ssa 1588

1588: [HNOI2002] turnover statistics time limit:5 Sec Memory limit:162 MBsubmit:14396 solved:5521[Submit] [Status] [Discuss] DescriptionTurnover statistics Tiger has recently been promoted to Sales manager, the first task he received after taking office was to count and analyze the company's business since its inception. Tiger took out the company's ledger, which recorded the daily turnover of the company since its inception. Analysis of the

1588: [HNOI2002] turnover statistics time limit:5 Sec Memory limit:162 MBsubmit:12485 solved:4508[Submit] [Status] [Discuss] DescriptionTurnover statistics Tiger has recently been promoted to Sales manager, the first task he received after taking office was to count and analyze the company's business since its inception. Tiger took out the company's ledger, which recorded the daily turnover of the company since its inception. Analysis of the

1588: [HNOI2002] turnover statistics time limit: 5 Sec Memory Limit: 162 MB Submit: 10371 Solved: 3597 [Submit] [Status] [Discuss] DescriptionTurnover statistics Tiger has recently been promoted to Sales manager, the first task he received after taking office was to count and analyze the company's business since its inception. Tiger took out the company's ledger, which recorded the daily turnover of the company since its inc

1588: [HNOI2002] turnover statistics time limit: 5 Sec Memory Limit: 162 MB Submit: 10828 Solved: 3771 [Submit] [Status] [Discuss] DescriptionTurnover statistics Tiger has recently been promoted to Sales manager, the first task he received after taking office was to count and analyze the company's business since its inception. Tiger took out the company's ledger, which recorded the daily turnover of the company since its inc

Bzoj 1588: [HNOI2002] turnover statistics time limit:5 Sec Memory limit:512 MBsubmit:9619 solved:3287 Topic Connectionhttp://www.lydsy.com/JudgeOnline/problem.php?id=1588Description turnover Statistics Tiger was recently promoted to Sales manager, the first task he received after taking office was to count and analyze the company's business since its inception. Tiger took out the company's ledger, which recorded the daily turnover of the co

First, the FIB series can be introduced to the matrix solution at will, and then here is to deal with a problem about the sum of the matrix proportional series. Here is a solution of logn, similar A ^ 0 + A ^ 1 + a ^ 2 + A ^ 3 = a ^ 0 + A ^ 1 + a ^ 2 * (a ^ 0 + A ^ 1) just deal with it. #include 　　 HDU 1588 Gauss Fibonacci Matrix

This problem thinking is not difficult to think, in the process of doing the main problems encountered are:Because there is no careful consideration of the boundary situation, there is no comprehensive analysis, resulting in a large amount of time wasted due to the lack of access to the correct results.In the future to do such topics, we must first carry out a more comprehensive analysis + simulation, and then write code, to avoid wasting time.　　1#include 2#include 3#include 4 using namespacestd

(I) = K * I + B. Find all F (G (I) in the range of N. Train of Thought: Reference: constructor matrix:| 1 1 | F (2) F (1) |A = | 1 0 | = | F (1) f (0) || 1 1 | ^ B | f (B + 1) F (B) |A ^ B = | 1 0 | = | F (B) f (b-1) |F (B) = matrix [0] [1] = matrix [1] [0];The first item is a ^ B.Public ratio: A ^ KNumber of items: NCan further simplify the problemSince the multiplication of the matrix addition also conforms to the allocation Law, we propose a ^ B to form this formula:A ^ B * (I + A ^ K + (a ^

; ++K) {C.num[i][j] = (c.num[i][j]+aa.num[i][k]*bb.num[k][j])%m; } } }returnC;} Node FA (Node A, LL N) {Node b = e; while(n) {if(n1) B = Mul (A, b); N >>=1; A = Mul (A, a); }returnb;} Node Add (node AA, node bb) {node C; for(inti =1; I 3; ++i) { for(intj =1; J 3; ++J) {C.num[i][j] = (aa.num[i][j]+bb.num[i][j])%m; } }returnC;} Node DG (node p, LL k) {//This is a coincidence . if(k = =1)returnPElse if(k1)returnAdd (DG (P, K1), FA (P, k));//This is a^ (K-1) +a^k

) + { the if(V==nod[t].val)return-1; - intq=-1; $ if(V>nod[t].val)//Right the { the if(nod[t].ch[1]==0) q= (nod[t].ch[1]=Create_node (V, t)); the ElseQ=insert (nod[t].ch[1], v); the } - Else //left in { the if(nod[t].ch[0]==0) q= (nod[t].ch[0]=Create_node (V, t)); the ElseQ=insert (nod[t].ch[0], v); About } the returnQ; the } the intGet_pre (intTintD//seeking precursors and successors, d=1 representatives seeking

Hdu_1588 Assume that F is the same matrix containing the Fibonacci items, and the final result is the matrix S (n-1) = f ^ (B) + f ^ (K + B) +... + F ^ (K * (n-1) + B) elements in the upper left corner. For the matrix S and F, the recursive

Thought very well, at the beginning WA's time, see the problem is not part of the flip, want to flip all can AC, flip found also wrong, tried a few sets of data found a special data, processing or wrong, suddenly thought can not flip, so removed the

DescriptionWithout expecting, angel replied quickly. she says: "I 'v heard that you' r a very clever boy. so if you wanna me be your GF, you shoshould solve the problem called GF ~. " How good an opportunity that gardon can not give up! The "problem

The data is incorrect. The reading file is incomplete... so there will be no number to read in the end... it's speechless... It's really amazing... This line segment tree can also be done offline... I started to use treap. the result times out...

Question: Find the sum of K * I + B in Fibonacci. Train of Thought Analysis: Defines the matrix of the Fibonacci series F (n) is the nth entry of Fibonacci F (n) = f (n + 1) F (N) Then we can know the matrix. A = 1 1 1 0 Make F (n) = A * F (n + 1)

Gauss Fibonacci Time Limit: 1000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 2090 accepted submission (s): 903 Problem descriptionwithout expecting, angel replied quickly. she says: "I 'v heard that you' r a

[Cpp]/*** Stratege: constructor A = | 1 1 |* | 1 0 |* Rapid matrix power, binary summation* Status: johnsondu B Accepted 252 KB 15 ms c ++ 3113 B**/  # Include # Include # Include # Include # Include  Using namespace std; Typedef _ int64 LLD; Struct

splay Tree Extension trees The basic operation and application of extensional tree Description Turnover statistics Tiger has recently been promoted to Sales manager, the first task he received after taking office was to count and analyze the

The Doesn't know why it always times out, basically it's a double loop. #include #include char top[101]; Char bottom[101]; int main () {while (scanf ("%s%s", Top, bottom)) {//printf ("%s\n", top); printf ("%s\n", bottom);

Topic links BZOJ1588 Topic Enter n N Number (n≤32767 n\le32767), each read into a number, in the previous input to find a number of the smallest difference. Add up all the difference to get the answer. Analysis I wrote the first splay question,