Topic Link: Click to open the linkThe main idea: a rectangle consisting of n small rectangles, now to the small rectangular dyeing, but the pigment will fall, in order to prevent the confusion of pigments, so to dye the above rectangle, and then dye the rectangle below, each time to change the color to use a new brush, ask the minimum number of brushes.According to the dyeing conditions, you can find a topological sequence, the topological sequence before the first to dye, after the dye, in the
:#include #include #include #include #include #include #define MAX_N 100010#define MAX_M 300010using namespace STD;structe{intFrom,to,next;BOOLsign;};intN,m;intResultintEdgenum;number of//sidesintTop,cnt,time;//stack top, number of strong unicom components, time axisE Edge[max_m];//Edge setintDis[max_n];//The weights of nodes in the topological sequenceintHead[max_n];//forward star Storage head arrayintBelong[max_n];//record which strong connected component A point belongs tointIndegree[max_n];/
there is a undirectional tunnel between
u , v
. (
u ≠ v
)The next
M2
Lines contain the details of the directional tunnels. Each line contains integers
u , v
Meaning that there was a directional tunnel from
u
To
v
. (
u ≠ v
)
T
is on 100.
1 NBSP; NBSP; n m 1 , m 2 NBSP; ≤ NBSP; 1000000.
There may some tunne
http://acm.hdu.edu.cn/showproblem.php?pid=1285determine the position of the matchTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 18484 Accepted Submission (s): 7399problem DescriptionThere are N teams (1Inputthe input has several groups, the first behavior in each group is two number n (1Outputgive a ranking that meets the requirements. There is a space between the queue numbers at the time of the output, and no space after the last. Other Note
, and, Each employee has a performance comparison, high salary high, at least 1 yuan, ask at least how much money to send. Idea: Topology sorting, find out how many different levels of points, the value of each point with the previous cumulative 1; Total plus everyone 888. Simple topological ordering, no need to say: AC code:/ */ #include "algorithm" #include "iostream" #include "CString" #include "Cstdlib" #include "string" #include "Cstdio" # Incl
enterprise internal applications.If you have an iphone or ipad on hand, you can experiment with it in the following ways:1. Open the link using the Safari browser on the iphone or ipad: http://pattern.dk/sun/, click the Send button at the bottom2. Click Send To Home screen3. Confirm Add4. Check the new app icon on the main screenYou can see that there is an "app" on our home screen, and if you are careful with optimization, users simply cannot tell whether this is a native or HTML5 application,
containsPNumbersv1,.. . ,vp , wherevi(1≤vi≤8) indicating the value of pondI.Each of the lastmlines contain, numbersaand b, which indicates that Pond a and pond b is connected by a pipe. Outputfor each test case, output the sum of the value of any connected components consisting of odd number of ponds after Removing all the ponds connected and less than the pipes.Sample Input17 71 2 3 4 5 6 71 41 54 52 32 63 62 7Sample Output21 Test Instructions: Always go to the point of less t
Topological sortingTopological order: If there is a forward path from V to W in the figure, V must precede w. The sequence of vertices that satisfy this condition is called a topological order.The process of obtaining a topological order is the topological orderingA sequence is obtained after the topology is sortedEach time we want to output a node without a precursor vertex, that is, a point with no degree of penetration. After the output, set the ve
http://acm.hdu.edu.cn/showproblem.php?pid=18111#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 #defineN 100108 intx[n*2],y[n*2];9 Charch[n*2][3];Ten intFa[n],deg[n]; One intF1,f2,tot; A structnode - { - intnext,to; the}edge[n*2]; - inthead[n],n,m,cnt; - /* - and check set + topology sorting + because there is an equal condition, put the equal condition in a set, when the topological sort - sort all the elements in the colle
Developers using the HT for Web (hereinafter referred to as HT) to develop a HTML5 network topology diagram are painful when they have a project with a chart requirement, and the HT Integrated Chart component does not contain coordinates and is not very intuitive in presentation. But there is no solution, so let's talk about specific solutions. First of all, the first solution is to define the chart vector in comps in addition to defining the chart, a
Test instructions: The basic salary for each person is 888. Because some people want to show their own level is higher, the demand to pay more than one of the other people. Ask if you can meet their requirements, assuming that the total amount of money to be issued at last, assuming that cannot be output-1.Policy: Topology ordering.This problem has some difficulties: one: Large data, build two-dimensional array is certainly not, to change other data s
that the topological ordering is defined as: if (u,v) ∈e, then the position where u appears in the arrangement must be in front of v.That is, considering a node u, when we delete u in the sequence before all the points in front of him, you should be in the degree of 0.So we get a rough idea of the algorithm for topological sequencing.What is it exactly??Loop n timesSelect a point with an entry level of 0 and still exist (not appearing in the sequence) vDelete Point V and all edges starting from
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Deploy Lotus Sametime Gateway in DMZ
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Deploy instant messages and online notifications only
Only instant messages and online notifications are provided. You can use the Sametime Community Server or server cluster running on Domino.
The following components are deployed in a Sametime environment that only contains instant messages and online notifications:
Lotus Sametime System Console (used to ma
Original address This is my personal AC first topological sorting problem.The title explains the outcome of several sets of matches. Infer the final ranking. According to test instructions this is an obvious topological ordering problem.Attention
Assuming there are multiple situations due to possible rankings, make sure that the numbers are small before.
The data entered by the topic may have repeated edges
Topology sequencing first
assigned to the DP array, the topology is sorted, and finally the point of 0 is traversed, and the maximum value is obtained.AC Code:#include "iostream" #include "Cstdio" #include "CString" #include "algorithm" #include "queue" #include "stack" #include " Cmath "#include" utility "#include" map "#include" set "#include" vector "#include" list "#include" string "using namespace Std;typedef Long Long ll;const int MOD = 1e9 + 7;const int INF = 0x3f3f3f3
each test data, the first line has two integers n (1 Then m lines, two integers a and b per line, indicate that a constraint a must precede the B number.A and B are necessarily different.Output the order in which each test data is queued, separated by a space. Sample INPUT15 103 The 2 sample OUTPUT1 2 3 4 5 The main topic: in a given order, find a set of numbers the lower the priority of the scheme, as far as possible to arrange 1 in front, if there are many cases Then as far as possible arrang
HDU-4857Test instructions is to do a qualifying sort, using the topological sequence.I started with a lot of WA, only to find that there are a few examples too, found 1->2->3 ... the order is not guaranteed.Later I wanted to use and check the strong company, or WA;Later found that the use of reverse topology sorting + priority queue to pass;Notice here that the entry to the 0 is changed into a 0-degree queueHere is the AC code:#include #include#includ
Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=4857The surface is a Chinese problem surface, do not explain test instructions, oneself click the link to look down ~ This question sort has two conditions, one is according to the given sequence (that is, the input of the u,v, the highest priority), one is the number from small to large (priority level). Positive words because these two conditions are not good maintenance, so think of using reverse topol
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