sql server split string

Tags: style blog http ar color sp for strong onThe number column queried in SQL Server preceded by 0 returns a string of the specified length:Such as:The angle is as follows:/** * * * Script for selecttopnrows command from SSMS * * * **/SELECT TOP +[ ID], [SN], [Name] from [Edudb]. [dbo]. [Testtab]SelectRight ('0123456', SN) fromTesttab; SelectRight (REPLICATE ('

Ice.num_entries (' Http://192.168.0.251/P Ackinfo/tiger/fm/tg17/pc/chest strap/a1.jpg ', ' tiger/') SELECT dbo. Ah_num_entries (' Http://192.168.0.251/PackInfo/Tiger/FM/TG17/PC/Chest strap/a1.jpg ', ' tiger/') SELECT dbo. Ah_num_entries (' Http://192.168.0.251/PackInfo/Tiger/FM/TG17/Tiger/PC/Chest strap/a1.jpg ', ' tiger/')*/ ALTER function [dbo].[ah_num_entries](@char_expr nvarchar(Max),@delim nvarchar( -)) returns int as begin Declare @begin int,@count int Declare @str nvarchar(Max)

前几天的考试系统出现了一个问题，背景大概就是告诉你正确答案，比如说是：答案1#答案2#答案3...而几百个学生答题的记录也是这样格式存储的，问如何用sql语句为每个学生判分？思路：第一步：找到第N个#在字符串中的位置createfunctionfn_find(@findvarchar(8000), @strvarchar(8000), @nsmallint)returnsintasbeginif @n return(0)declare@startsmallint, @countsmallint, @indexsmallint, @lensmallintset@index= charindex(@find, @str)if @index= 0return(0)elseselect@count= 1, @len = len(@find)while @index> 0and@countbeginset@start = @index+ @lenselect@index= charindex(@find,

Tags: using AR data SP problem on BS database SQLIn the data we often encounter ntext large text type, this type if and nvarchar type addition can have problems, so there is a way to solve this problem.SQL functions used:TEXTPTR: Returns the value of the text pointer to the textual, ntext, or image data to be updated.UPDATETEXT: Change part of text, ntext, or image column in the appropriate locationWRITETEXT: To update and replace the entire text, ntext, or image fieldsExample:CREATE TABLE [dbo]

Label:Sql2005 has a function isnumeric (expression) function: Returns 1 when expression is a number, otherwise returns 0. This is just a rookie-level solution, and most of the situation is more effective. eg Select IsNumeric ('123'-- The result is 1 However, this function has a drawback! eg SELECT ,IsNumeric('-') as '-' --1,IsNumeric('+') as '+' --1,IsNumeric('$') as '$' --1,IsNumeric('.') as '.' --1,IsNumeric(',') as ',' --1,IsNumeric('\') as '\' --1,IsNumeric('2D3') as '2D

CREATE FUNCTION F_covert (@str nvarchar (4000)) returns nvarchar (4000)AsBegindeclare @endp int, @endflag int, @length int,@i int, @reversestr nvarchar (4000), @return_str nvarchar (4000)Select @endflag = 0, @length =len (@str), @i=1, @reversestr = reverse (@str), @endp = 0while (@endflag = 0 and @iBeginif (SUBSTRING (@reversestr, @i,1)! = '? ‘)BeginSet @endflag = 1Set @endp = @length-@i + 1EndSet @i = @i + 1EndSet @return_str = substring (@str, 1, @endp)Return @return_strEnd

): (+), select CONVERT (varchar), GETDATE (), 107): 109 Select CONVERT (varchar (+), GETDATE (), 108): 14:58:28 Select convert (varchar), GETDATE (),): 0 6 6 2:58:34:133pm Select CONVERT (varchar (+), GETDATE (), +): 06-06-2012 select CONVERT (varchar), GETDATE (), 111): 2012/06/06 select CONVERT (varchar), GETDATE (), GETDATE): 20120606 select CONVERT (varchar), (), 113): 06 14:58:58:960select CONVERT (varchar), GETDATE (), 14:59:08:527 Select convert (varchar), GETDATE (), 1 : 2012-06-06 14:

MSSQL-string separation (Split function), mssqlsplit As mentioned above, record merging will certainly require separation when combined. When it comes to string separation, you will surely think of the SPLIT function. NET, Java, and JS all have functions. Unfortunately, they are not in

Tags: style blog http io java ar for Data 2014The previous mention of record consolidation, there must be a merger requirement there will be separate requirements, when it comes to the separation of strings, you will certainly think of the split function, which in. Net,java and JS have functions, unfortunately in SQL Server, we can only write such a function. Fir

The previous mention of record consolidation, there must be a merger requirement there will be separate requirements, when it comes to the separation of strings, you will certainly think of the split function, which in. Net,java and JS have functions, unfortunately in SQL Server, we can only write such a function.First of all to analyze how to write this function

SQL Server is commonly used to split string functions. If object_id (n'fn _ Split ') is not nullDrop function fn_splitGoCreate Function DBO. fn_split(@ Inputstr varchar (8000 ),@ Seprator varchar (10 ),@ P int -- the number of data records to be retrieved, starting from 0.

' Age=28Addr='Chengdu' Money='200w'Cars='1w Units'words='INSERT INTO user values ("%s", "%s", "%s", "%s", "%s", "%s");'% (User,sex,age,addr,money,cars)#order can not be chaotic, must be in order toPrint(words)The output is:Insert into user values ("Emily", "female", "28", "Chengdu", "200w", "1w Station")Mode 2user ='Emily'Sex='female' Age=28Addr='Chengdu' Money='200w'Cars='1w Units'SQL='INSERT into user values ({name},{sex},{age},{addr},{qian},{che})'New_sql=sql.format (age=age,che=cars,name=use

Sometimes we use batch operations to Split strings, but SQLServer does not have its own Split function, so we need to implement it ourselves. There's nothing to say. You need to use it directly. Sometimes we use batch operations to Split strings, but SQL Server does not have

Tags: Technology share exp Regular WWW pre nbsp ACL substr netSplits all specified characters in a string and then into multiple linesParameter description,Parameter 1: string to be splitParameter 2: Regular expressionParameter 3: Starting position, starting with the first character of the regular expression match (default is 1)Parameter 4: Identifies the first matching group, which defaults to 1Parameter 5

In the database development, sometimes encountered the string, according to a certain rule of the segmentation, such as "a,b,c,1,2,3" such as a comma-delimited string, you need to split out, divided into a single row of records. The first thought is to use the substitution function to remove the delimiter. So there was:IF (object_id (N ' Tempdb). # #T1 ') is not

Summary of several methods for implementing the SPLIT function in SQL (required), sqlsplit Example 1 The Code is as follows: Create function f_split (@ SourceSql varchar (8000), @ StrSeprate varchar (10) returns @ temp table (a varchar (100) -- function for implementing the split function -- date: 2003-10-14as begindeclare @ I intset @ SourceSql = rtrim (ltrim (@

(T4cpreparedstatement.java:884) at Oracle.jdbc.driver.OracleStatement.executeMaybeDescribe (Oraclestatement.java:1167) at Oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout (Oraclestatement.java:1289) at Oracle.jdbc.driver.OraclePreparedStatement.executeInternal (Oraclepreparedstatement.java:3584) at Oracle.jdbc.driver.OraclePreparedStatement.executeQuery (Oraclepreparedstatement.java:3628) at Oracle.jdbc.driver.OraclePreparedStatementWrapper.executeQuery (Oraclepreparedstatementwrapper.ja

Format of: 1 str.split ([SEQ [, Maxsplit]]) We are most used to! Name, age | Another user name, age Name:haha,age:20|name:python,age:30|name:fef,age:55 Then we can cut the string object into a list by the split method of the string object. A = ' name:haha,age:20|name:python,age:30|name:fef,age:55 ' Print A.split (' | ') return Result: [' name:haha,age:20

Label: Turn from: http://www.2cto.com/database/201209/154045.html Oracle the REGEXP_SUBSTR function Instructions for using the REGEXP_SUBSTR function in Oracle: The topic is as follows: In Oracle, a statement is implemented to split ' 17,20,23 ' into a collection of ' 17 ', ' 20 ', ' 23 '. The REGEXP_SUBSTR functions are formatted as follows: function regexp_substr (String, pattern, position,

Example 1 The code is as follows Create function F_split (@SourceSql varchar (8000), @StrSeprate varchar) returns @temp table (a varchar (100)) --function of the split function --date:2003-10-14 as begin Declare @i int set @SourceSql =rtrim LTrim (@ Sourcesql)) set @i=charindex (@StrSeprate, @SourceSql) while @i>=1 begin Insert @temp VALUES ( Left (@SourceSql, @i-1)) set @SourceSql =substring (@SourceSql, @i+1,len (@SourceSql)-@i) set @i=cha