MD5 hash is completed after a 16-length byte and byte can save 0~255 integer, so in the example, the random salt is 0~255 numberThen MD5 (clear text + salt) and then save the salt to the byte[0] positionSo each hash after the ciphertext are different but still can be directly ciphertext comparison, here is a point, think 255 not enough can add aOf course, it c