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Steps:
One, new text document Xxx.txt, modify file type is. udl
Open the document and find the corresponding service in the provision of data.
Select the required database in the connection and fill in the relevant information.
Test the connection, if successful, skip to the next step, the failure is the user information is incorrect, modify.
V. To change the xxx.udl suffix name to txt, the connection string can be found on the open.
Note: There
SqlServer removes string spaces and SQL Server strings
Speaking of removing spaces at the beginning and end of a string, you must be the first to think of the trim () function. However, this function is not available in sqlserver, but instead of ltrim () and rtrim () two functions. We can see that everyone knows what
Tags: length des. com object RIP Color COM technology share delimiter Select STUFF ((select ',' + modifyby
from dbo.tbl_stationprofile
for
XML PATH (")
11") as Name Comma-separated string-to-table Use [Mbg3sdb] GO/** * * * object:userdefinedfunction [dbo]. [Getidlist] Script DATE:2017/9/12 10:13:38 * * * * **/SET ANSI_NULLS on Go SET quoted_identifier on Go-- ===================
Tags: style io os ar strong art SP CTI on1. Write scalar value function iconvert2stringCREATE FUNCTION iconvert2string (@N int,@f INT) RETURNS varchar (ten) Asbegindeclare @M intdeclare @L0 intdeclare @CH VARCHAR (10) DECLARE @ST VARCHAR () Select @CH = "Select @ST =convert (VARCHAR), @N) Select @ST =rtrim (@ST) Select @L0 =len (@ST) Select@m=1while (@mDescription: The parameter @f is the length of the variable part after the string. 2. Write a scalar
Label:SQL Server Split stringThe following is a function that creates a split string with ",":createfunctionf_splitstr (@SourceSql varchar (8000), @ Strsepratevarchar (+)) returns @temp table (F1varchar) as begindeclare @ch asvarchar (set@[email) Protected][emailprotected]while (@SourceSql SQL Server Split
Tags: tin BSP Replace Code tab UNION ALL null with ORDER byWith table1 (sessionid,message,createtime)As(Select 1, ' Hello ', ' 2014/5/6 ' UNION ALLSelect 1, ' word ', ' 2015/6/5 ' UNION ALLSelect 1, ' Hello ', ' 2015/7/4 ' UNION ALLSelect 2, ' Hello ', ' ditto time ' union ALLSelect 2, ' Hello ', ' ditto time ')Select SessionID,Replace (CAST ((select ', ' +message from table1 T2where T1.sessionid = T2.sessionidFOR XML Path (")) as varchar (+)), ', ', ') as a message,Max (Createtime) createtimefr
Create function [dbo]. [Getchildworkerextension](@ChildId int)Returns nvarchar (100)AsBegindeclare @ret nvarchar (2000)Set @ret = ' 'Select @ret = @ret + '; ' + (Case relationshipWhen 1 Then ' father 'When 2 Then ' mother 'When 3 Then ' Grandpa 'When 4 Then ' Granny 'When 5 Then ' Granny 'When 6 then ' Grandpa 'Else ' other ' end) + ': ' + phone from guardianinfo where [email protected] and (phone was not null or phone!= ")Set @ret = case If Len (@ret) >0 then stuff (@ret, ",") Else @ret endRetu
/* -- The method for resolving strings that cannot exceed 8000
It is often mentioned that when data is processed using the dynamic generation of SQL statements, the processing statements are too long and cannot be processed.This issue is discussed below:-- Producer build 2003.9 (reference please keep this information )--*/
/* -- Test environment
-- The system table syscolumns is used as the test data, and the xtype column and name column are used as t
Can be achieved by writing a custom function, the following provides two ways to solve:1, through regular matching, find the number in the string, one by one to spell up/*method One: one to find out*/CREATE FUNCTION [dbo].[Fun_getnumpart] ( @Str NVARCHAR(MAX) )RETURNS NVARCHAR(MAX) as BEGIN DECLARE @Start INT; DECLARE @End INT; DECLARE @Part NVARCHAR(MAX) SET @Start = PATINDEX('%[0-9]%',@Str); SET @End = PATINDEX('%[0-9]%',SUBSTRING(@
Label:Use [DataChange]
GO
/****** Object: userdefinedfunction [dbo].[ F_SPLITSTR] Script date:05/09/2016 15:04:21 Apply SQL: Implement data segmentation such as data: b41j-002/145%b41j-002/15%b41j-003/36%b41j-000/00%b43k-001/00%b41j-002/045%b41j-002/055%b41j-002/21%b43k-008/00 %b81b-007/04%b43k-029/00%b43k-027/00%b43k-029/093 Take the previous digit in each set of% data together to get the data in% split B%b%b%b%b%b%b%b%b%b%b%b%b Update [ Pub_no
Windows integrated security verification:1. With SQL Server 2005 "Server = SAIXIN-1F662FDD \ saixin; database = blogdb; Integrated Security = sspi"The server is the SQL server name, not the computer name or local or localhost.
2.
Label:SELECT CONVERT (varchar), CAST (@testFloat as Decimal (38,2)))SELECT STR (@testFloat, 38, 2) Import from Excel to sql2000, there is a column "contact" has become a float type, I want to convert to nvarchar type, with the following statement Select convert (nvarchar (+), convert (int, contact)) from employeeGo Data overflow, no! Select convert (nvarchar), CONVERT (Decimal (11,0), contact) from employeeGo Data Conversion Success! SELECT CONVERT (nvarchar), CAST (Contact as decimal (11,
Because this side of the database is more, the data is more, but there is a legacy of historical data problems; A string preceded by a comma;Now the demand is to get rid of the English comma, with a script to run the database is also OK, but here with SQL statements to remove;Here's the complete code, here's a record.DECLARE @cursor CURSOR;DECLARE @id int;DECLARE @Staging varchar(Max);DECLARE @Staging
Label:Two ways, efficiency is immediate ------------------------------------------------
SET STATISTICSTime on
DECLARE @OrderStr NVARCHAR(Max)= "'; SELECT @OrderStr +=A.serialnumber+','
fromdbo. Withdrawalslog aSET STATISTICSTimeOFF
------------------------------------------------
SET STATISTICSTime on
DECLARE @OrderStr NVARCHAR(Max)= "'; SET @OrderStr = (
SELECTA.serialnumber+','
fromdbo. Withdrawalslog a forXML PATH ("')
)
SET STATISTICSTimeOFF
----------------------------------------
, @Value2 int set @Value1 = 2 Set @Value2 = 2000000000 Select Datalength (@Value1) Select LEN (@Value1 Select Datalength (@Value2) Select LEN (@Value2) In both cases, the DATALENGTH () function returns 4. Because the int type, regardless of the value, always uses 4 bytes. The LEN () function essentially treats integer values as data that has been converted to character, so in this case, it returns 1 and 10, which is the number of digits of the value.This article from Csdn Blog, reproduced please
Only SQL functions can be used to manipulate fields in a SELECT statement (linked to SQL Server).Select field 1 from Table 1 where field 1. IndexOf ("cloud") = 1;The reason this statement is not correct is that the indexof () function is not an SQL function, so it can be changed to the corresponding function of SQL.Lef
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