sql compare two tables and find records without matches

1. Query table name:SELECT table_name from User_all_tables;2. Assemble statistical SQL statements:1 >select ' SELECT ' | | table_name | | ' As TableName, COUNT (*) from ' | | table_name | | ‘ ; ' As Exectutesql from User_all_tables;2> select ' Select ' | | table_name | | ' As TableName, COUNT (*) from ' | | table_name | | ' Union ' as exectutesql from User_all_tables;3. Copy the assembled Exectutesql executionselect * from ( 第二步2> 执行的结果复制到这里 删除最后一个 un

Obtain table records of all tables and SQL statements that use space Exec sp_msforeachtable@ Precommand = N'Create Table ##(Id int identity,Table Name sysname,Number of fields int,Number of records int,Reserved space nvarchar (10 ),Use space varchar (10 ),Index space varchar (10 ),Unused space varchar (10 ))',@ Comman

One of the SQL Master tables records multiple record statements corresponding to the schedule Like this, we use the Union statement SQL Union syntax Select column_name (s) from table_name1 Union Select COLUMN_NAME (s) from Table_name2 Join left statement LEFT JOIN keyword syntax Select column_na

--discontinuous and sequential records2 Select * 3 from [t_idnotcontinuous_temp]4 whereIdnew_id- 15 6 7 --querying original Records8 SelectA.* from [t_idnotcontinuous] asa9 Inner Join(Select * Ten from [t_idnotcontinuous_temp] One whereIdnew_id- 1) asb A ona.ID>=b.ID anda.IDb.new_id - Order bya.ID(Figure 3: effects)Supplement 1: If this ID field is not a primary key, then there will be duplicate ID values (there may be some misoperation, have encountered before) then you need to handle t

2016-05-20A table that counts no records in a SQL Server databaseWhen you use it, replace the red [TestDB] in the SQL script with your target database name.1 /************************************************************2 * Code formatted by Softtree SQL Assistant? v7.0.1583 * TIME:2016/5/19 18:47:024 * AUTHOR:ZHANGCN5

One business requirement in the project is to load 15 history by default (in chronological order from morning to night).Here is the SQL logic I constructed, mark, and it works.SELECT * FROM (select *from group_chatmsg_vwhere ((group_id=46 and send_user_id=28 and receive_user_id=70) OR (group_id=46 and receive_user_id=28 and Status=1)) and Is_delete =0order by Crtime DESC LIMIT, as Chatmsgtableorder by Crtime ASCSlightly more complex

,--Optimization methodA.executions,--Execution timesA.disk_reads,--Read Disk countA.sharable_mem,--The amount of memory occupied by the shared poolA.buffer_gets,--The number of read buffersA.command_type,--Command Type (3:select,2:insert;6:update;7delete;47:pl/sql program unit)A.sql_text,--SQL StatementsA.sharable_mem,A.persistent_mem,A.runtime_mem,A.parse_calls,A.disk_reads,A.direct_writes,A.concurrency_wa

Label:Http://www.hanyu123.cn/html/c61/6790.html One, check a column (or more than one column) of the duplicate values. (You can only find the value of the duplicate record, cannot find the whole record information) For example: Find Stuid,stuname duplicate records: Select stuid,stuname from stuinfo Gr

The following two tables have the same structure. use SQL to find columns with different values. Student_1 NAME AGE SCORE Peter 26 100 Jack 25 96 Daniel 26 48 Bark 21 69 Student_2 NAME AGE SCORE Peter 26 89 Jack 25 96 Daniel

The following two tables have the same structure. use SQL to find columns with different values. Student_1 NAME AGE SCORE Peter 26 100 Jack 25 96 Daniel 26 48 Bark 21 69 Student_2 NAME AGE SCORE Peter 26 89 Jack 25 96 Daniel 2

Two methods for SQL to find the intersection of two tables Dept Table ID DeptID1 202 203 20 User table ID UserID1 332 343 34 Method One SELECT DISTINCT UserID From User U where ID in (SELECT ID from dept where deptid=20) And NOT EXISTS (select 1 from user where ID in (select IDs from dept deptid=20) and Userid Method two Join SELECT DISTIN