In MYSQL, you can use the internal and external key links to merge data in related tables for conditional filtering:First, create two new tables. The data is as follows:Student table data:Score table data:We can see that the score table corresponding to the record with stu_id 16048008 in the students table has no data;1. When the internal connection is performed, the system automatically ignores the data th
Let's look at one of the simplest inner joins, inner the corresponding class information from the Join Class table when reading the student table:Static voidMain (string[] args) { using(varwriter =NewStreamWriter (Watchsqlpath,false, Encoding.UTF8)) { using(Dbappdatacontext db =NewDbappdatacontext ()) {db. Log=writer; //INNER JOIN varquery = fromSinchdb. Students
In and exists (excerpt from Baidu)in is the appearance and the inner table as a hash connection, and exists is the external loop loop, each loop loop and then query the internal table. If one of the two tables is smaller and one is a large table, then the subquery table is large with exists, and the subquery table is small in:Example: Table A (small table), table B (large table)1: SELECT * from A where CC in (select CC from B) is inefficient and uses
The syntax format for the ON clause in a join SQL statement in Mysql is: Table1.column_name = table2.column_name. When schema design uses the same naming style for columns that join tables, you can use the using syntax to simplify the on syntax, in the form: using (column_name). For example:[
1. Join keyword is to link multiple tables togetherBoth on and where are conditions, but the objects are different1.1. The keyword on refers to how to connect two tables, such as: on a.name = B.nameis a row-by-row comparison, and then joined together, at which point the contents of the WHERE clause are not judged1.2. The keyword Where is the final data that is
-free Empress','Taoism'),
*('Heavenly Queen','Taoism')
$
Panax Notoginseng--insert these lines into this location - Insert into location theValues'Buddhist','India'),
+('Taoism','China'),
A('Christ','Western'),
the('Confucian','China')
+
---inner JOIN inline, link the teacher table to the location table $--teacher is the main table, location is attached table, with teacher $
---only the matching content is displayed, and the mismatch does n
SQL is required. Note: Chapter 13th creates an advanced join. SQL is required.13.1 use table alias
In addition to column names and calculated fields, the SQL statement allows you to specify aliases. There are two main reasons for doing this:(1) Shorten SQL statements(
https://leetcode.com/problems/combine-two-tables/Combine TablesTable:Person+-------------+---------+| Column Name | Type |+-------------+---------+| PersonId | int | | FirstName | varchar | | LastName | varchar |+-------------+---------+personid is the primary key, column for this table.Table:Address+-------------+---------+| Column Name | Type |+-------------+---------+| Addressid | int | | PersonId | int | | City
The actual project, there are multiple tables of the association relationship. It is impossible to retrieve all the data in a single table. If there is no table connection, then we need a lot of action. For example, you need to find restrictive conditions from table A to retrieve data from table B. Not only need to be divided into multiple tables to operate, but also not high efficiency. For example in the
There are two table A and table B. The structure of table A is as follows: Aid:int; identity seed, primary key, self-increment ID Aname:varchar data case, that is, the record with select * from A is shown in 1:Figure 1:a Table DataThe structure of table B is as follows: Bid:int; identity seed, primary key, self-increment ID bnameid:int data case, that is, the record with select * from B is shown as 2:Figure 2
Label:There are currently two tables, Sgroup and Sgroupuser, which are associated by Gkey, while the Sgroup table records the group, and the Sgroupuser record is the user in the group, so there is no data in the Sgroupuser. You need to use the left join to get the data: The LINQ syntax is as follows: var sg = ( from the dc.sgroup
in dc.sgroupuser on G.gkey equals Gu.gkey into L
, which is why (int *) (int *) two times, you should understand, because it may //There are multiple virtual pointers, the compiler does a good job, if you do not compile will error. coutsizeof(c) //Ultimate test Result 8. return 0;}//Summary 2: Each base class in multiple inheritance maintains one of its own virtual tables, and each inheritance of a virtual base class in a subclass has a//Pointe
should be clear about that. Because there may //have more than one virtual pointer. The compiler is doing very well, assuming that compiling without this will cause an error. cout sizeof(c) //Ultimate test Result 8. return 0;} //Summary 2: Each base class in multiple inheritance maintains one of its own virtual tables, and each inheritance of a virtual base class in a subclass has a //Pointer to t
1 Overview
Hash join has the same features as merge join, and requires an equivalent condition. When the index cannot be hit on the connection bar, or the join of a large set, the nested join and merge join may not achieve good performance. In this case, we need to conside
Assume that the table structure is: user_info table: role_info table: to query some data from the user_info table and role_info table, for example, when logging on to the system, in addition to the login name and password, you can also query additional information, such as user permissions, which may be connected. Here we use the left join: the SQL statement is as follows: selectu. *, r. role_name, r. right
) [USA]-- @p1: Input Int (Size = 0; Prec = 0; Scale = 0) [0]2. many to many relationships ):
var q = from e in db.Employees from et in e.EmployeeTerritories where e.City == "Seattle" select new { e.FirstName, e.LastName, et.Territory.TerritoryDescription };
Note: many-to-many relationships generally involve three tables (if one table is self-associated, there may be on
Left join returns records that include all the records in the left table and the equivalent of the junction fields in the right tableRight join returns records that include all records in the right table and the junction fields in the left tableINNER JOIN (equivalent join) returns only rows that have the same
If you have a one-to-many relationship and want to Join two tables, but you only want to generate a row in each "one-to-many" relationship, you can refer to the following:
A simple example is as follows:
If you want to obtain the essay ID, Title, and comment ID, there are two solutions:
Solution 1:
Solution 2:
The first scheme has few essays, but it
. Username;
Efficiency has improved a lot, but it is still unsatisfactory.
During the test, it is found that if you do not select users within two hours, but directly select all users within three days for statistics, the efficiency is very high. It seems that the performance bottleneck is still on table join. If you have selected a hash connection, you only need to reduce the number of connections. So I tried to write the following query:Result1(Sele
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