sql remove duplicates

Leetcode notes: Remove Duplicates from Sorted Array II, leetcodeduplicates I. Description Ii. problem-solving skills This is similar to removing Duplicates from Sorted Array, but repeated numbers are allowed here. You can use the binary search variant algorithm, however, the process of removing elements that are the same as the first element is added. Another i

LeetCode83: Remove Duplicates from Sorted List, Given a sorted linked list, delete all duplicates such that each element appear only once.For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. If you want to delete a duplicate element from the linked list, but you need to keep one repeat element, you can delete it one by one.Runtime: 16 ms /

Given a sorted array, remove the duplicates in place such, all element appear only once and return the new L Ength.Do the allocate extra space for another array, and you must does this on place with constant memory.For example,Given input Array A = [1,1,2] ,Your function should return length = 2 , and A is now [1,2] .One: Compare adjacent elementsClass Solution {public: int removeduplicates (int a[], int

Given a sorted Linked List, delete all duplicates such that each element appear onlyOnce. For example,Given1->1->2, Return1->2.Given1->1->2->3->3, Return1->2->3. Https://oj.leetcode.com/problems/remove-duplicates-from-sorted-list/ Idea: the Basic Linked List Operation stores the pre pointer, and cur is deleted when cur is the same as pre. public class Solution {

Label: style blog Io color AR for SP Div on Given a sorted Linked List, delete all duplicates such that each element appear onlyOnce. For example,Given1->1->2, Return1->2.Given1->1->2->3->3, Return1->2->3. Idea: two pointers, one pointing to the current node cur, one pointing to the next node NX, termination conditions, that is, compared with the len-1 times. If the comparison is not equal, Both pointers are moved backward. If the two pointers are equ

Given an ordered array, you need to delete the duplicates in place so that each element appears only once and returns the new length.Do not define an array separately, you must do this by modifying the input array in place with O (1) extra memory.Personal code, more mentally retarded.Class Solution {Publicint RemoveDuplicates (vectorVectorint m;if (Nums.size () ==0) return 0;else m=nums[0];For (Iter=++nums.begin (); Iter!=nums.end ();){if (*iter!=m) {

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given1->2->3->3->4->4->5, return1->2->5.Given1->1->1->2->3, return2->3.Idea: This question in just start to do when thinking of a bit, how can not be solved correctly. Rewrite all of the code to remove it later. The idea is to record the current node P=head, then head down, and when the head value is not equal to th

LeetCode [Linked List]: Remove Duplicates from Sorted List II, leetcodeduplicates Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. To remove the special characteristics of the header node, the virtual

Title: Give a sorted array, remove duplicate elements in the array and allow up to two elements of the same, and finally return the processed array length, and the array is collated.Algorithm idea: When the array length is less than 3 o'clock do not tidy up the array, directly return the length of the array; When the array length is greater than or equal to 3 o'clock, with the pre record of the precursor element, the flag tag repeats once, p records t

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list. For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 . Problem Solving Ideas:Create a new auxiliary header, using two pointers pre,p;Start cycle judgment1. Pre->next=p->next, stating that there is the same element, then p=p->next; know that P->next is empty or discovers new elements;2. Judge P->next!=p, if there is the same e

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Delete the duplicate numbers in the list, and note that this is the number that will be removed once the numbers have been duplicated. So how to completely remove is a technical live. Of course, in order to deal with the deletion of the h

Description:Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Code:1listnode* Deleteduplicates (listnode*head) {2 if(head)3 {4listnode* p =head;5listnode* Lastnode =head;6 7 intLastdeleteval =0;8 BOOLFlag =false;//flag is false to indicate that no elements have been deleted9

Because the list is used, there are several ways to remove duplicate data. Recorded in this ...Test data:listMethod One:hashsetSeveral ways to remove duplicates in the list collection-reproduced

/** Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * ListNode (int x) : Val (x), Next (NULL) {}}; */classSolution { Public: ListNode* Deleteduplicates (listnode*head) { if(Head ==null)returnHead; if(Head->next ==null)returnHead; ListNode*res =Head; intHead_val; while(head) {Head_val= head->Val; if(Head->next head->next->val = =head_val) { while(Head Head->val = = head_val)//Remove the beginning of

do not know the size of the problem, it is very bad. It also caused me to waste a quick 2 hours =.= (listnode* res,*tmp;STD:: mapint,int>Ans ListNode *deleteduplicates (ListNode *head) {ListNode * I,*K,*AA;intJBOOLflag=true;if(head = = NULL | | head->next = = NULL)returnHead for(j=-65536;j65537; j + +) Ans.insert (STD::p airint,int> (J,0)); for(I=head;i!=null;i=i->next) {ans[i->val]++;//cout} for(I=head;i!=null;i=i->next) {if(ans[i->val]==1){int*a =New int; ListNode L (i->val);//cout

found that Prev is Fakenode node initially. Because the Fakenode node initially points to the head node.Runtime:8ms/** * Definition forsingly-linked list. * struct ListNode {*intVal * ListNode *Next; * ListNode (intx): Val (x),Next(NULL) {} * }; */classSolution { Public: listnode* deleteduplicates (listnode* head) {ListNode * fakenode=NewListNode (0); Fakenode->Next=head; ListNode *prev=fakenode; while(head!=NULL) {if(head->Nexthead->val==head->Next->val) {intvalue=head->val; while(Headhead-

; * ListNode *next; * ListNode (int x): Val (x), Next (NULL) {} *}; */class Solution {public:listnode* deleteduplicates (listnode* head) {if (head==null) return NULL; if (Head->next==null) return head; listnode* P=head; listnode* Q=head; listnode* k=p->next; BOOL Flag=false; while (k) {if (p->val==k->val) {if (p==q) {p=q=k; Head=k; k=k->next; } else {listnode* tobedeleted=k; p->next=tobedeleted->next; k=p->next; Delete tobedeleted; Tobedeleted=nu

unification of the two. Also highlighted in the relevant documentation.Solution One:1 Public Static BooleanContainsNearbyAlmostDuplicate1 (int[] Nums,intKintt) {2 if(kreturn false;3 4TreesetNewTreeset();5 for(inti=0;i){6 intCurrent =Nums[i];7 if(Set.floor (current)! =NULL current8(Set.ceiling (current)! =NULL) current>=set.ceiling (current)-t)9 return true;Ten Set.add (current); One A if(i>=k) -Set.remov

It's easy to repeat the data in the list result, as long as. dinstinct (). However, if you want to remove duplicate data based on a field, the above method will not be helpful. We need to rewrite a method. Let's look at the example directly. [Serializable] public class HomePageUserModel { public int UserID { get; set; } public string TitleUserName { get; set; } public string ShowUserName { get; set; } public DateTim

Tags: leetcode linked list algorithm virtual header Node Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. To remove the special characteristics of the header node, the virtual header node technology is required. C++ code ListNode *deleteDuplicates(ListNode *head) { if (!head)